如何用PHP cURL发布JSON数据？
如何用PHP cURL发布JSON数据？
提问于 2012-06-18 16:17:51
这是我的代码，
$url = 'url_to_post';
$data = array(
"first_name" => "First name",
"last_name" => "last name",
"email"=>"email@gmail.com",
"addresses" => array (
"address1" => "some address",
"city" => "city",
"country" => "CA",
"first_name" => "Mother",
"last_name" => "Lastnameson",
"phone" => "555-1212",
"province" => "ON",
"zip" => "123 ABC"
)
);
$data_string = json_encode($data);
$ch=curl_init($url);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, array("customer"=>$data_string));
curl_setopt($ch, CURLOPT_HEADER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER,
array(
'Content-Type:application/json',
'Content-Length: ' . strlen($data_string)
)
);
$result = curl_exec($ch);
curl_close($ch);在其他页面上，我正在检索帖子数据。
print_r ($_POST);输出为
HTTP/1.1 200 OK
Date: Mon, 18 Jun 2012 07:58:11 GMT
Server: Apache
X-Powered-By: PHP/5.3.6
Vary: Accept-Encoding
Connection: close
Content-Type: text/html
Array ( ) 所以，即使在我自己的服务器上，我也没有得到正确的数据，它是一个空数组。我想像在http://docs.shopify.com/api/customer#create一样使用json实现REST
回答 4
Stack Overflow用户
发布于 2018-12-24 14:03:24
$url = 'url_to_post';
$data = array("first_name" => "First name","last_name" => "last name","email"=>"email@gmail.com","addresses" => array ("address1" => "some address" ,"city" => "city","country" => "CA", "first_name" => "Mother","last_name" => "Lastnameson","phone" => "555-1212", "province" => "ON", "zip" => "123 ABC" ) );
$postdata = json_encode($data);
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $postdata);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/json'));
$result = curl_exec($ch);
curl_close($ch);
print_r ($result);这段代码对我很有效。你可以试试..。
Stack Overflow用户
发布于 2018-03-06 21:09:51
请尝试此代码：-
$url = 'url_to_post';
$data = array("first_name" => "First name","last_name" => "last name","email"=>"email@gmail.com","addresses" => array ("address1" => "some address" ,"city" => "city","country" => "CA", "first_name" => "Mother","last_name" => "Lastnameson","phone" => "555-1212", "province" => "ON", "zip" => "123 ABC" ) );
$data_string = json_encode(array("customer" =>$data));
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type:application/json'));
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$result = curl_exec($ch);
curl_close($ch);
echo "$result";Stack Overflow用户
发布于 2012-06-18 16:38:38
试着这样做：
$url = 'url_to_post';
// this is only part of the data you need to sen
$customer_data = array("first_name" => "First name","last_name" => "last name","email"=>"email@gmail.com","addresses" => array ("address1" => "some address" ,"city" => "city","country" => "CA", "first_name" => "Mother","last_name" => "Lastnameson","phone" => "555-1212", "province" => "ON", "zip" => "123 ABC" ) );
// As per your API, the customer data should be structured this way
$data = array("customer" => $customer_data);
// And then encoded as a json string
$data_string = json_encode($data);
$ch=curl_init($url);
curl_setopt_array($ch, array(
CURLOPT_POST => true,
CURLOPT_POSTFIELDS => $data_string,
CURLOPT_HEADER => true,
CURLOPT_HTTPHEADER => array('Content-Type:application/json', 'Content-Length: ' . strlen($data_string)))
));
$result = curl_exec($ch);
curl_close($ch);您忘记的关键事情是json_encode您的数据。但是您可能会发现，通过传递一个数组，使用curl_setopt_array一次设置所有的curl选项会很方便。
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原文链接：
https://stackoverflow.com/questions/11079135
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