我已经编写了MarshalJSON
和UnmarshalJSON
的自定义版本。我的UnmarshalJSON
可以按照我想要的方式调用,但我不能让它与MarshalJSON
一起工作。下面是总结我的问题的代码:
package main
import (
"bytes"
"encoding/json"
"fmt"
"log"
"os"
)
type myStruct struct {
Data string `json:"data"`
}
func (s *myStruct) MarshalJSON() ([]byte, error) {
return []byte(`{"data":"charlie"}`), nil
}
func (s *myStruct) UnmarshalJSON(b []byte) error {
// Insert the string directly into the Data member
return json.Unmarshal(b, &s.Data)
}
func main() {
// Create a struct with initial content "alpha"
ms := myStruct{"alpha"}
// Replace content with "bravo" using custom UnmarshalJSON() (SUCCESSFUL)
if err := json.NewDecoder(bytes.NewBufferString(`"bravo"`)).Decode(&ms); err != nil {
log.Fatal(err)
}
// Use custom MarshalJSON() to get "charlie" back (UNSUCCESSFUL)
if err := json.NewEncoder(os.Stdout).Encode(ms); err != nil {
log.Fatal(err)
}
// Trying another method (UNSUCCESSFUL)
if ret, err := json.Marshal(ms); err != nil {
log.Fatal(err)
} else {
fmt.Println(string(ret))
}
// Verify that the Marshaler interface is correctly implemented
var marsh json.Marshaler
marsh = &ms
ret, _ := marsh.MarshalJSON()
fmt.Println(string(ret)) // Prints "charlie"
}
简而言之,程序以两种方式“自动”编码struct
,然后最终手动调用MarshalJSON
。我想要的响应是"charlie"
。运行代码将生成以下输出:
{"data":"bravo"}
{"data":"bravo"}
{"data":"charlie"}
在Go Playground:http://play.golang.org/p/SJ05S8rAYN上试试吧
https://stackoverflow.com/questions/21390979
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