blocks|key|2796577|text|使用子字符串和连接：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2796578|if(str.length()+>+50)
++++strOut+=+str.substring(0,7)+%2B+"...";|code-block|syntax|javascript|2796579|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Use substring and concatenate:

<pre><code>if(str.length() &gt; 50)
 strOut = str.substring(0,7) + "...";
</code></pre>

blocks|key|185206|text|StringUtils.abbreviate("abcdefg",+6);|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|185207|这将为您提供以下结果：abc...|185208|其中6是所需的长度，"abcdefg“是需要缩写的字符串。|185209|entityMap^0|0|11|0|B|6|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@$9|M|A|N|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|R|8|@]|D|@]|E|$]]|$1|J|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|K|$]]

<code>StringUtils.abbreviate("abcdefg", 6);</code>

This will give you the following result: <code>abc...</code>

Where 6 is the needed length, and "abcdefg" is the string that needs to be abbrevieted.

blocks|key|2796481|text|使用子字符串|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2796482|String+strOut+=+"abcdefghijklmnopqrtuvwxyz"
String+result+=+strOut.substring(0,+8)+%2B+"...";//+count+start+in+0+and+8+is+excluded
System.out.pritnln(result);|code-block|syntax|javascript|2796483|注意:+substring(int+first，int+second)有两个参数。第一个是包容性的，第二个是排他性的。|2796484|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Use substring

<pre><code>String strOut = "abcdefghijklmnopqrtuvwxyz"
String result = strOut.substring(0, 8) + "...";// count start in 0 and 8 is excluded
System.out.pritnln(result);
</code></pre>

Note: substring(int first, int second) takes two parameters. The first is inclusive and the second is exclusive.

blocks|key|183294|text|雅加达公共StringUtils.abbreviate()。如果出于某种原因你不想使用第三方库，至少可以复制source+code。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|183295|与目前为止的其他答案相比，这有一个很大的好处，就是如果你传入一个null，它就不会抛出。|183296|entityMap|0|LINK|mutability|MUTABLE|url|http://commons.apache.org/proper/commons-lang/javadocs/api-3.1/org/apache/commons/lang3/StringUtils.html#abbreviate%2528java.lang.String,%2520int%2529|1|http://svn.apache.org/viewvc/commons/proper/lang/trunk/src/main/java/org/apache/commons/lang3/StringUtils.java?view=markup^0|5|O|0|1I|B|1|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@$A|Q|B|R|1|S]|$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|6|7|W|8|@]|9|@]|C|$]]|$1|F|3|-4|5|6|7|X|8|@]|9|@]|C|$]]]|G|$H|$5|I|J|K|C|$L|M]]|N|$5|I|J|K|C|$L|O]]]]

Jakarta Commons <a href="http://commons.apache.org/proper/commons-lang/javadocs/api-3.1/org/apache/commons/lang3/StringUtils.html#abbreviate%28java.lang.String,%20int%29" rel="noreferrer">StringUtils.abbreviate()</a>. If, for some reason you don't want to use a 3rd-party library, at least copy the <a href="http://svn.apache.org/viewvc/commons/proper/lang/trunk/src/main/java/org/apache/commons/lang3/StringUtils.java?view=markup" rel="noreferrer">source code</a>.

One big benefit of this over the other answers to date is that it won't throw if you pass in a null.

blocks|key|183340|text|您可以使用安全子字符串：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|183341|org.apache.commons.lang3.StringUtils.substring(str,+0,+LENGTH);|code-block|syntax|javascript|183342|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use safe substring:

<pre><code>org.apache.commons.lang3.StringUtils.substring(str, 0, LENGTH);
</code></pre>

blocks|key|2796584|text|您可以使用String#substring()|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2796585|if(str+!=+null+&&+str.length()+>+8)+{
++++return+str.substring(0,+8)+%2B+"...";
}+else+{
++++return+str;
}|code-block|syntax|javascript|2796586|但是，您可以创建一个函数，在该函数中传递可以显示的最大字符数。然后，只有当指定的宽度不足以容纳字符串时，省略号才会被插入。|2796587|public+String+getShortString(String+input,+int+width)+{
++if(str+!=+null+&&+str.length()+>+width)+{
++++++return+str.substring(0,+width+-+3)+%2B+"...";
++}+else+{
++++++return+str;
++}
}

//+abcdefgh...
System.out.println(getShortString("abcdefghijklmnopqrstuvwxyz",+11));

//+abcdefghijk
System.out.println(getShortString("abcdefghijk",+11));+//+no+need+to+trim|2796588|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.oracle.com/javase/7/docs/api/java/lang/String.html#substring%2528int,%2520int%2529^0|5|I|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@$A|V|B|W|1|X]]|C|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|Z|8|@]|9|@]|C|$]]|$1|K|3|L|5|F|7|10|8|@]|9|@]|C|$G|H]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|C|$]]]|N|$O|$5|P|Q|R|C|$S|T]]]]

You can use <a href="http://docs.oracle.com/javase/7/docs/api/java/lang/String.html#substring%28int,%20int%29" rel="nofollow">String#substring()</a>

<pre><code>if(str != null &amp;&amp; str.length() &gt; 8) {
 return str.substring(0, 8) + "...";
} else {
 return str;
}
</code></pre>

You could however make a function where you pass the maximum number of characters that can be displayed. The ellipsis would then cut in only if the width specified isn't enough for the string.

<pre><code>public String getShortString(String input, int width) {
 if(str != null &amp;&amp; str.length() &gt; width) {
 return str.substring(0, width - 3) + "...";
 } else {
 return str;
 }
}

// abcdefgh...
System.out.println(getShortString("abcdefghijklmnopqrstuvwxyz", 11));

// abcdefghijk
System.out.println(getShortString("abcdefghijk", 11)); // no need to trim
</code></pre>

blocks|key|185160|text|类似这样的内容可能是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|185161|String+str+=+"abcdefghijklmnopqrtuvwxyz";
if+(str.length()+>+8)
++++str+=+str.substring(0,+8)+%2B+"...";|code-block|syntax|javascript|185162|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Something like this may be:

<pre><code>String str = "abcdefghijklmnopqrtuvwxyz";
if (str.length() &gt; 8)
 str = str.substring(0, 8) + "...";
</code></pre>

blocks|key|2796564|text|String+strOut+=+str.substring(0,+8)+%2B+"...";|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2796565|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>String strOut = str.substring(0, 8) + "...";
</code></pre>

I would like to cut a Java String when this String length is > 50, and add "..." at the end of the string.

Example :

I have the following Java String :

<pre><code>String str = "abcdefghijklmnopqrtuvwxyz";
</code></pre>

I would like to cut the String at length = 8 :

Result must be:

<pre><code>String strOut = "abcdefgh..."
</code></pre>

Cut Java String at a number of character

Java

当这个字符串长度大于50时，我想剪切一个Java字符串，并添加"...“在字符串的末尾。示例:我有以下Java字符串：String str = "abcdefghijklmnopqrtuvwxyz";我想剪断长度为8的字符串：结果必须为：String strOut = "abcdefgh..."

问在若干字符处剪切Java字符串
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