blocks|key|955759|text|取消换行符并打印\r。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|955760|print+1,
print+'\r2'|code-block|syntax|javascript|955761|或者写到stdout：|955762|sys.stdout.write('1')
sys.stdout.write('\r2')|955763|entityMap^0|8|2|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

<p>Suppress the newline and print <code>\r</code>.</p>

<pre><code>print 1,
print '\r2'
</code></pre>

<p>or write to stdout:</p>

<pre><code>sys.stdout.write('1')
sys.stdout.write('\r2')
</code></pre>


blocks|key|955805|text|简单版本|type|unstyled|depth|inlineStyleRanges|entityRanges|data|955806|一种方法是使用回车符('\r')返回到行首，而不前进到下一行。|offset|length|style|CODE|955807|Python+3|955808|for+x+in+range(10):
++++print(x,+end='\r')
print()|code-block|syntax|javascript|955809|Python+2.7向前兼容|955810|from+__future__+import+print_function
for+x+in+range(10):
++++print(x,+end='\r')
print()|955811|Python+2.7|955812|for+x+in+range(10):
++++print+'{}\r'.format(x),
print|955813|Python+2.0-2.6|955814|for+x+in+range(10):
++++print+'{0}\r'.format(x),
print|955815|在后两种情况(仅适用于Python+2)中，print语句末尾的逗号告诉它不要转到下一行。最后一条print语句前进到下一行，这样提示符就不会覆盖最终输出。|955816|线路清洗|955817|如果您不能保证新文本行不比现有行短，那么您只需要添加一个“清除到行尾”转义序列'\x1b[1K'+('\x1b'+=+ESC)：|955818|for+x+in+range(75):
++++print('*'+*+(75+-+x),+x,+end='\x1b[1K\r')
print()|955819|entityMap^0|0|B|4|0|0|0|0|0|0|0|0|0|0|0|13|9|1E|6|0|0^^$0|@$1|2|3|4|5|6|7|1A|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|1B|8|@$D|1C|E|1D|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|1E|8|@]|9|@]|A|$]]|$1|J|3|K|5|L|7|1F|8|@]|9|@]|A|$M|N]]|$1|O|3|P|5|6|7|1G|8|@]|9|@]|A|$]]|$1|Q|3|R|5|L|7|1H|8|@]|9|@]|A|$M|N]]|$1|S|3|T|5|6|7|1I|8|@]|9|@]|A|$]]|$1|U|3|V|5|L|7|1J|8|@]|9|@]|A|$M|N]]|$1|W|3|X|5|6|7|1K|8|@]|9|@]|A|$]]|$1|Y|3|Z|5|L|7|1L|8|@]|9|@]|A|$M|N]]|$1|10|3|11|5|6|7|1M|8|@]|9|@]|A|$]]|$1|12|3|13|5|6|7|1N|8|@]|9|@]|A|$]]|$1|14|3|15|5|6|7|1O|8|@$D|1P|E|1Q|F|G]|$D|1R|E|1S|F|G]]|9|@]|A|$]]|$1|16|3|17|5|L|7|1T|8|@]|9|@]|A|$M|N]]|$1|18|3|-4|5|6|7|1U|8|@]|9|@]|A|$]]]|19|$]]

<h1>Simple Version</h1>
<p>One way is to use the carriage return (<code>'\r'</code>) character to return to the start of the line without advancing to the next line.</p>
<h3>Python 3</h3>
<pre><code>for x in range(10):
    print(x, end='\r')
print()
</code></pre>
<h3>Python 2.7 forward compatible</h3>
<pre><code>from __future__ import print_function
for x in range(10):
    print(x, end='\r')
print()
</code></pre>
<h3>Python 2.7</h3>
<pre><code>for x in range(10):
    print '{}\r'.format(x),
print
</code></pre>
<h3>Python 2.0-2.6</h3>
<pre><code>for x in range(10):
    print '{0}\r'.format(x),
print
</code></pre>
<p>In the latter two (Python 2-only) cases, the comma at the end of the print statement tells it not to go to the next line. The last print statement advances to the next line so your prompt won't overwrite your final output.</p>
<h1>Line Cleaning</h1>
<p>If you can’t guarantee that the new line of text is not shorter than the existing line, then you just need to add a “clear to end of line” escape sequence, <code>'\x1b[1K'</code> (<code>'\x1b'</code> = ESC):</p>
<pre><code>for x in range(75):
    print('*' * (75 - x), x, end='\x1b[1K\r')
print()
</code></pre>


