blocks|key|275443|text|将file_get_contents与json_decode和echo结合使用。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|275444|entityMap^0|1|H|J|B|V|4|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]|$9|M|A|N|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|O|8|@]|D|@]|E|$]]]|G|$]]

Use <code>file_get_contents</code> in combination with <code>json_decode</code> and <code>echo</code>.

blocks|key|271872|text|根据您的PHP配置，这可能很容易使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|271873|$jsonData+=+json_decode(file_get_contents('https://chart.googleapis.com/chart?cht=p3&chs=250x100&chd=t:60,40&chl=Hello%7CWorld&chof=json'));|code-block|syntax|javascript|271874|但是，如果您的系统上没有启用allow_url_fopen，您可以通过CURL读取数据，如下所示：|offset|length|style|CODE|271875|<?php
++++$curlSession+=+curl_init();
++++curl_setopt($curlSession,+CURLOPT_URL,+'https://chart.googleapis.com/chart?cht=p3&chs=250x100&chd=t:60,40&chl=Hello%7CWorld&chof=json');
++++curl_setopt($curlSession,+CURLOPT_BINARYTRANSFER,+true);
++++curl_setopt($curlSession,+CURLOPT_RETURNTRANSFER,+true);

++++$jsonData+=+json_decode(curl_exec($curlSession));
++++curl_close($curlSession);
?>|271876|顺便说一句，如果您只需要原始的JSON数据，那么只需删除json_decode即可。|271877|entityMap^0|0|0|E|F|0|0|S|B|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|Y|8|@$I|Z|J|10|K|L]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|R|$]]

Depending on your PHP configuration, this may be a easy as using:

<pre><code>$jsonData = json_decode(file_get_contents('https://chart.googleapis.com/chart?cht=p3&amp;chs=250x100&amp;chd=t:60,40&amp;chl=Hello|World&amp;chof=json'));
</code></pre>

However, if <code>allow_url_fopen</code> isn't enabled on your system, you could read the data via CURL as follows:

<pre><code>&lt;?php
 $curlSession = curl_init();
 curl_setopt($curlSession, CURLOPT_URL, 'https://chart.googleapis.com/chart?cht=p3&amp;chs=250x100&amp;chd=t:60,40&amp;chl=Hello|World&amp;chof=json');
 curl_setopt($curlSession, CURLOPT_BINARYTRANSFER, true);
 curl_setopt($curlSession, CURLOPT_RETURNTRANSFER, true);

 $jsonData = json_decode(curl_exec($curlSession));
 curl_close($curlSession);
?&gt;
</code></pre>

Incidentally, if you just want the raw JSON data, then simply remove the <code>json_decode</code>.

blocks|key|275475|text|$url+=+"https://chart.googleapis....";
$json+=+file_get_contents($url);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|275476|现在，如果您只想显示输出，您可以回显$json变量，也可以对其进行解码，并对其执行某些操作，如下所示：|unstyled|275477|$data+=+json_decode($json);
var_dump($data);|275478|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>$url = "https://chart.googleapis....";
$json = file_get_contents($url);
</code></pre>

Now you can either echo the $json variable, if you just want to display the output, or you can decode it, and do something with it, like so:

<pre><code>$data = json_decode($json);
var_dump($data);
</code></pre>

blocks|key|271909|text|别忘了:要获取HTTPS内容，应该在php.ini中启用OPENSSL扩展。(how+to+get+contents+of+site+use+HTTPS)|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|271910|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/2880169/how-to-get-contents-of-site-use-https^0|13|11|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

