使用Json.Net将谷歌地图地理编码json响应解析为对象
使用Json.Net将谷歌地图地理编码json响应解析为对象
提问于 2010-06-09 04:41:59
我有一个充满了地址的数据库，我需要得到lat和long，所以我想循环通过它们并使用Google地理编码来更新我的数据库。我陷入了如何解析JSOn结果以获得所需内容的困境：
var address = "http://maps.google.com/maps/api/geocode/json?address=1600+Amphitheatre+Parkway,+Mountain+View,+CA&sensor=false";
var result = new System.Net.WebClient().DownloadString(address);
GoogleGeoCodeResponse test = JsonConvert.DeserializeObject<GoogleGeoCodeResponse>(result);我认为我可以简单地构建一个快速的类，并使用JSON.Net来反序列化结果，这是一种工作，但我认为我在我的类结构上搞砸了：
public class GoogleGeoCodeResponse {
public string status { get; set; }
public geometry geometry { get; set; }
}
public class geometry {
public string location_type { get; set; }
public location location { get; set; }
}
public class location {
public string lat {get;set;}
public string lng {get;set;}
}以下是get从Google返回的示例：
{
"status": "OK",
"results": [ {
"types": [ "street_address" ],
"formatted_address": "1600 Amphitheatre Pkwy, Mountain View, CA 94043, USA",
"address_components": [ {
"long_name": "1600",
"short_name": "1600",
"types": [ "street_number" ]
}, {
"long_name": "Amphitheatre Pkwy",
"short_name": "Amphitheatre Pkwy",
"types": [ "route" ]
}, {
"long_name": "Mountain View",
"short_name": "Mountain View",
"types": [ "locality", "political" ]
}, {
"long_name": "California",
"short_name": "CA",
"types": [ "administrative_area_level_1", "political" ]
}, {
"long_name": "United States",
"short_name": "US",
"types": [ "country", "political" ]
}, {
"long_name": "94043",
"short_name": "94043",
"types": [ "postal_code" ]
} ],
"geometry": {
"location": {
"lat": 37.4219720,
"lng": -122.0841430
},
"location_type": "ROOFTOP",
"viewport": {
"southwest": {
"lat": 37.4188244,
"lng": -122.0872906
},
"northeast": {
"lat": 37.4251196,
"lng": -122.0809954
}
}
}
} ]
}我错过了这里的简单我知道这一点，任何人？
回答 7
Stack Overflow用户
回答已采纳
发布于 2010-08-02 23:30:59
我试过了，做了一个简单的测试，它起作用了(添加了结果和其他)：
public class GoogleGeoCodeResponse
{
public string status { get; set; }
public results[] results { get; set; }
}
public class results
{
public string formatted_address { get; set; }
public geometry geometry { get; set; }
public string[] types { get; set; }
public address_component[] address_components { get; set; }
}
public class geometry
{
public string location_type { get; set; }
public location location { get; set; }
}
public class location
{
public string lat { get; set; }
public string lng { get; set; }
}
public class address_component
{
public string long_name { get; set; }
public string short_name { get; set; }
public string[] types { get; set; }
}Stack Overflow用户
发布于 2011-11-23 08:44:58
您可以使用动态对象，而不是定义对象。
public static dynamic GEOCodeAddress(String Address)
{
var address = String.Format("http://maps.google.com/maps/api/geocode/json?address={0}&sensor=false", Address.Replace(" ", "+"));
var result = new System.Net.WebClient().DownloadString(address);
JavaScriptSerializer jss = new JavaScriptSerializer();
return jss.Deserialize<dynamic>(result);
}Stack Overflow用户
发布于 2010-09-23 03:19:09
参考Google Geo Kit，我也做过类似的事情
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/3001132
复制相关文章
相似问题