blocks|key|955887|text|由于我是通过Google来到这里的，但我使用的是Python3，下面是Python3的工作原理：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|955888|for+x+in+range(10):
++++print("Progress+{:2.1%25}".format(x+/+10),+end="\r")|code-block|syntax|javascript|955889|相关答案：How+can+I+suppress+the+newline+after+a+print+statement?|offset|length|955890|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/12102749/in-python-3-how-can-i-suppress-the-newline-after-a-print-statement-with-the-comm^0|0|0|5|1J|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

<p>Since I ended up here via Google but am using Python 3, here's how this would work in Python 3:</p>

<pre><code>for x in range(10):
    print("Progress {:2.1%}".format(x / 10), end="\r")
</code></pre>

<p>Related answer here: <a href="https://stackoverflow.com/questions/12102749/in-python-3-how-can-i-suppress-the-newline-after-a-print-statement-with-the-comm">How can I suppress the newline after a print statement?</a></p>


blocks|key|955947|text|@Mike+DeSimone+answer可能会在大部分时间内工作。但是..。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|955948|for+x+in+['abc',+1]:
++++print+'{}\r'.format(x),

->+1bc|code-block|syntax|javascript|955949|这是因为'\r'只返回到行的开头，而不清除输出。|offset|length|style|CODE|955950|编辑:更好的解决方案(比我下面的旧方案更好)|955951|如果POSIX支持对您来说足够了，下面的命令将清除当前行，并将光标留在其开头：|955952|print+'\x1b[2K\r',|955953|它使用ANSI转义代码来清除终端行。更多信息可以在in+wikipedia和this+great+talk中找到。|955954|老答案|955955|我找到的(不太好的)解决方案是这样的：|955956|last_x+=+''
for+x+in+['abc',+1]:
++++print+'+'+*+len(str(last_x))+%2B+'\r',
++++print+'{}\r'.format(x),
++++last_x+=+x

->+1|955957|它的一个优点是它也可以在windows上工作。|955958|entityMap|0|LINK|mutability|MUTABLE|url|http://en.wikipedia.org/wiki/ANSI_escape_code|1|https://www.youtube.com/watch?v=WAitSilLDUA^0|0|0|4|4|0|0|0|0|P|C|0|12|F|1|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|1C|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|1D|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|1E|8|@$I|1F|J|1G|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|1H|8|@]|9|@]|A|$]]|$1|O|3|P|5|6|7|1I|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|1J|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|1K|8|@]|9|@$I|1L|J|1M|1|1N]|$I|1O|J|1P|1|1Q]]|A|$]]|$1|U|3|V|5|6|7|1R|8|@]|9|@]|A|$]]|$1|W|3|X|5|6|7|1S|8|@]|9|@]|A|$]]|$1|Y|3|Z|5|D|7|1T|8|@]|9|@]|A|$E|F]]|$1|10|3|11|5|6|7|1U|8|@]|9|@]|A|$]]|$1|12|3|-4|5|6|7|1V|8|@]|9|@]|A|$]]]|13|$14|$5|15|16|17|A|$18|19]]|1A|$5|15|16|17|A|$18|1B]]]]

<p>@Mike DeSimone answer will probably work most of the time. But...</p>

<pre><code>for x in ['abc', 1]:
    print '{}\r'.format(x),

-&gt; 1bc
</code></pre>

<p>This is because the <code>'\r'</code> only goes back to the beginning of the line but doesn't clear the output.</p>

<h2>EDIT: Better solution (than my old proposal below)</h2>

<p>If POSIX support is enough for you, the following would clear the current line and leave the cursor at its beginning:</p>

<pre><code>print '\x1b[2K\r',
</code></pre>

<p>It uses ANSI escape code to clear the terminal line. More info can be found <a href="http://en.wikipedia.org/wiki/ANSI_escape_code" rel="noreferrer">in wikipedia</a> and in <a href="https://www.youtube.com/watch?v=WAitSilLDUA" rel="noreferrer">this great talk</a>.</p>

