我是(有点) Python的初学者。在我的Tic Tac Toe游戏中,我被困在赢家(棋盘)函数上,因为每当我运行程序并将X放在任何地方时,它都会立即显示"Y O U W O N !“当我删除make_computer_move(主板)下的代码来尝试和调试我的winner (主板)函数时,从右上角到左下角的对角线不起作用,但从左上角到右下角的获胜者确定代码可以工作。下面是我的代码:
"""
Author: Victor Xu
Date: Jan 12, 2021
Description: An implementation of the game Tic-Tac-Toe in Python,
using a nested list, and everything else we've learned this quadmester!
"""
import random
def winner(board):
"""This function accepts the Tic-Tac-Toe board as a parameter.
If there is no winner, the function will return the empty string "".
If the user has won, it will return 'X', and if the computer has
won it will return 'O'."""
# Check rows for winner
for row in range(3):
if (board[row][0] == board[row][1] == board[row][2]) and \
(board[row][0] != " "):
return board[row][0]
# COMPLETE THE REST OF THE FUNCTION CODE BELOW
for col in range(3):
if (board[0][col] == board[1][col] == board[2][col]) and \
(board[0][col] != " "):
return board[0][col]
# Check diagonal (top-left to bottom-right) for winner
if (board[0][0] == board[1][1] == board[2][2]) and \
(board[0][0] != " "):
return board[0][0]
# Check diagonal (bottom-left to top-right) for winner
if (board[0][2] == board[1][1] == board[2][0]) and \
(board[0][0] != " "):
return board[0][0]
# No winner: return the empty string
return ""
def display_board(board):
"""This function accepts the Tic-Tac-Toe board as a parameter.
It will print the Tic-Tac-Toe board grid (using ASCII characters)
and show the positions of any X's and O's. It also displays
the column and row numbers on top and beside the board to help
the user figure out the coordinates of their next move.
This function does not return anything."""
print(" 0 1 2")
print("0: " + board[0][0] + " | " + board[0][1] + " | " + board[0][2])
print(" ---+---+---")
print("1: " + board[1][0] + " | " + board[1][1] + " | " + board[1][2])
print(" ---+---+---")
print("2: " + board[2][0] + " | " + board[2][1] + " | " + board[2][2])
print()
def make_user_move(board):
"""This function accepts the Tic-Tac-Toe board as a parameter.
It will ask the user for a row and column. If the row and
column are each within the range of 0 and 2, and that square
is not already occupied, then it will place an 'X' in that square."""
valid_move = False
while not valid_move:
row = int(input("What row would you like to move to (0-2):"))
col = int(input("What col would you like to move to (0-2):"))
if (0 <= row <= 2) and (0 <= col <= 2) and (board[row][col] == " "):
board[row][col] = 'X'
valid_move = True
else:
print("Sorry, invalid square. Please try again!\n")
def make_computer_move(board):
"""This function accepts the Tic-Tac-Toe board as a parameter.
It will randomly pick row and column values between 0 and 2.
If that square is not already occupied it will place an 'O'
in that square. Otherwise, another random row and column
will be generated."""
computer_valid_move = False
while not computer_valid_move:
row = random.randint(0, 2)
col = random.randing(0, 2)
if (0 <= row <= 2) and (0 <= col <= 2) and (board[row][col] == " "):
board[row][col] = 'O'
computer_valid_move = True
def main():
"""Our Main Game Loop:"""
free_cells = 9
users_turn = True
ttt_board = [[" ", " ", " "], [" ", " ", " "], [" ", " ", " "]]
while not winner(ttt_board) and (free_cells > 0):
display_board(ttt_board)
if users_turn:
make_user_move(ttt_board)
users_turn = not users_turn
else:
make_computer_move(ttt_board)
users_turn = not users_turn
free_cells -= 1
display_board(ttt_board)
if (winner(ttt_board) == 'X'):
print("Y O U W O N !")
elif (winner(ttt_board) == 'O'):
print("I W O N !")
else:
print("S T A L E M A T E !")
print("\n*** GAME OVER ***\n")
# Start the game!
main()
TL;DR
请检查从右上角到左下角的win判定代码和问题,每当我按下一个X,它就会说“您赢了!”
发布于 2021-01-21 03:04:23
首先:我看到你有一个打字错误("randing",我猜它是不是又像前一行一样随机输入了?)第二:代码在这里运行得很好,直到我把我的第一个X放在所有东西都崩溃的地方(由于排名错误,AttributeError:‘模块’对象没有' randing‘属性)第三:在为你改变打字错误后,我完成了游戏,并战胜了机器(幸运的是,直到你/某人(嘿,我可能有一次)在游戏中实现了AI )。
祝Python好运,它是一种非常有趣的语言,但在出现问题时很难做到。
问候
https://stackoverflow.com/questions/65815805
复制相似问题