如何在django中对文件上传进行单元测试
如何在django中对文件上传进行单元测试
提问于 2012-06-23 22:49:08
在我的django应用程序中，我有一个完成文件upload.The核心片段的视图，如下所示
...
if (request.method == 'POST'):
if request.FILES.has_key('file'):
file = request.FILES['file']
with open(settings.destfolder+'/%s' % file.name, 'wb+') as dest:
for chunk in file.chunks():
dest.write(chunk)我想对视图进行单元测试。我计划测试快乐路径和失败文件，在request.FILES没有密钥‘path..ie’的情况下，在request.FILES['file']有None的情况下。
如何设置快乐路径的帖子数据?谁能告诉我？
回答 10
Stack Overflow用户
发布于 2012-06-24 00:50:28
我为我自己的事件相关应用程序做了类似的事情，但是您应该有足够的代码来继续您自己的用例
import tempfile, csv, os
class UploadPaperTest(TestCase):
def generate_file(self):
try:
myfile = open('test.csv', 'wb')
wr = csv.writer(myfile)
wr.writerow(('Paper ID','Paper Title', 'Authors'))
wr.writerow(('1','Title1', 'Author1'))
wr.writerow(('2','Title2', 'Author2'))
wr.writerow(('3','Title3', 'Author3'))
finally:
myfile.close()
return myfile
def setUp(self):
self.user = create_fuser()
self.profile = ProfileFactory(user=self.user)
self.event = EventFactory()
self.client = Client()
self.module = ModuleFactory()
self.event_module = EventModule.objects.get_or_create(event=self.event,
module=self.module)[0]
add_to_admin(self.event, self.user)
def test_paper_upload(self):
response = self.client.login(username=self.user.email, password='foz')
self.assertTrue(response)
myfile = self.generate_file()
file_path = myfile.name
f = open(file_path, "r")
url = reverse('registration_upload_papers', args=[self.event.slug])
# post wrong data type
post_data = {'uploaded_file': i}
response = self.client.post(url, post_data)
self.assertContains(response, 'File type is not supported.')
post_data['uploaded_file'] = f
response = self.client.post(url, post_data)
import_file = SubmissionImportFile.objects.all()[0]
self.assertEqual(SubmissionImportFile.objects.all().count(), 1)
#self.assertEqual(import_file.uploaded_file.name, 'files/registration/{0}'.format(file_path))
os.remove(myfile.name)
file_path = import_file.uploaded_file.path
os.remove(file_path)Stack Overflow用户
发布于 2018-02-02 16:46:47
我做了这样的事情：
from django.core.files.uploadedfile import SimpleUploadedFile
from django.test import TestCase
from django.core.urlresolvers import reverse
from django.core.files import File
from django.utils.six import BytesIO
from .forms import UploadImageForm
from PIL import Image
from io import StringIO
def create_image(storage, filename, size=(100, 100), image_mode='RGB', image_format='PNG'):
"""
Generate a test image, returning the filename that it was saved as.
If ``storage`` is ``None``, the BytesIO containing the image data
will be passed instead.
"""
data = BytesIO()
Image.new(image_mode, size).save(data, image_format)
data.seek(0)
if not storage:
return data
image_file = ContentFile(data.read())
return storage.save(filename, image_file)
class UploadImageTests(TestCase):
def setUp(self):
super(UploadImageTests, self).setUp()
def test_valid_form(self):
'''
valid post data should redirect
The expected behavior is to show the image
'''
url = reverse('image')
avatar = create_image(None, 'avatar.png')
avatar_file = SimpleUploadedFile('front.png', avatar.getvalue())
data = {'image': avatar_file}
response = self.client.post(url, data, follow=True)
image_src = response.context.get('image_src')
self.assertEquals(response.status_code, 200)
self.assertTrue(image_src)
self.assertTemplateUsed('content_upload/result_image.html')create_image函数会创建图片，所以你不需要给出图片的静态路径。
注:您可以根据自己的代码更新代码。这是Python 3.6的代码。
Stack Overflow用户
发布于 2020-11-11 20:10:31
如果您想在上传文件时添加其他数据，请遵循以下方法
file = open('path/to/file.txt', 'r', encoding='utf-8')
data = {
'file_name_to_receive_on_backend': file,
'param1': 1,
'param2': 2,
.
.
}
response = self.client.post("/url/to/view", data, format='multipart')`唯一的file_name_to_receive_on_backend将作为文件接收，其他参数通常作为post参数接收。
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原文链接：
https://stackoverflow.com/questions/11170425
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