blocks|key|710709|text|使用-获取两个datetime对象之间的差异并获取days成员。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|710710|from+datetime+import+datetime

def+days_between(d1,+d2):
++++d1+=+datetime.strptime(d1,+"%25Y-%25m-%25d")
++++d2+=+datetime.strptime(d2,+"%25Y-%25m-%25d")
++++return+abs((d2+-+d1).days)|code-block|syntax|javascript|710711|entityMap^0|2|1|7|8|P|4|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|U|8|@]|D|@]|E|$]]]|L|$]]

Use <code>-</code> to get the difference between two <code>datetime</code> objects and take the <code>days</code> member.

<pre><code>from datetime import datetime

def days_between(d1, d2):
 d1 = datetime.strptime(d1, "%Y-%m-%d")
 d2 = datetime.strptime(d2, "%Y-%m-%d")
 return abs((d2 - d1).days)
</code></pre>

blocks|key|710762|text|我尝试了上面larsmans发布的代码，但有几个问题：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|710763|1)原样代码将抛出mauguerra提到的错误2)如果您将代码更改为以下代码：|710764|...
++++d1+=+d1.strftime("%25Y-%25m-%25d")
++++d2+=+d2.strftime("%25Y-%25m-%25d")
++++return+abs((d2+-+d1).days)|code-block|syntax|javascript|710765|这将把datetime对象转换为字符串，但是，有两件事|710766|1)尝试执行d2+-+d1将失败，因为您不能在字符串上使用减号运算符；2)如果您阅读上面答案的第一行，您希望在两个datetime对象上使用-运算符，但您只是将它们转换为字符串|710767|我发现从字面上看，你只需要以下内容：|710768|import+datetime

end_date+=+datetime.datetime.utcnow()
start_date+=+end_date+-+datetime.timedelta(days=8)
difference_in_days+=+abs((end_date+-+start_date).days)

print+difference_in_days|710769|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|V|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|W|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|X|8|@]|9|@]|A|$]]|$1|O|3|P|5|F|7|Y|8|@]|9|@]|A|$G|H]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

I tried the code posted by larsmans above but, there are a couple of problems:

1) The code as is will throw the error as mentioned by mauguerra
2) If you change the code to the following:

<pre><code>...
 d1 = d1.strftime("%Y-%m-%d")
 d2 = d2.strftime("%Y-%m-%d")
 return abs((d2 - d1).days)
</code></pre>

This will convert your datetime objects to strings but, two things

1) Trying to do d2 - d1 will fail as you cannot use the minus operator on strings and
2) If you read the first line of the above answer it stated, you want to use the - operator on two datetime objects but, you just converted them to strings

What I found is that you literally only need the following:

<pre><code>import datetime

end_date = datetime.datetime.utcnow()
start_date = end_date - datetime.timedelta(days=8)
difference_in_days = abs((end_date - start_date).days)

print difference_in_days
</code></pre>

blocks|key|495209|text|另一个简短的解决方案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|495210|from+datetime+import+date

def+diff_dates(date1,+date2):
++++return+abs(date2-date1).days

def+main():
++++d1+=+date(2013,1,1)
++++d2+=+date(2013,9,13)
++++result1+=+diff_dates(d2,+d1)
++++print+'{}+days+between+{}+and+{}'.format(result1,+d1,+d2)
++++print+("Happy+programmer's+day!")

main()|code-block|syntax|javascript|495211|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Another short solution:

<pre><code>from datetime import date

def diff_dates(date1, date2):
 return abs(date2-date1).days

def main():
 d1 = date(2013,1,1)
 d2 = date(2013,9,13)
 result1 = diff_dates(d2, d1)
 print '{} days between {} and {}'.format(result1, d1, d2)
 print ("Happy programmer's day!")

main()
</code></pre>

blocks|key|710809|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|710810|data=pd.read_csv('C:\Users\Desktop\Data+Exploration.csv')
data.head(5)
first=data['1st+Gift']
last=data['Last+Gift']
maxi=data['Largest+Gift']
l_1=np.mean(first)-3*np.std(first)
u_1=np.mean(first)%2B3*np.std(first)


m=np.abs(data['1st+Gift']-np.mean(data['1st+Gift']))>3*np.std(data['1st+Gift'])
pd.value_counts(m)
l=first[m]
data.loc[:,'1st+Gift'][m==True]=np.mean(data['1st+Gift'])%2B3*np.std(data['1st+Gift'])
data['1st+Gift'].head()




m=np.abs(data['Last+Gift']-np.mean(data['Last+Gift']))>3*np.std(data['Last+Gift'])
pd.value_counts(m)
l=last[m]
data.loc[:,'Last+Gift'][m==True]=np.mean(data['Last+Gift'])%2B3*np.std(data['Last+Gift'])
data['Last+Gift'].head()|code-block|syntax|javascript|710811|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try this:

<pre><code>data=pd.read_csv('C:\Users\Desktop\Data Exploration.csv')
data.head(5)
first=data['1st Gift']
last=data['Last Gift']
maxi=data['Largest Gift']
l_1=np.mean(first)-3*np.std(first)
u_1=np.mean(first)+3*np.std(first)


m=np.abs(data['1st Gift']-np.mean(data['1st Gift']))&gt;3*np.std(data['1st Gift'])
pd.value_counts(m)
l=first[m]
data.loc[:,'1st Gift'][m==True]=np.mean(data['1st Gift'])+3*np.std(data['1st Gift'])
data['1st Gift'].head()




m=np.abs(data['Last Gift']-np.mean(data['Last Gift']))&gt;3*np.std(data['Last Gift'])
pd.value_counts(m)
l=last[m]
data.loc[:,'Last Gift'][m==True]=np.mean(data['Last Gift'])+3*np.std(data['Last Gift'])
data['Last Gift'].head()
</code></pre>

blocks|key|495289|text|pd.date_range('2019-01-01'，'2019-02-01').shape|type|unstyled|depth|inlineStyleRanges|entityRanges|data|495290|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

pd.date_range('2019-01-01', '2019-02-01').shape[0]

I have two different dates and I want to know the difference in days between them. The format of the date is YYYY-MM-DD.

I have a function that can ADD or SUBTRACT a given number to a date:

<pre><code>def addonDays(a, x):
 ret = time.strftime("%Y-%m-%d",time.localtime(time.mktime(time.strptime(a,"%Y-%m-%d"))+x*3600*24+3600)) 
 return ret
</code></pre>

where A is the date and x the number of days I want to add. And the result is another date.

I need a function where I can give two dates and the result would be an int with date difference in days.

Difference between two dates in Python

我有两个不同的日期，我想知道它们之间的天数差异。日期的格式为YYYY-MM-DD。我有一个函数可以将给定的数字与日期相加或相减：def addonDays(a, x):   ret = time.strftime("%Y-%m-%d",time.localtime(time.mktime(time.strptime(a...

问Python中两个日期之间的差异
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