<h2>Old answer</h2>

<p>The (not so good) solution I've found looks like this:</p>

<pre><code>last_x = ''
for x in ['abc', 1]:
    print ' ' * len(str(last_x)) + '\r',
    print '{}\r'.format(x),
    last_x = x

-&gt; 1
</code></pre>

<p>One advantage is that it will work on windows too.</p>


blocks|key|956027|text|在访问这个帖子之前，我也有同样的问题。对于我来说，只有当我正确地刷新缓冲区时，sys.stdout.write才能工作。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|956028|for+x+in+range(10):
++++sys.stdout.write('\r'%2Bstr(x))
++++sys.stdout.flush()|code-block|syntax|javascript|956029|如果不刷新，则只在脚本末尾打印结果|956030|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

<p>I had the same question before visiting this thread. For me the sys.stdout.write worked only if I properly flush the buffer i.e.</p>

<pre><code>for x in range(10):
    sys.stdout.write('\r'+str(x))
    sys.stdout.flush()
</code></pre>

<p>Without flushing, the result is printed only at the end out the script</p>


blocks|key|956087|text|for+x+in+range(10):
++++time.sleep(0.5)+#+shows+how+its+working
++++print("\r+{}".format(x),+end="")|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|956088|time.sleep(0.5)用于显示如何擦除先前的输出以及如何打印新输出"\r“当它位于打印消息的开头时，它将在新输出之前擦除先前的输出。|unstyled|956089|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>for x in range(10):
    time.sleep(0.5) # shows how its working
    print("\r {}".format(x), end="")
</code></pre>

<p>time.sleep(0.5) is to show how previous output is erased and new output is printed 
"\r" when its at the start of print message , it gonna erase previous output before  new output.</p>


blocks|key|956128|text|这是@Nagaki45答案的一个更简洁、更“即插即用”的版本。与这里的许多其他答案不同的是，它可以正确处理不同长度的字符串。它通过使用与打印的最后一行的长度一样多的空格清除行来实现这一点。也可以在Windows上运行。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|956129|def+print_statusline(msg:+str):
++++last_msg_length+=+len(print_statusline.last_msg)+if+hasattr(print_statusline,+'last_msg')+else+0
++++print('+'+*+last_msg_length,+end='\r')
++++print(msg,+end='\r')
++++sys.stdout.flush()++#+Some+say+they+needed+this,+I+didn't.
++++print_statusline.last_msg+=+msg|code-block|syntax|javascript|956130|用法|956131|只需像这样使用它：|956132|for+msg+in+["Initializing...",+"Initialization+successful!"]:
++++print_statusline(msg)
++++time.sleep(1)|956133|这个小测试表明，即使对于不同的长度，也可以正确清除行：|956134|for+i+in+range(9,+0,+-1):
++++print_statusline("{}".format(i)+*+i)
++++time.sleep(0.5)|956135|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|V|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|W|8|@]|9|@]|A|$E|F]]|$1|M|3|N|5|6|7|X|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|Y|8|@]|9|@]|A|$E|F]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

<p>Here's a cleaner, more "plug-and-play", version of @Nagasaki45's answer. Unlike many other answers here, it works properly with strings of different lengths. It achieves this by clearing the line with just as many spaces as the length of the last line printed print. Will also work on Windows.</p>

<pre class="lang-python prettyprint-override"><code>def print_statusline(msg: str):
    last_msg_length = len(print_statusline.last_msg) if hasattr(print_statusline, 'last_msg') else 0
    print(' ' * last_msg_length, end='\r')
    print(msg, end='\r')
    sys.stdout.flush()  # Some say they needed this, I didn't.
    print_statusline.last_msg = msg
</code></pre>

<h2>Usage</h2>

<p>Simply use it like this:</p>

<pre class="lang-python prettyprint-override"><code>for msg in ["Initializing...", "Initialization successful!"]:
    print_statusline(msg)
    time.sleep(1)
</code></pre>

<p>This small test shows that lines get cleared properly, even for different lengths:</p>

<pre class="lang-python prettyprint-override"><code>for i in range(9, 0, -1):
    print_statusline("{}".format(i) * i)
    time.sleep(0.5)
</code></pre>


blocks|key|956187|text|我有点惊讶没有人使用退格符。这里就有一个使用它的例子。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|956188|import+sys
import+time

secs+=+1000

while+True:
++++time.sleep(1)++#wait+for+a+full+second+to+pass+before+assigning+a+second
++++secs+%2B=+1++#acknowledge+a+second+has+passed

