blocks|key|982680|text|代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|982681|public+class+Test+{
++++public+static+void+main(String+args[])+{
++++++++String+string+=+args[0];
++++++++System.out.println("last+character:+"+%2B
+++++++++++++++++++++++++++string.substring(string.length()+-+1));+
++++}
}|code-block|syntax|javascript|982682|java+Test+abcdef的输出|offset|length|style|CODE|982683|last+character:+f|982684|entityMap^0|0|0|0|G|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

The code:

<pre><code>public class Test {
 public static void main(String args[]) {
 String string = args[0];
 System.out.println("last character: " +
 string.substring(string.length() - 1)); 
 }
}
</code></pre>

The output of <code>java Test abcdef</code>:

<pre><code>last character: f
</code></pre>

blocks|key|982734|text|简单的解决方案是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|982735|public+String+frontBack(String+str)+{
++if+(str+==+null+%7C%7C+str.length()+==+0)+{
++++return+str;
++}
++char[]+cs+=+str.toCharArray();
++char+first+=+cs[0];
++cs[0]+=+cs[cs.length+-1];
++cs[cs.length+-1]+=+first;
++return+new+String(cs);
}|code-block|syntax|javascript|982736|使用字符数组(注意讨厌的空字符串或空字符串参数！)|982737|另一种解决方案是使用StringBuilder+(由于字符串本身是不可变的，它通常用于执行字符串处理)。|982738|public+String+frontBack(String+str)+{
++if+(str+==+null+%7C%7C+str.length()+==+0)+{
++++return+str;
++}
++StringBuilder+sb+=+new+StringBuilder(str);++
++char+first+=+sb.charAt(0);
++sb.setCharAt(0,+sb.charAt(sb.length()-1));
++sb.setCharAt(sb.length()-1,+first);
++return+sb.toString();
}|982739|还有另一种方法(更多地用于指导而不是实际使用)是这种方法：|982740|public+String+frontBack(String+str)+{
++if+(str+==+null+%7C%7C+str.length()+<+2)+{
++++return+str;
++}
++StringBuilder+sb+=+new+StringBuilder(str);
++String+sub+=+sb.substring(1,+sb.length()+-1);
++return+sb.reverse().replace(1,+sb.length()+-1,+sub).toString();
}|982741|这里颠倒了整个字符串，然后用子字符串替换了不应该颠倒的部分。;)|982742|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|X|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|Y|8|@]|9|@]|A|$E|F]]|$1|M|3|N|5|6|7|Z|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|10|8|@]|9|@]|A|$E|F]]|$1|Q|3|R|5|6|7|11|8|@]|9|@]|A|$]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

Simple solution is:

<pre><code>public String frontBack(String str) {
 if (str == null || str.length() == 0) {
 return str;
 }
 char[] cs = str.toCharArray();
 char first = cs[0];
 cs[0] = cs[cs.length -1];
 cs[cs.length -1] = first;
 return new String(cs);
}
</code></pre>

Using a character array (watch out for the nasty empty String or null String argument!)

Another solution uses StringBuilder (which is usually used to do String manupilation since String itself is immutable.

<pre><code>public String frontBack(String str) {
 if (str == null || str.length() == 0) {
 return str;
 }
 StringBuilder sb = new StringBuilder(str); 
 char first = sb.charAt(0);
 sb.setCharAt(0, sb.charAt(sb.length()-1));
 sb.setCharAt(sb.length()-1, first);
 return sb.toString();
}
</code></pre>

Yet another approach (more for instruction than actual use) is this one:

<pre><code>public String frontBack(String str) {
 if (str == null || str.length() &lt; 2) {
 return str;
 }
 StringBuilder sb = new StringBuilder(str);
 String sub = sb.substring(1, sb.length() -1);
 return sb.reverse().replace(1, sb.length() -1, sub).toString();
}
</code></pre>

Here the complete string is reversed and then the part that should not be reversed is replaced with the substring. ;)

blocks|key|767621|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|767622|if+(s.charAt(0)+==+s.charAt(s.length()+-+1))|code-block|syntax|javascript|767623|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try this:

