blocks|key|787707|text|+String+s1="[a,b,c,d]";
+String+replace+=+s1.replace("[","");
+System.out.println(replace);
+String+replace1+=+replace.replace("]","");
+System.out.println(replace1);
+List<String>+myList+=+new+ArrayList<String>(Arrays.asList(replace1.split(",")));
+System.out.println(myList.toString());|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|787708|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code> String s1="[a,b,c,d]";
 String replace = s1.replace("[","");
 System.out.println(replace);
 String replace1 = replace.replace("]","");
 System.out.println(replace1);
 List&lt;String&gt; myList = new ArrayList&lt;String&gt;(Arrays.asList(replace1.split(",")));
 System.out.println(myList.toString());
</code></pre>

blocks|key|787858|text|更容易理解的是这样的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|787859|String+s+=+"a,b,c,d,e";
String[]+sArr+=+s.split(",");
List<String>+sList+=+Arrays.asList(sArr);|code-block|syntax|javascript|787860|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Easier to understand is like this:

<pre><code>String s = "a,b,c,d,e";
String[] sArr = s.split(",");
List&lt;String&gt; sList = Arrays.asList(sArr);
</code></pre>

blocks|key|787760|text|如果您正在导入，或者您的代码中有一个数组(string类型)，并且您必须将其转换为arraylist+(当然字符串)，那么使用集合会更好。如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|787761|String+array1[]+=+getIntent().getExtras().getStringArray("key1");+or+String+array1[]+=+...+then

List+allEds+=+new+ArrayList();+Collections.addAll(allEds,+array1);|code-block|syntax|javascript|787762|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you are importing or you have an array (of type string) in your code and you have to convert it into arraylist (offcourse string) then use of collections is better. like this:

<pre><code>String array1[] = getIntent().getExtras().getStringArray("key1"); or String array1[] = ... then

List allEds = new ArrayList(); Collections.addAll(allEds, array1);
</code></pre>

blocks|key|787813|text|您可以使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|787814|List<String>+tokens+=+Arrays.stream(s.split("\\s%2B")).collect(Collectors.toList());|code-block|syntax|javascript|787815|首先，您应该问问自己是否真的需要ArrayList。通常，您将根据额外的条件过滤列表，而Stream是最好的选择。您可能需要一个集合；您可能希望通过另一个正则表达式等方式过滤它们。顺便说一句，Java8提供了这个非常有用的扩展，它可以在任何CharSequence：https://docs.oracle.com/javase/8/docs/api/java/util/regex/Pattern.html#splitAsStream-java.lang.CharSequence-上工作。由于根本不需要该数组，因此应避免创建它，如下所示：|offset|length|style|CODE|787816|//+This+will+presumably+be+a+static+final+field+somewhere.
Pattern+splitter+=+Pattern.compile("\\s%2B");
//+...
String+untokenized+=+reader.readLine();
Stream<String>+tokens+=+splitter.splitAsStream(untokenized);|787817|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.oracle.com/javase/8/docs/api/java/util/regex/Pattern.html#splitAsStream-java.lang.CharSequence-^0|0|0|3C|C|3P|30|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@$I|Z|J|10|K|L]]|9|@$I|11|J|12|1|13]]|A|$]]|$1|M|3|N|5|D|7|14|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

You could use: 

<pre><code>List&lt;String&gt; tokens = Arrays.stream(s.split("\\s+")).collect(Collectors.toList());
</code></pre>

You should ask yourself if you really need the ArrayList in the first place. Very often, you're going to filter the list based on additional criteria, for which a Stream is perfect. You may want a set; you may want to filter them by means of another regular expression, etc. Java 8 provides this very useful extension, by the way, which will work on any <code>CharSequence</code>: <a href="https://docs.oracle.com/javase/8/docs/api/java/util/regex/Pattern.html#splitAsStream-java.lang.CharSequence-" rel="nofollow noreferrer">https://docs.oracle.com/javase/8/docs/api/java/util/regex/Pattern.html#splitAsStream-java.lang.CharSequence-</a>. Since you don't need the array at all, avoid creating it thus: 