++++sys.stdout.write(str(secs))

++++for+i+in+range(len(str(secs))):
++++++++sys.stdout.write('\b')|code-block|syntax|javascript|956189|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>I'm a bit surprised nobody is using the backspace character. Here's one that uses it.</p>

<pre><code>import sys
import time

secs = 1000

while True:
    time.sleep(1)  #wait for a full second to pass before assigning a second
    secs += 1  #acknowledge a second has passed

    sys.stdout.write(str(secs))

    for i in range(len(str(secs))):
        sys.stdout.write('\b')
</code></pre>


blocks|key|956208|text|这适用于Windows和python+3.6|type|unstyled|depth|inlineStyleRanges|entityRanges|data|956209|import+time
for+x+in+range(10):
++++time.sleep(0.5)
++++print(str(x)%2B'\r',end='')|code-block|syntax|javascript|956210|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>This works on Windows and python 3.6</p>

<pre><code>import time
for x in range(10):
    time.sleep(0.5)
    print(str(x)+'\r',end='')
</code></pre>


blocks|key|956276|text|这是我的解决方案！Windows+10，Python+3.7.1|type|unstyled|depth|inlineStyleRanges|entityRanges|data|956277|我不确定为什么这段代码可以工作，但它完全删除了原始行。我从前面的答案中编译出来的。其他答案只是将行返回到开头，但是如果后面有更短的行，它看起来会像hello变成byelo一样混乱。|offset|length|style|CODE|956278|import+sys
#include+ctypes+if+you're+on+Windows
import+ctypes
kernel32+=+ctypes.windll.kernel32
kernel32.SetConsoleMode(kernel32.GetStdHandle(-11),+7)
#end+ctypes

def+clearline(msg):
++++CURSOR_UP_ONE+=+'\033[K'
++++ERASE_LINE+=+'\x1b[2K'
++++sys.stdout.write(CURSOR_UP_ONE)
++++sys.stdout.write(ERASE_LINE%2B'\r')
++++print(msg,+end='\r')

#example
ig_usernames+=+['beyonce','selenagomez']
for+name+in+ig_usernames:
++++clearline("SCRAPING+COMPLETE:+"%2B+name)|code-block|syntax|javascript|956279|输出-每一行都将被重写，而不显示任何旧文本：|956280|SCRAPING+COMPLETE:+selenagomez|956281|下一行(完全重写在同一行)：|956282|SCRAPING+COMPLETE:+beyonce|956283|entityMap^0|0|21|5|28|5|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@$D|Y|E|Z|F|G]|$D|10|E|11|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|12|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|13|8|@]|9|@]|A|$]]|$1|O|3|P|5|J|7|14|8|@]|9|@]|A|$K|L]]|$1|Q|3|R|5|6|7|15|8|@]|9|@]|A|$]]|$1|S|3|T|5|J|7|16|8|@]|9|@]|A|$K|L]]|$1|U|3|-4|5|6|7|17|8|@]|9|@]|A|$]]]|V|$]]

<p>Here's my solution! Windows 10, Python 3.7.1</p>

<p>I'm not sure why this code works, but it completely erases the original line. I compiled it from the previous answers. The other answers would just return the line to the beginning, but if you had a shorter line afterwards, it would look messed up like <code>hello</code> turns into <code>byelo</code>.</p>

<pre><code>import sys
#include ctypes if you're on Windows
import ctypes
kernel32 = ctypes.windll.kernel32
kernel32.SetConsoleMode(kernel32.GetStdHandle(-11), 7)
#end ctypes

def clearline(msg):
    CURSOR_UP_ONE = '\033[K'
    ERASE_LINE = '\x1b[2K'
    sys.stdout.write(CURSOR_UP_ONE)
    sys.stdout.write(ERASE_LINE+'\r')
    print(msg, end='\r')

#example
ig_usernames = ['beyonce','selenagomez']
for name in ig_usernames:
    clearline("SCRAPING COMPLETE: "+ name)
</code></pre>