<pre><code>if (s.charAt(0) == s.charAt(s.length() - 1))
</code></pre>

blocks|key|983409|text|下面是一个使用String.charAt()的方法|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|983410|String+str+=+"India";
System.out.println("last+char+=+"+%2B+str.charAt(str.length()+-+1));|code-block|syntax|javascript|983411|结果输出为last+char+=+a。|983412|entityMap^0|7|F|0|0|5|D|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|N|$]]

Here is a method using <code>String.charAt()</code>:

<pre><code>String str = "India";
System.out.println("last char = " + str.charAt(str.length() - 1));
</code></pre>

The resulting output is <code>last char = a</code>.

blocks|key|768356|text|public+String+lastChars(String+a)+{
if(a.length()>=1{
String+str1+=a.substring(b.length()-1);
}
return+str1;
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|768357|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>public String lastChars(String a) {
if(a.length()&gt;=1{
String str1 =a.substring(b.length()-1);
}
return str1;
}
</code></pre>

blocks|key|983442|text|public+char+LastChar(String+a){
++++return+a.charAt(a.length()+-+1);
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|983443|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>public char LastChar(String a){
 return a.charAt(a.length() - 1);
}
</code></pre>

blocks|key|983445|text|String+aString+=+"This+will+return+the+letter+t";
System.out.println(aString.charAt(aString.length()+-+1));|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|983446|输出应为：|unstyled|983447|t|983448|祝你编码愉快！|983449|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$B|C]]|$1|I|3|J|5|F|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>String aString = "This will return the letter t";
System.out.println(aString.charAt(aString.length() - 1));
</code></pre>

Output should be:

<pre><code>t
</code></pre>

Happy coding!

blocks|key|768440|text|其他答案非常完整，如果您正在尝试查找字符串的最后一个字符，则绝对应该使用它们。但是如果你只是想使用一个条件(例如最后一个字符'g')，你也可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|768441|if+(str.endsWith("g"))+{|code-block|syntax|javascript|768442|或者，字符串|768443|if+(str.endsWith("bar"))+{|768444|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

The other answers are very complete, and you should definitely use them if you're trying to find the last character of a string. But if you're just trying to use a conditional (e.g. is the last character 'g'), you could also do the following:

<pre><code>if (str.endsWith("g")) {
</code></pre>

or, strings

<pre><code>if (str.endsWith("bar")) {
</code></pre>

blocks|key|768451|text|+public+char+lastChar(String+s)+{
+++++if+(s+==+""+%7C%7C+s+==+null)
++++++++return+'+';
++++char+lc+=+s.charAt(s.length()+-+1);
++++return+lc;
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|768452|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code> public char lastChar(String s) {
 if (s == "" || s == null)
 return ' ';
 char lc = s.charAt(s.length() - 1);
 return lc;
}
</code></pre>

blocks|key|983538|text|下面是我用来获取字符串最后第n个字符的方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|983539|public+static+String+takeLast(String+value,+int+count)+{
++++if+(value+==+null+%7C%7C+value.trim().length()+==+0)+return+"";
++++if+(count+<+1)+return+"";

++++if+(value.length()+>+count)+{
++++++++return+value.substring(value.length()+-+count);
++++}+else+{
++++++++return+value;
++++}
}|code-block|syntax|javascript|983540|然后像这样使用它：|983541|String+testStr+=+"this+is+a+test+string";
String+last1+=+takeLast(testStr,+1);+//Output:+g
String+last4+=+takeLast(testStr,+4);+//Output:+ring|983542|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Here is a method I use to get the last nth characters of a string:
<pre><code>public static String takeLast(String value, int count) {
 if (value == null || value.trim().length() == 0) return &quot;&quot;;
 if (count &lt; 1) return &quot;&quot;;

 if (value.length() &gt; count) {
 return value.substring(value.length() - count);
 } else {
 return value;
 }
}
</code></pre>
Then use it like so:
<pre><code>String testStr = &quot;this is a test string&quot;;
String last1 = takeLast(testStr, 1); //Output: g
String last4 = takeLast(testStr, 4); //Output: ring
</code></pre>

How do I get the last character of a string?
<pre><code>public class Main {
 public static void main(String[] args) {
 String s = &quot;test string&quot;;
 //char lastChar = ???
 } 
}
</code></pre>

How do I get the last character of a string?

如何获取字符串的最后一个字符？public class Main {    public static void main(String[] args)  {        String s = "test string";        //char lastChar = ???    }   }

问如何获取字符串的最后一个字符？
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