将JSON.NET JObject的属性/标记转换为字典键
将JSON.NET JObject的属性/标记转换为字典键
提问于 2013-01-05 01:11:59
我使用JSON.NET通过.NET解析来自openexhangerates.org服务器端的JSON响应，该响应包含一个嵌套对象("rates")，该对象具有一长串数字属性：
{
"disclaimer": "Exchange rates provided for informational purposes only, with no guarantee whatsoever of accuracy, validity, availability, or fitness for any purpose; use at your own risk. Other than that, have fun! Usage subject to acceptance of terms: http://openexchangerates.org/terms/",
"license": "Data sourced from various providers with public-facing APIs; copyright may apply; not for resale; no warranties given. Usage subject to acceptance of license agreement: http://openexchangerates.org/license/",
"timestamp": 1357268408,
"base": "USD",
"rates": {
"AED": 3.673033,
"AFN": 51.5663,
"ALL": 106.813749,
"AMD": 403.579996,
etc...
}
}属性名称对应于货币类型(例如"USD")。我需要假设属性列表可以随着时间的推移而变化，因此我希望将对象转换为字典，而不是相应的C#对象。
因此，不是将JSON对象反序列化为如下所示：
class Rates
{
public decimal AED; // United Arab Emirates Dirham
public decimal AFN; // Afghan Afghani
public decimal ALL; // Albanian Lek
public decimal AMD; // Armenian Dram
// etc...
}我想用这个来结束：
Dictionary<string,decimal>() {{"AED",0.2828},{"AFN",0.3373},{"ALL",2.2823},{"AMD",33.378} // etc...};如何从响应字符串或调用JObject.Parse(responseString)生成的JObject开始？
回答 3
Stack Overflow用户
回答已采纳
发布于 2013-01-05 01:15:03
JObject已经实现了IDictionary<string, JToken>，所以我怀疑当您导航到rates成员时，您应该能够使用：
var result = rates.ToDictionary(pair => pair.Key, pair => (decimal) pair.Value);不幸的是，它使用了显式的接口实现，这使得这有点麻烦--但是如果你通过IDictionary<string, JToken>接口，那就没问题了。
下面是一个简短但完整的示例，它似乎适用于您提供的JSON (保存为test.json文件)：
using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using Newtonsoft.Json.Linq;
class Test
{
static void Main()
{
JObject parsed = JObject.Parse(File.ReadAllText("test.json"));
IDictionary<string, JToken> rates = (JObject) parsed["rates"];
// Explicit typing just for "proof" here
Dictionary<string, decimal> dictionary =
rates.ToDictionary(pair => pair.Key,
pair => (decimal) pair.Value);
Console.WriteLine(dictionary["ALL"]);
}
}Stack Overflow用户
发布于 2014-01-21 09:54:29
这对你有效吗？
using System;
using System.Collections.Generic;
using System.Linq;
using Newtonsoft.Json.Linq;
namespace JsonNetTest
{
class Program
{
static void Main(string[] args)
{
string jsonString = @"{
'disclaimer': 'Exchange rates provided for informational purposes only, with no guarantee whatsoever of accuracy, validity, availability, or fitness for any purpose; use at your own risk. Other than that, have fun! Usage subject to acceptance of terms: http://openexchangerates.org/terms/',
'license': 'Data sourced from various providers with public-facing APIs; copyright may apply; not for resale; no warranties given. Usage subject to acceptance of license agreement: http://openexchangerates.org/license/',
'timestamp': 1357268408,
'base': 'USD',
'rates': {
'AED': 3.673033,
'AFN': 51.5663,
'ALL': 106.813749,
'AMD': 403.579996
}
}";
JObject parsed = JObject.Parse(jsonString);
Dictionary<string, decimal> rates = parsed["rates"].ToObject<Dictionary<string, decimal>>();
Console.WriteLine(rates["ALL"]);
Console.ReadKey();
}
}
}Stack Overflow用户
发布于 2015-10-10 18:54:52
如果您希望子对象具有对象属性(或字段)，最好使用：
Dictionary<string, object> rates = parsed["rates"].ToObject<Dictionary<string, object>>();否则，它将抛出错误。
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原文链接：
https://stackoverflow.com/questions/14161615
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