blocks|key|1274563|text|您想要具有搜索值的array_keys|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1274564|array_keys($list[0],+"2009-09-09");|code-block|syntax|javascript|1274565|它将返回具有指定值的键的数组，在本例中为0，2。如果您还想查找重复项，可以首先使用array_unique传递，然后在原始数组上使用array_keys遍历该数组；任何返回长度大于1的数组的都是复制项，结果是存储重复项的键。就像..。|1274566|$uniqueKeys+=+array_unique($list[0])

foreach+($uniqueKeys+as+$uniqueKey)
{
++$v+=+array_keys($list[0],+$uniqueKey);

++if+(count($v)+>+1)
++{
++++foreach+($v+as+$key)
++++{
++++++//+Work+with+$list[0][$key]
++++}

++}
}|1274567|entityMap|0|LINK|mutability|MUTABLE|url|http://tr.php.net/manual/en/function.array-keys.php|1|http://uk3.php.net/manual/en/function.array-unique.php^0|9|A|0|0|0|15|C|1|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@$A|X|B|Y|1|Z]]|C|$]]|$1|D|3|E|5|F|7|10|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|11|8|@]|9|@$A|12|B|13|1|14]]|C|$]]|$1|K|3|L|5|F|7|15|8|@]|9|@]|C|$G|H]]|$1|M|3|-4|5|6|7|16|8|@]|9|@]|C|$]]]|N|$O|$5|P|Q|R|C|$S|T]]|U|$5|P|Q|R|C|$S|V]]]]

You want <a href="http://tr.php.net/manual/en/function.array-keys.php" rel="noreferrer">array_keys</a> with the search value

<pre><code>array_keys($list[0], "2009-09-09");
</code></pre>

which will return an array of the keys with the specified value, in your case [0, 2]. If you want to find the duplicates as well, you can first make a pass with <a href="http://uk3.php.net/manual/en/function.array-unique.php" rel="noreferrer">array_unique</a>, then iterate over that array using array_keys on the original; anything which returns an array of length > 1 is a duplicate, and the result is the keys in which the duplicates are stored. Something like...

<pre><code>$uniqueKeys = array_unique($list[0])

foreach ($uniqueKeys as $uniqueKey)
{
 $v = array_keys($list[0], $uniqueKey);

 if (count($v) &gt; 1)
 {
 foreach ($v as $key)
 {
 // Work with $list[0][$key]
 }

 }
}
</code></pre>

blocks|key|1489380|text|PHP手册在Return+Value+section+of+the+array_search()+function+documentation中指出，您可以使用array_keys()来完成此任务。您只需要提供第二个参数：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1489381|$keys+=+array_keys($list[0],+"2009-09-09");|code-block|syntax|javascript|1489382|entityMap|0|LINK|mutability|MUTABLE|url|http://php.net/manual/en/function.array-search.php#function.array-search.returnvalues|1|http://php.net/manual/en/function.array-keys.php^0|6|C|Y|E|28|C|6|1T|0|28|C|1|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@$9|11|A|12|1|13]|$9|14|A|15|1|16]]|E|$]]|$1|F|3|G|5|H|7|17|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|18|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]|S|$5|N|O|P|E|$Q|T]]]]

The PHP manual states in the <a href="http://php.net/manual/en/function.array-search.php#function.array-search.returnvalues" rel="nofollow noreferrer"><code>Return Value</code> section of the <code>array_search()</code> function documentation</a> that you can use <a href="http://php.net/manual/en/function.array-keys.php" rel="nofollow noreferrer"><code>array_keys()</code></a> to accomplish this. You just need to provide the second parameter:

<pre><code>$keys = array_keys($list[0], "2009-09-09");
</code></pre>

blocks|key|1274640|text|下面的函数调用组合将为您提供所有重复的值：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1274641|$a+=+array(1,+1,+2,+3,+4,+5,+99,+2,+5,+2);

$unique+++++=+array_unique($a);+//+preserves+keys
$diffkeys+++=+array_diff_key($a,+$unique);
$duplicates+=+array_unique($diffkeys);

echo+'Duplicates:+'+.+join('+',+$duplicates)+.+"\n";+//+1+2+5|code-block|syntax|javascript|1274642|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

The following combination of function calls will give you all duplicate values:

<pre><code>$a = array(1, 1, 2, 3, 4, 5, 99, 2, 5, 2);

$unique = array_unique($a); // preserves keys
$diffkeys = array_diff_key($a, $unique);
$duplicates = array_unique($diffkeys);

echo 'Duplicates: ' . join(' ', $duplicates) . "\n"; // 1 2 5
</code></pre>

blocks|key|1489435|text|$userdb=Array
(
++++(0)+=>+Array
++++++++(
++++++++++++(uid)+=>+'100',
++++++++++++(name)+=>+'Sandra+Shush',
++++++++++++(url)+=>+'urlof100'
++++++++),
);

$key+=+array_search(100,+array_column($userdb,+'uid'));|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1489436|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$userdb=Array
(
 (0) =&gt; Array
 (
 (uid) =&gt; '100',
 (name) =&gt; 'Sandra Shush',
 (url) =&gt; 'urlof100'
 ),
);

$key = array_search(100, array_column($userdb, 'uid'));
</code></pre>

I need to get the keys from values that are duplicates. I tried to use array_search and that worked fine, BUT I only got the first value as a hit.

I need to get both keys from the duplicate values, in this case 0 and 2. The search result output as an array would be good.

Is there a PHP function to do this or do I need to write some multiple loops to do it?

<pre><code>$list[0][0] = "2009-09-09";
$list[0][1] = "2009-05-05";
$list[0][2] = "2009-09-09";
$list[1][0] = "first-paid";
$list[1][1] = "1";
$list[1][2] = "last-unpaid";

echo array_search("2009-09-09",$list[0]);
</code></pre>

How to search Array for multiple values in PHP?

我需要从重复的值中获取键。我试着使用array_search，它工作得很好，但我只得到了第一个值。我需要从重复的值中获取两个键，在本例中为0和2。以数组形式输出的搜索结果会很好。有没有PHP函数可以做到这一点，或者我需要编写一些多个循环来做到这一点？$list[0][0] = "2009-09-09";$list[0]...

问如何在PHP中搜索数组的多个值？
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