<p>Output - Each line will be rewritten without any old text showing:</p>

<pre><code>SCRAPING COMPLETE: selenagomez
</code></pre>

<p>Next line (rewritten completely on same line):</p>

<pre><code>SCRAPING COMPLETE: beyonce
</code></pre>


blocks|key|956328|text|(Python3)这就是对我有效的方法。如果您只使用\010，那么它将留下字符，所以我对它进行了一些调整，以确保它覆盖了那里的内容。这也允许您在第一个打印项目之前有一些东西，并且只删除项目的长度。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|956329|print("Here+are+some+strings:+",+end="")
items+=+["abcd",+"abcdef",+"defqrs",+"lmnop",+"xyz"]
for+item+in+items:
++++print(item,+end="")
++++for+i+in+range(len(item)):+#+only+moving+back+the+length+of+the+item
++++++++print("\010+\010",+end="")+#+the+trick!
++++++++time.sleep(0.2)+#+so+you+can+see+what+it's+doing|code-block|syntax|javascript|956330|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>(Python3) This is what worked for me. If you just use the \010 then it will leave characters, so I tweaked it a bit to make sure it's overwriting what was there. This also allows you to have something before the first print item and only removed the length of the item.</p>

<pre><code>print("Here are some strings: ", end="")
items = ["abcd", "abcdef", "defqrs", "lmnop", "xyz"]
for item in items:
    print(item, end="")
    for i in range(len(item)): # only moving back the length of the item
        print("\010 \010", end="") # the trick!
        time.sleep(0.2) # so you can see what it's doing
</code></pre>


blocks|key|740410|text|根据前面的答案再给出一个答案。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|740411|Pbar.py的内容:+import+sys，shutil，datetime|740412|last_line_is_progress_bar=False


def+print2(print_string):
++++global+last_line_is_progress_bar
++++if+last_line_is_progress_bar:
++++++++_delete_last_line()
++++++++last_line_is_progress_bar=False
++++print(print_string)


def+_delete_last_line():
++++sys.stdout.write('\b\b\r')
++++sys.stdout.write('+'*shutil.get_terminal_size((80,+20)).columns)
++++sys.stdout.write('\b\r')
++++sys.stdout.flush()


def+update_progress_bar(current,+total):
++++global+last_line_is_progress_bar
++++last_line_is_progress_bar=True

++++completed_percentage+=+round(current+/+(total+/+100))
++++current_time=datetime.datetime.now().strftime('%25m/%25d/%25Y-%25H:%25M:%25S')
++++overhead_length+=+len(current_time%2Bstr(current))%2B13
++++console_width+=+shutil.get_terminal_size((80,+20)).columns+-+overhead_length
++++completed_width+=+round(console_width+*+completed_percentage+/+100)
++++not_completed_width+=+console_width+-+completed_width
++++sys.stdout.write('\b\b\r')

++++sys.stdout.write('{}>+[{}{}]+{}+-+{}%25+'.format(current_time,+'#'*completed_width,+'-'*not_completed_width,+current,
++++++++++++++++++++++++++++++++++++++++completed_percentage),)
++++sys.stdout.flush()|code-block|syntax|javascript|740413|脚本的用法：|740414|import+time
from+pbar+import+update_progress_bar,+print2


update_progress_bar(45,200)
time.sleep(1)

update_progress_bar(70,200)
time.sleep(1)

update_progress_bar(100,200)
time.sleep(1)


update_progress_bar(130,200)
time.sleep(1)

print2('some+text+that+will+re-place+current+progress+bar')
time.sleep(1)

update_progress_bar(111,200)
time.sleep(1)

print('\n')+#+without+\n+next+line+will+be+attached+to+the+end+of+the+progress+bar
print('built+in+print+function+that+will+push+progress+bar+one+line+up')
time.sleep(1)

update_progress_bar(111,200)
time.sleep(1)|740415|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

