我在Windows上使用XAMPP。在我的开发中,我使用了http://127.0.0.1/test_website/
。
如何在PHP中获得http://127.0.0.1/test_website/
?
我试过这样的方法,但都不起作用。
echo dirname(__FILE__)
or
echo basename(__FILE__);
etc.
发布于 2013-01-24 19:39:17
函数调整为在没有警告的情况下执行:
function url(){
if(isset($_SERVER['HTTPS'])){
$protocol = ($_SERVER['HTTPS'] && $_SERVER['HTTPS'] != "off") ? "https" : "http";
}
else{
$protocol = 'http';
}
return $protocol . "://" . $_SERVER['HTTP_HOST'] . $_SERVER['REQUEST_URI'];
}
发布于 2013-11-19 23:12:13
有趣的'base_url‘片段!
if (!function_exists('base_url')) {
function base_url($atRoot=FALSE, $atCore=FALSE, $parse=FALSE){
if (isset($_SERVER['HTTP_HOST'])) {
$http = isset($_SERVER['HTTPS']) && strtolower($_SERVER['HTTPS']) !== 'off' ? 'https' : 'http';
$hostname = $_SERVER['HTTP_HOST'];
$dir = str_replace(basename($_SERVER['SCRIPT_NAME']), '', $_SERVER['SCRIPT_NAME']);
$core = preg_split('@/@', str_replace($_SERVER['DOCUMENT_ROOT'], '', realpath(dirname(__FILE__))), NULL, PREG_SPLIT_NO_EMPTY);
$core = $core[0];
$tmplt = $atRoot ? ($atCore ? "%s://%s/%s/" : "%s://%s/") : ($atCore ? "%s://%s/%s/" : "%s://%s%s");
$end = $atRoot ? ($atCore ? $core : $hostname) : ($atCore ? $core : $dir);
$base_url = sprintf( $tmplt, $http, $hostname, $end );
}
else $base_url = 'http://localhost/';
if ($parse) {
$base_url = parse_url($base_url);
if (isset($base_url['path'])) if ($base_url['path'] == '/') $base_url['path'] = '';
}
return $base_url;
}
}
像这样简单地使用:
// url like: http://stackoverflow.com/questions/2820723/how-to-get-base-url-with-php
echo base_url(); // will produce something like: http://stackoverflow.com/questions/2820723/
echo base_url(TRUE); // will produce something like: http://stackoverflow.com/
echo base_url(TRUE, TRUE); || echo base_url(NULL, TRUE); // will produce something like: http://stackoverflow.com/questions/
// and finally
echo base_url(NULL, NULL, TRUE);
// will produce something like:
// array(3) {
// ["scheme"]=>
// string(4) "http"
// ["host"]=>
// string(12) "stackoverflow.com"
// ["path"]=>
// string(35) "/questions/2820723/"
// }
发布于 2014-07-15 04:20:54
$base_url="http://".$_SERVER['SERVER_NAME'].dirname($_SERVER["REQUEST_URI"].'?').'/';
用法:
print "<script src='{$base_url}js/jquery.min.js'/>";
https://stackoverflow.com/questions/2820723
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