Don't forget: to get HTTPS contents, your OPENSSL extension should be enabled in your php.ini. (<a href="https://stackoverflow.com/questions/2880169/how-to-get-contents-of-site-use-https">how to get contents of site use HTTPS</a>)

blocks|key|3190898|text|1)+局部最简单方法|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|3190899|<?php
echo+readfile("http://example.com/");+++//needs+"Allow_url_include"+enabled
//OR
echo+include("http://example.com/");++++//needs+"Allow_url_include"+enabled
//OR
echo+file_get_contents("http://example.com/");
//OR
echo+stream_get_contents(fopen('http://example.com/',+"rb"));+//you+may+use+"r"+instead+of+"rb"++//needs+"Allow_url_fopen"+enabled
?>+|code-block|syntax|javascript|3190900|2)更好的方式是CURL|3190901|echo+get_remote_data('http://example.com');+//+GET+request+
echo+get_remote_data('http://example.com',+"var2=something&var3=blabla"+);+//+POST+request|3190902|它会自动处理FOLLOWLOCATION问题%2B远程urls：|3190903|src="./imageblabla.png"变成了：|CODE|3190904|src="http://example.com/path/imageblabla.png"|3190905|代码：https://github.com/tazotodua/useful-php-scripts/blob/master/get-remote-url-content-data.php|3190906|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/tazotodua/useful-php-scripts/blob/master/get-remote-url-content-data.php^0|3|7|0|0|5|7|0|0|6|E|0|0|N|0|0|19|0|3|2J|0|0^^$0|@$1|2|3|4|5|6|7|15|8|@$9|16|A|17|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|18|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|19|8|@$9|1A|A|1B|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|1C|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|1D|8|@$9|1E|A|1F|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|6|7|1G|8|@$9|1H|A|1I|B|S]]|D|@]|E|$]]|$1|T|3|U|5|6|7|1J|8|@$9|1K|A|1L|B|S]]|D|@]|E|$]]|$1|V|3|W|5|6|7|1M|8|@]|D|@$9|1N|A|1O|1|1P]]|E|$]]|$1|X|3|-4|5|6|7|1Q|8|@]|D|@]|E|$]]]|Y|$Z|$5|10|11|12|E|$13|14]]]]

1) local simplest methods

<pre><code>&lt;?php
echo readfile("http://example.com/"); //needs "Allow_url_include" enabled
//OR
echo include("http://example.com/"); //needs "Allow_url_include" enabled
//OR
echo file_get_contents("http://example.com/");
//OR
echo stream_get_contents(fopen('http://example.com/', "rb")); //you may use "r" instead of "rb" //needs "Allow_url_fopen" enabled
?&gt; 
</code></pre>

2) Better Way is CURL:

<pre><code>echo get_remote_data('http://example.com'); // GET request 
echo get_remote_data('http://example.com', "var2=something&amp;var3=blabla" ); // POST request
</code></pre>

It automatically handles FOLLOWLOCATION problem + Remote urls: <code>src="./imageblabla.png"</code> turned into: <code>src="http://example.com/path/imageblabla.png"</code>

Code : <a href="https://github.com/tazotodua/useful-php-scripts/blob/master/get-remote-url-content-data.php" rel="noreferrer">https://github.com/tazotodua/useful-php-scripts/blob/master/get-remote-url-content-data.php</a>

When I use following URL in browser then it prompt me to download a text file with JSOn content.

<a href="https://chart.googleapis.com/chart?cht=p3&amp;chs=250x100&amp;chd=t:60,40&amp;chl=Hello|World&amp;chof=json">https://chart.googleapis.com/chart?cht=p3&amp;chs=250x100&amp;chd=t:60,40&amp;chl=Hello|World&amp;chof=json</a>

(Click above URL see downloaded file content)

Now I want to create a php page. I want that when I call this php page, it should call above URL and get content(json format) from file and show it on screen.

How can I do this ??

Get file content from URL?

JSON

当我在浏览器中使用下面的网址时，它会提示我下载一个包含JSOn内容的文本文件。(单击上面的URL查看下载的文件内容)现在我想创建一个php页面。我希望当我调用这个php页面时，它应该调用上面的URL，并从文件中获取内容(json格式)并将其显示在屏幕上。我该怎么做呢?？

问是否从URL获取文件内容？
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问是否从URL获取文件内容？
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