<p>One more answer based on the prevous answers.</p>

<p>Content of pbar.py:
    import sys, shutil, datetime</p>

<pre><code>last_line_is_progress_bar=False


def print2(print_string):
    global last_line_is_progress_bar
    if last_line_is_progress_bar:
        _delete_last_line()
        last_line_is_progress_bar=False
    print(print_string)


def _delete_last_line():
    sys.stdout.write('\b\b\r')
    sys.stdout.write(' '*shutil.get_terminal_size((80, 20)).columns)
    sys.stdout.write('\b\r')
    sys.stdout.flush()


def update_progress_bar(current, total):
    global last_line_is_progress_bar
    last_line_is_progress_bar=True

    completed_percentage = round(current / (total / 100))
    current_time=datetime.datetime.now().strftime('%m/%d/%Y-%H:%M:%S')
    overhead_length = len(current_time+str(current))+13
    console_width = shutil.get_terminal_size((80, 20)).columns - overhead_length
    completed_width = round(console_width * completed_percentage / 100)
    not_completed_width = console_width - completed_width
    sys.stdout.write('\b\b\r')

    sys.stdout.write('{}&gt; [{}{}] {} - {}% '.format(current_time, '#'*completed_width, '-'*not_completed_width, current,
                                        completed_percentage),)
    sys.stdout.flush()
</code></pre>

<p>Usage of script:</p>

<pre><code>import time
from pbar import update_progress_bar, print2


update_progress_bar(45,200)
time.sleep(1)

update_progress_bar(70,200)
time.sleep(1)

update_progress_bar(100,200)
time.sleep(1)


update_progress_bar(130,200)
time.sleep(1)

print2('some text that will re-place current progress bar')
time.sleep(1)

update_progress_bar(111,200)
time.sleep(1)

print('\n') # without \n next line will be attached to the end of the progress bar
print('built in print function that will push progress bar one line up')
time.sleep(1)

update_progress_bar(111,200)
time.sleep(1)
</code></pre>


blocks|key|740447|text|最好覆盖整个行，否则如果新行更短，新行将与旧行混合。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|740448|import+time,+os
for+s+in+['overwrite!',+'the!',+'whole!',+'line!']:
++++print(s.ljust(os.get_terminal_size().columns+-+1),+end="\r")
++++time.sleep(1)|code-block|syntax|javascript|740449|我不得不在Windows上使用columns+-+1。|offset|length|style|CODE|740450|entityMap^0|0|0|F|B|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

<p>Better to overwrite the whole line otherwise the new line will mix with the old ones if the new line is shorter.</p>
<pre><code>import time, os
for s in ['overwrite!', 'the!', 'whole!', 'line!']:
    print(s.ljust(os.get_terminal_size().columns - 1), end=&quot;\r&quot;)
    time.sleep(1)
</code></pre>
<p>Had to use <code>columns - 1</code> on Windows.</p>


blocks|key|956460|text|这对我来说很有效，在Windows中使用Spyder中的Python+3.7.9：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|956461|from+IPython.display+import+clear_output
from+time+import+sleep

def+print_and_overwrite(text):
++++'''Remember+to+add+print()+after+the+last+print+that+you+want+to+overwrite.'''
++++clear_output(wait=True)
++++print(text,+end='\r')

for+i+in+range(15):
++++#I+print+the+results+backwards+(from+15+to+1),+to+test+shorter+strings
++++message+=+"Iteration+%25d+out+of+15"+%25(15-i)
++++print_and_overwrite(message)
++++sleep(0.5)

print()+#This+stops+the+overwriting
print("This+will+be+on+a+new+line")|code-block|syntax|javascript|956462|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>This worked for me, using Python 3.7.9 within Spyder, in Windows:</p>
<pre class="lang-py prettyprint-override"><code>from IPython.display import clear_output
from time import sleep

def print_and_overwrite(text):
    '''Remember to add print() after the last print that you want to overwrite.'''
    clear_output(wait=True)
    print(text, end='\r')

for i in range(15):
    #I print the results backwards (from 15 to 1), to test shorter strings
    message = &quot;Iteration %d out of 15&quot; %(15-i)
    print_and_overwrite(message)
    sleep(0.5)

print() #This stops the overwriting
print(&quot;This will be on a new line&quot;)
</code></pre>


<p>If I had the following code:</p>

<pre><code>for x in range(10):
     print x
</code></pre>

<p>I would get the output of</p>

<pre><code>1
2
etc..
</code></pre>

<p>What I would like to do is instead of printing a newline, I want to replace the previous value and overwrite it with the new value on the same line.</p>


How to overwrite the previous print to stdout in python?

Windows

Python

如果我有以下代码：for x in range(10):     print x我会得到下面的输出12etc..我想要做的不是打印换行符，而是替换以前的值，并用同一行上的新值覆盖它。

问如何在python中覆盖之前的打印到stdout？
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