blocks|key|3321303|text|MD5散列值只是一个128位的值，所以如果你想要一个随机的值：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3321304|import+random

hash+=+random.getrandbits(128)

print("hash+value:+%25032x"+%25+hash)|code-block|syntax|javascript|3321305|不过，我真的不明白这一点。也许你应该详细解释一下为什么你需要这个。|3321306|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

A md5-hash is just a 128-bit value, so if you want a random one:

<pre><code>import random

hash = random.getrandbits(128)

print("hash value: %032x" % hash)
</code></pre>

I don't really see the point, though. Maybe you should elaborate why you need this...

blocks|key|3108596|text|我认为您正在寻找的是一个通用的、唯一的identifier.Then，python中的模块UUID就是您正在寻找的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3108597|import+uuid
uuid.uuid4().hex|code-block|syntax|javascript|3108598|UUID4为您提供了一个随机的唯一标识符，该标识符的长度与md5和相同。十六进制将表示为十六进制字符串，而不是返回uuid对象。|3108599|http://docs.python.org/2/library/uuid.html|offset|length|3108600|entityMap|0|LINK|mutability|MUTABLE|url^0|0|0|0|0|16|0|0^^$0|@$1|2|3|4|5|6|7|T|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|U|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|V|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|W|8|@]|9|@$K|X|L|Y|1|Z]]|A|$]]|$1|M|3|-4|5|6|7|10|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|J]]]]

I think what you are looking for is a universal unique identifier.Then the module UUID in python is what you are looking for.

<pre><code>import uuid
uuid.uuid4().hex
</code></pre>

UUID4 gives you a random unique identifier that has the same length as a md5 sum. Hex will represent is as an hex string instead of returning a uuid object. 

<a href="http://docs.python.org/2/library/uuid.html">http://docs.python.org/2/library/uuid.html</a>

blocks|key|339408|text|secrets+module是在Python+3.6%2B中添加的。它通过一个调用提供加密安全的随机值。这些函数接受一个可选的nbytes参数，默认值为32+(字节*8位=256位标记)。MD5有128位散列，因此为“类md5”令牌提供16位散列。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|339409|>>>+import+secrets

>>>+secrets.token_hex(nbytes=16)
'17adbcf543e851aa9216acc9d7206b96'

>>>+secrets.token_urlsafe(16)
'X7NYIolv893DXLunTzeTIQ'

>>>+secrets.token_bytes(128+//+8)
b'\x0b\xdcA\xc0.\x0e\x87\x9b`\x93\\Ev\x1a%7Cu'|code-block|syntax|javascript|339410|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/3/library/secrets.html^0|0|7|1P|6|0|E|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@$9|X|A|Y|1|Z]]|E|$]]|$1|F|3|G|5|H|7|10|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]]]

The <a href="https://docs.python.org/3/library/secrets.html" rel="noreferrer"><code>secrets</code> module</a> was added in Python 3.6+. It provides cryptographically secure random values with a single call. The functions take an optional <code>nbytes</code> argument, default is 32 (bytes * 8 bits = 256-bit tokens). MD5 has 128-bit hashes, so provide 16 for "MD5-like" tokens.

<pre><code>&gt;&gt;&gt; import secrets

&gt;&gt;&gt; secrets.token_hex(nbytes=16)
'17adbcf543e851aa9216acc9d7206b96'

&gt;&gt;&gt; secrets.token_urlsafe(16)
'X7NYIolv893DXLunTzeTIQ'

&gt;&gt;&gt; secrets.token_bytes(128 // 8)
b'\x0b\xdcA\xc0.\x0e\x87\x9b`\x93\\Ev\x1a|u'
</code></pre>

blocks|key|342848|text|这适用于python+2.x和3.x|type|unstyled|depth|inlineStyleRanges|entityRanges|data|342849|import+os
import+binascii
print(binascii.hexlify(os.urandom(16)))
'4a4d443679ed46f7514ad6dbe3733c3d'|code-block|syntax|javascript|342850|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This works for both python 2.x and 3.x

<pre><code>import os
import binascii
print(binascii.hexlify(os.urandom(16)))
'4a4d443679ed46f7514ad6dbe3733c3d'
</code></pre>

blocks|key|3321406|text|还有另一种方法。你不需要格式化一个int来得到它。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3321407|import+random
import+string

def+random_string(length):
++++pool+=+string.letters+%2B+string.digits
++++return+''.join(random.choice(pool)+for+i+in+xrange(length))|code-block|syntax|javascript|3321408|使您可以灵活地控制字符串的长度。|3321409|>>>+random_string(64)
'XTgDkdxHK7seEbNDDUim9gUBFiheRLRgg7HyP18j6BZU5Sa7AXiCHP1NEIxuL2s0'|3321410|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Yet another approach. You won't have to format an int to get it.

<pre><code>import random
import string

def random_string(length):
 pool = string.letters + string.digits
 return ''.join(random.choice(pool) for i in xrange(length))
</code></pre>

Gives you flexibility on the length of the string.

<pre><code>&gt;&gt;&gt; random_string(64)
'XTgDkdxHK7seEbNDDUim9gUBFiheRLRgg7HyP18j6BZU5Sa7AXiCHP1NEIxuL2s0'
</code></pre>

blocks|key|3321335|text|这个特定问题的另一种方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3321336|import+random,+string

def+random_md5like_hash():
++++available_chars=+string.hexdigits[:16]
++++return+''.join(
++++++++random.choice(available_chars)
++++++++for+dummy+in+xrange(32))|code-block|syntax|javascript|3321337|我并不是说它比任何其他答案更快或更可取；只是说它是另一种方法:)|3321338|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Another approach to this specific question:

<pre><code>import random, string

def random_md5like_hash():
 available_chars= string.hexdigits[:16]
 return ''.join(
 random.choice(available_chars)
 for dummy in xrange(32))
</code></pre>

I'm not saying it's faster or preferable to any other answer; just that it's another approach :)

blocks|key|342852|text|import+uuid
from+md5+import+md5

print+md5(str(uuid.uuid4())).hexdigest()|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|342853|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>import uuid
from md5 import md5

print md5(str(uuid.uuid4())).hexdigest()
</code></pre>

blocks|key|342889|text|import+os,+hashlib
hashlib.md5(os.urandom(32)).hexdigest()|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|342890|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>import os, hashlib
hashlib.md5(os.urandom(32)).hexdigest()
</code></pre>

blocks|key|3108707|text|from+hashlib+import+md5
plaintext+=+input('Enter+the+plaintext+data+to+be+hashed:+')+#+Must+be+a+string,+doesn't+need+to+have+utf-8+encoding
ciphertext+=+md5(plaintext.encode('utf-8')).hexdigest()
print(ciphertext)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3108708|还应该注意的是，MD5是一个非常弱的散列函数，也发现了冲突(两个不同的明文值导致相同的散列)，只是使用plaintext的随机值。|unstyled|offset|length|style|CODE|3108709|entityMap^0|0|1F|9|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre class="lang-py prettyprint-override"><code>
from hashlib import md5
plaintext = input('Enter the plaintext data to be hashed: ') # Must be a string, doesn't need to have utf-8 encoding
ciphertext = md5(plaintext.encode('utf-8')).hexdigest()
print(ciphertext)
</code></pre>
It should also be noted that MD5 is a very weak hash function, also collisions have been found (two different plaintext values result in the same hash)
Just use a random value for <code>plaintext</code>.

What is the easiest way to generate a random hash (MD5) in Python?

Random hash in Python

Python

在中生成随机哈希(MD5)的最简单的方法是什么？

问Python中的随机哈希
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