问RxJava -可观察对象的压缩列表，如果抛出异常，如何获取成功响应

EN

private fun getStoreCouponData() {

    val userObservable = repo2
        .create<StoreCouponsApi>(StoreCouponsApi::class.java!!)
        .getCoupons
        .subscribeOn(Schedulers.newThread())
        .observeOn(AndroidSchedulers.mainThread())

    val eventsObservable = repo2
        .create<StoreCouponsApi>(StoreCouponsApi::class.java!!)
        .storeInfo
        .subscribeOn(Schedulers.newThread())
        .observeOn(AndroidSchedulers.mainThread())

    val combined = Observable.zip<StoreCoupons, StoreCoupons, StoreList>(userObservable, eventsObservable,
        BiFunction<StoreCoupons, StoreCoupons, StoreList> { response1, response2 -> StoreList(response1, response2) })

    combined.subscribe(object : DefaultObserver<StoreList>() {
        override fun onNext(s: StoreList) {
            for (item in s.store!!.coupons!!) {
                System.out.println(item.store)
            }
        }


        override fun onError(e: Throwable) {
           System.out.println(e)
        }

        override fun onComplete() {

        }
    })

    println(combined)

}