<pre><code>// This will presumably be a static final field somewhere.
Pattern splitter = Pattern.compile("\\s+");
// ...
String untokenized = reader.readLine();
Stream&lt;String&gt; tokens = splitter.splitAsStream(untokenized);
</code></pre>

blocks|key|571817|text|这是在Kotlin中使用Gson|type|unstyled|depth|inlineStyleRanges|entityRanges|data|571818|+val+listString+=+"[uno,dos,tres,cuatro,cinco]"
+val+gson+=+Gson()
+val+lista+=+gson.fromJson(listString+,+Array<String>::class.java).toList()
+Log.e("GSON",+lista[0])|code-block|syntax|javascript|571819|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This is using Gson in Kotlin 

<pre><code> val listString = "[uno,dos,tres,cuatro,cinco]"
 val gson = Gson()
 val lista = gson.fromJson(listString , Array&lt;String&gt;::class.java).toList()
 Log.e("GSON", lista[0])
</code></pre>

blocks|key|571770|text|让我们来看一个问题:颠倒一个字符串。我将使用stream().collect()来完成此操作。但首先，我要将字符串更改为ArrayList。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|571771|++++public+class+StringReverse1+{
++++public+static+void+main(String[]+args)+{

++++++++String+a+=+"Gini+Gina++Proti";

++++++++List<String>+list+=+new+ArrayList<String>(Arrays.asList(a.split("")));

++++++++list.stream()
++++++++.collect(Collectors.toCollection(+LinkedList+::+new+))
++++++++.descendingIterator()
++++++++.forEachRemaining(System.out::println);



++++}}
/*
The+output+:
i
t
o
r
P


a
n
i
G

i
n
i
G
*/|code-block|syntax|javascript|571772|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Let's take a question : Reverse a String. I shall do this using stream().collect(). But first I shall change the string into an ArrayList .

<pre><code> public class StringReverse1 {
 public static void main(String[] args) {

 String a = "Gini Gina Proti";

 List&lt;String&gt; list = new ArrayList&lt;String&gt;(Arrays.asList(a.split("")));

 list.stream()
 .collect(Collectors.toCollection( LinkedList :: new ))
 .descendingIterator()
 .forEachRemaining(System.out::println);



 }}
/*
The output :
i
t
o
r
P


a
n
i
G

i
n
i
G
*/
</code></pre>

blocks|key|787873|text|我推荐使用StringTokenizer，非常高效|type|unstyled|depth|inlineStyleRanges|entityRanges|data|787874|+++++List<String>+list+=+new+ArrayList<>();

+++++StringTokenizer+token+=+new+StringTokenizer(value,+LIST_SEPARATOR);
+++++while+(token.hasMoreTokens())+{
+++++++++++list.add(token.nextToken());
+++++}|code-block|syntax|javascript|787875|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I recommend use the StringTokenizer, is very efficient 

<pre><code> List&lt;String&gt; list = new ArrayList&lt;&gt;();

 StringTokenizer token = new StringTokenizer(value, LIST_SEPARATOR);
 while (token.hasMoreTokens()) {
 list.add(token.nextToken());
 }
</code></pre>

blocks|key|787920|text|如果您正在使用芭乐(您应该使用，请参阅effective+java+item+#15)：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|787921|ImmutableList<String>+list+=+ImmutableList.copyOf(s.split(","));|code-block|syntax|javascript|787922|entityMap|0|LINK|mutability|MUTABLE|url|https://www.google.com/search?q=effective%2520java%2520immutable^0|J|N|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

If you're using guava (and you should be, see <a href="https://www.google.com/search?q=effective%20java%20immutable" rel="nofollow noreferrer">effective java item #15</a>):

<pre><code>ImmutableList&lt;String&gt; list = ImmutableList.copyOf(s.split(","));
</code></pre>

In my String, I can have an arbitrary number of words which are comma separated. I wanted each word added into an ArrayList. E.g.:

<pre><code>String s = "a,b,c,d,e,.........";
</code></pre>

How to convert a String into an ArrayList?

Kotlin

在我的字符串中，我可以有任意数量的逗号分隔的单词。我希望每个单词都添加到一个ArrayList中。例如：String s = "a,b,c,d,e,.........";

问如何将字符串转换为ArrayList？
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