blocks|key|508389|text|您可以通过键入?rm找到答案|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|508390|rm(data_1,+data_2,+data_3)|code-block|syntax|javascript|508391|entityMap^0|7|3|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

You'll find the answer by typing <code>?rm</code>

<pre><code>rm(data_1, data_2, data_3)
</code></pre>

blocks|key|292128|text|删除一组命名相似对象的一种有用方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|292129|rm(list+=+ls()[grep("%5Etmp",+ls())])|code-block|syntax|javascript|292130|从而移除名称以字符串"tmp“开头的所有对象。|292131|编辑:遵循use的评论，使用pattern参数：|offset|length|style|CODE|292132|rm(list+=+ls(pattern+=+"%5Etmp"))|292133|编辑:在回答Rafael的评论时，只保留对象子集的一种方法是使用特定模式命名要保留的数据。例如，如果要删除名称不是以paper开头的所有对象，可以发出以下命令：|292134|rm(list+=+grep("%5Epaper",+ls(),+value+=+TRUE,+invert+=+TRUE))|292135|entityMap^0|0|0|0|E|7|0|0|1M|5|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|Z|8|@$K|10|L|11|M|N]]|9|@]|A|$]]|$1|O|3|P|5|D|7|12|8|@]|9|@]|A|$E|F]]|$1|Q|3|R|5|6|7|13|8|@$K|14|L|15|M|N]]|9|@]|A|$]]|$1|S|3|T|5|D|7|16|8|@]|9|@]|A|$E|F]]|$1|U|3|-4|5|6|7|17|8|@]|9|@]|A|$]]]|V|$]]

A useful way to remove a whole set of named-alike objects:

<pre><code>rm(list = ls()[grep("^tmp", ls())])
</code></pre>

thereby removing all objects whose name begins with the string "tmp".

Edit: Following Gsee's comment, making use of the <code>pattern</code> argument:

<pre><code>rm(list = ls(pattern = "^tmp"))
</code></pre>

Edit: Answering Rafael comment, one way to retain only a subset of objects is to name the data you want to retain with a specific pattern. For example if you wanted to remove all objects whose name do not start with <code>paper</code> you would issue the following command:

<pre><code>rm(list = grep("^paper", ls(), value = TRUE, invert = TRUE))
</code></pre>

blocks|key|292234|text|下面的命令就可以了|type|unstyled|depth|inlineStyleRanges|entityRanges|data|292235|rm(list=ls(all=TRUE))|code-block|syntax|javascript|292236|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Following command will do

<pre><code>rm(list=ls(all=TRUE))
</code></pre>

blocks|key|508588|text|使用以下命令|type|unstyled|depth|inlineStyleRanges|entityRanges|data|508589|remove(list=c("data_1",+"data_2",+"data_3"))|code-block|syntax|javascript|508590|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Use the following command

<pre><code>remove(list=c("data_1", "data_2", "data_3"))
</code></pre>

blocks|key|292362|text|可以使用apropos函数，该函数用于查找使用部分名称的对象。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|292363|rm(list+=+apropos("data_"))|code-block|syntax|javascript|292364|entityMap^0|4|7|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

You can use the <code>apropos</code> function which is used to find the objects using partial name.

<pre><code>rm(list = apropos("data_"))
</code></pre>

blocks|key|292304|text|如果您只想删除一组变量中的一个，那么您可以创建一个列表并只保留您需要的变量。rm函数可用于删除除"data“之外的所有变量。下面是脚本：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|292305|0->data
1->data_1
2->data_2
3->data_3
#check+variables+in+workspace
ls()
rm(list=setdiff(ls(),+"data"))
#check+remaining+variables+in+workspace+after+deletion
ls()

#note:+if+you+just+use+rm(list)+then+R+will+attempt+to+remove+the+"list"+variable.+
list=setdiff(ls(),+"data")
rm(list)
ls()|code-block|syntax|javascript|292306|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you just want to remove one of a group of variables, then you can create a list and keep just the variable you need. The rm function can be used to remove all the variables apart from "data". Here is the script:

<pre><code>0-&gt;data
1-&gt;data_1
2-&gt;data_2
3-&gt;data_3
#check variables in workspace
ls()
rm(list=setdiff(ls(), "data"))
#check remaining variables in workspace after deletion
ls()

#note: if you just use rm(list) then R will attempt to remove the "list" variable. 
list=setdiff(ls(), "data")
rm(list)
ls()
</code></pre>

blocks|key|292258|text|paste0("data_",seq(1,3,1))+
#+makes+multiple+data.frame+names+with+sequential+number
rm(list=paste0("data_",seq(1,3,1))
#+above+code+removes+data_1~data_3|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|292259|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>paste0("data_",seq(1,3,1)) 
# makes multiple data.frame names with sequential number
rm(list=paste0("data_",seq(1,3,1))
# above code removes data_1~data_3
</code></pre>

blocks|key|292184|text|要清除所有数据，请执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|292185|单击Misc>Remove+all+objects。|offset|length|style|CODE|292186|你可以走了。|292187|要清除控制台，请执行以下操作：|292188|单击edit>Clear+console。|292189|不需要任何代码。|292190|entityMap^0|0|2|N|0|0|0|2|I|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|S|8|@$D|T|E|U|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|V|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|W|8|@]|9|@]|A|$]]|$1|L|3|M|5|6|7|X|8|@$D|Y|E|Z|F|G]]|9|@]|A|$]]|$1|N|3|O|5|6|7|10|8|@]|9|@]|A|$]]|$1|P|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|Q|$]]

To clear all data:

click on <code>Misc&gt;Remove all objects</code>. 

Your good to go. 

To clear the console: 

click on <code>edit&gt;Clear console</code>. 

No need for any code.

blocks|key|292471|text|您还可以使用tidyverse|type|unstyled|depth|inlineStyleRanges|entityRanges|data|292472|#+to+remove+specific+objects(s)
rm(list+=+ls()+%25>%25+str_subset("xxx"))+
#+or+to+keep+specific+object(s)
rm(list+=+setdiff(ls(),+ls()+%25>%25+str_subset("xxx")))|code-block|syntax|javascript|292473|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can also use tidyverse
<pre><code># to remove specific objects(s)
rm(list = ls() %&gt;% str_subset(&quot;xxx&quot;)) 
# or to keep specific object(s)
rm(list = setdiff(ls(), ls() %&gt;% str_subset(&quot;xxx&quot;)))
</code></pre>

blocks|key|292517|text|添加另一种方法，使用ls()和remove()|type|unstyled|depth|inlineStyleRanges|entityRanges|data|292518|ls()返回一个字符串矢量，给出指定环境中对象的名称。|292519|使用ls()创建要从环境中删除的对象列表，然后使用remove()删除它。|292520|remove(list+=+ls()[ls()+!=++"data"])|code-block|syntax|javascript|292521|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|O|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|P|8|@]|9|@]|A|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Adding one more way, using ls() and remove()
ls() return a vector of character strings giving the names of the objects in the specified environment.
Create a list of objects you want to remove from the environment using ls() and then use remove() to remove it.
<pre><code>remove(list = ls()[ls() != &quot;data&quot;])
</code></pre>

I would like to remove some data from the workspace. I know the "Clear All" button will remove all data. However, I would like to remove just certain data.

For example, I have these data frames in the data section:

<pre><code>data
data_1
data_2
data_3
</code></pre>

I would like to remove <code>data_1</code>, <code>data_2</code> and <code>data_3</code>, while keeping <code>data</code>.

I tried <code>data_1 &lt;- data_2 &lt;- data_3 &lt;- NULL</code>, which does remove the data (I think), but still keeps it in the workspace area, so it is not fully what I would like to do.

How do I clear only a few specific objects from the workspace?

我想从工作区中删除一些数据。我知道"Clear All“按钮将删除所有数据。但是，我只想删除某些数据。例如，我在数据部分中有以下数据框：datadata_1data_2data_3我想删除data_1、data_2和data_3，同时保留data。我尝试了data_1 <- data_2 <- data_3 <- NULL，它确实删除了数据(我想)，但仍然将其保留在工作区中，所以它并不完全是我想要

问如何从工作区中仅清除几个特定对象？
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