Android-创建JSON数组和JSON对象
Android-创建JSON数组和JSON对象
提问于 2013-07-23 20:19:50
如何在Android中创建这种格式的JSON :因为我将要传递的API将解析JsonArray，然后解析对象。或者只要传递一个json对象就可以了吗？因为我只需要在每个服务调用中插入1个事务。
{
"student": [
{
"id": 1,
"name": "John Doe",
"year": "1st",
"curriculum": "Arts",
"birthday": 3/3/1995
},
{
"id": 2,
"name": "Michael West",
"year": "2nd",
"curriculum": "Economic",
"birthday": 4/4/1994
}
]
}我只知道JSONObject。就像这张。
JSONObject obj = new JSONObject();
try {
obj.put("id", "3");
obj.put("name", "NAME OF STUDENT");
obj.put("year", "3rd");
obj.put("curriculum", "Arts");
obj.put("birthday", "5/5/1993");
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}任何想法。谢谢
回答 9
Stack Overflow用户
回答已采纳
发布于 2013-07-23 20:31:13
使用以下代码：
JSONObject student1 = new JSONObject();
try {
student1.put("id", "3");
student1.put("name", "NAME OF STUDENT");
student1.put("year", "3rd");
student1.put("curriculum", "Arts");
student1.put("birthday", "5/5/1993");
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
JSONObject student2 = new JSONObject();
try {
student2.put("id", "2");
student2.put("name", "NAME OF STUDENT2");
student2.put("year", "4rd");
student2.put("curriculum", "scicence");
student2.put("birthday", "5/5/1993");
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
JSONArray jsonArray = new JSONArray();
jsonArray.put(student1);
jsonArray.put(student2);
JSONObject studentsObj = new JSONObject();
studentsObj.put("Students", jsonArray);
String jsonStr = studentsObj.toString();
System.out.println("jsonString: "+jsonStr);Stack Overflow用户
发布于 2013-11-22 17:24:01
public JSONObject makJsonObject(int id[], String name[], String year[],
String curriculum[], String birthday[], int numberof_students)
throws JSONException {
JSONObject obj = null;
JSONArray jsonArray = new JSONArray();
for (int i = 0; i < numberof_students; i++) {
obj = new JSONObject();
try {
obj.put("id", id[i]);
obj.put("name", name[i]);
obj.put("year", year[i]);
obj.put("curriculum", curriculum[i]);
obj.put("birthday", birthday[i]);
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
jsonArray.put(obj);
}
JSONObject finalobject = new JSONObject();
finalobject.put("student", jsonArray);
return finalobject;
}Stack Overflow用户
发布于 2013-07-23 20:30:48
JSONObject obj = new JSONObject();
try {
obj.put("id", "3");
obj.put("name", "NAME OF STUDENT");
obj.put("year", "3rd");
obj.put("curriculum", "Arts");
obj.put("birthday", "5/5/1993");
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
JSONArray js=new JSONArray(obj.toString());
JSONObject obj2 = new JSONObject();
obj2.put("student", js.toString());页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/17810044
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