使用JAXB的具有属性和内容的XML元素
使用JAXB的具有属性和内容的XML元素
提问于 2011-04-01 22:27:32
如何使用JAXB生成以下XML？
<sport type="" gender="">
sport description
</sport>回答 3
Stack Overflow用户
发布于 2012-09-24 17:28:53
正确的方案应该是：
<?xml version="1.0" encoding="UTF-8"?>
<schema xmlns="http://www.w3.org/2001/XMLSchema"
targetNamespace="http://www.example.org/Sport"
xmlns:tns="http://www.example.org/Sport"
elementFormDefault="qualified"
xmlns:jaxb="http://java.sun.com/xml/ns/jaxb"
jaxb:version="2.0">
<complexType name="sportType">
<simpleContent>
<extension base="string">
<attribute name="type" type="string" />
<attribute name="gender" type="string" />
</extension>
</simpleContent>
</complexType>
<element name="sports">
<complexType>
<sequence>
<element name="sport" minOccurs="0" maxOccurs="unbounded"
type="tns:sportType" />
</sequence>
</complexType>
</element>为SportType生成的代码为：
package org.example.sport;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlType;
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "sportType")
public class SportType {
@XmlValue
protected String value;
@XmlAttribute
protected String type;
@XmlAttribute
protected String gender;
public String getValue() {
return value;
}
public void setValue(String value) {
this.value = value;
}
public String getType() {
return type;
}
public void setType(String value) {
this.type = value;
}
public String getGender() {
return gender;
}
public void setGender(String value) {
this.gender = value;
}
}Stack Overflow用户
发布于 2015-06-14 04:03:24
以下是可行的解决方案：
输出：
public class XmlTest {
private static final Logger log = LoggerFactory.getLogger(XmlTest.class);
@Test
public void createDefaultBook() throws JAXBException {
JAXBContext jaxbContext = JAXBContext.newInstance(Book.class);
Marshaller marshaller = jaxbContext.createMarshaller();
StringWriter writer = new StringWriter();
marshaller.marshal(new Book(), writer);
log.debug("Book xml:\n {}", writer.toString());
}
@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement(name = "book")
public static class Book {
@XmlElementRef(name = "price")
private Price price = new Price();
}
@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement(name = "price")
public static class Price {
@XmlAttribute(name = "drawable")
private Boolean drawable = true; //you may want to set default value here
@XmlValue
private int priceValue = 1234;
public Boolean getDrawable() {
return drawable;
}
public void setDrawable(Boolean drawable) {
this.drawable = drawable;
}
public int getPriceValue() {
return priceValue;
}
public void setPriceValue(int priceValue) {
this.priceValue = priceValue;
}
}
}输出：
22:00:18.471 main DEBUG com.grebski.stack.XmlTest - Book xml：
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<book>
<price drawable="true">1234</price>
</book>Stack Overflow用户
发布于 2011-04-01 22:30:49
更新的解决方案-使用我们正在讨论的模式解决方案。这将带您找到答案：
示例架构：
<?xml version="1.0" encoding="UTF-8"?>
<schema xmlns="http://www.w3.org/2001/XMLSchema"
targetNamespace="http://www.example.org/Sport"
xmlns:tns="http://www.example.org/Sport"
elementFormDefault="qualified"
xmlns:jaxb="http://java.sun.com/xml/ns/jaxb"
jaxb:version="2.0">
<complexType name="sportType">
<attribute name="type" type="string" />
<attribute name="gender" type="string" />
</complexType>
<element name="sports">
<complexType>
<sequence>
<element name="sport" minOccurs="0" maxOccurs="unbounded"
type="tns:sportType" />
</sequence>
</complexType>
</element>
生成的代码
SportType：
package org.example.sport;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlType;
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "sportType")
public class SportType {
@XmlAttribute
protected String type;
@XmlAttribute
protected String gender;
public String getType() {
return type;
}
public void setType(String value) {
this.type = value;
}
public String getGender() {
return gender;
}
public void setGender(String value) {
this.gender = value;
}
}体育：
package org.example.sport;
import java.util.ArrayList;
import java.util.List;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlType;
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "", propOrder = {
"sport"
})
@XmlRootElement(name = "sports")
public class Sports {
protected List<SportType> sport;
public List<SportType> getSport() {
if (sport == null) {
sport = new ArrayList<SportType>();
}
return this.sport;
}
}输出类文件是通过在命令行上对架构运行xjc来生成的
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原文链接：
https://stackoverflow.com/questions/5514752
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