blocks|key|1719327|text|As+per+the+documentation，则需要c关键字参数而不是color。(我同意这有点令人困惑，但在这种情况下，"c“和"s”术语是从matlab继承的。)|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1719328|例如。|1719329|import+numpy+as+np
import+matplotlib.pyplot+as+plt
import+matplotlib+as+mpl

x,+y,+colors+=+np.random.random((3,10))

fig,+ax+=+plt.subplots()
ax.scatter(x,+y,+c=colors,+s=50,+cmap=mpl.cm.Reds)

plt.show()|code-block|syntax|javascript|1719330|​|1719331|📷|atomic|1719332|1719333|entityMap|0|LINK|mutability|MUTABLE|url|http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot.scatter|1|IMAGE|IMMUTABLE|imageUrl|https://ask.qcloudimg.com/http-save/yehe-900000/5eda1281fc00f70d3e8c0fa839b2ba47.png|imageAlt^0|S|1|11|5|0|O|0|0|0|0|0|0|1|1|0|0^^$0|@$1|2|3|4|5|6|7|16|8|@$9|17|A|18|B|C]|$9|19|A|1A|B|C]]|D|@$9|1B|A|1C|1|1D]]|E|$]]|$1|F|3|G|5|6|7|1E|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|1F|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|1G|8|@]|D|@]|E|$]]|$1|O|3|P|5|Q|7|1H|8|@]|D|@$9|1I|A|1J|1|1K]]|E|$]]|$1|R|3|N|5|6|7|1L|8|@]|D|@]|E|$]]|$1|S|3|-4|5|6|7|1M|8|@]|D|@]|E|$]]]|T|$U|$5|V|W|X|E|$Y|Z]]|10|$5|11|W|12|E|$13|14|15|-4]]]]

<a href="http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot.scatter" rel="noreferrer">As per the documentation</a>, you want the <code>c</code> keyword argument instead of <code>color</code>. (I agree that this is a bit confusing, but the "c" and "s" terminology is inherited from matlab, in this case.)

E.g.

<pre><code>import numpy as np
import matplotlib.pyplot as plt
import matplotlib as mpl

x, y, colors = np.random.random((3,10))

fig, ax = plt.subplots()
ax.scatter(x, y, c=colors, s=50, cmap=mpl.cm.Reds)

plt.show()
</code></pre>

<img src="https://i.stack.imgur.com/UH7Ab.png" alt="enter image description here">

blocks|key|1719564|text|如果你真的想要这样做(你在编辑中描述的那样)，你必须从你的色彩映射表中“拉”出颜色(我已经注释了我对你的代码所做的所有更改)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1719565|import+numpy+as+np
import+matplotlib.pyplot+as+plt+

#+plt.subplots+instead+of+plt.subplot
#+create+a+figure+and+two+subplots+side+by+side,+they+share+the
#+x+and+the+y-axis
fig,+axes+=+plt.subplots(ncols=2,+sharey=True,+sharex=True)
data+=+np.random.random([10,+2])+
#+np.r_+instead+of+lists
colors+=+np.r_[np.linspace(0.1,+1,+5),+np.linspace(0.1,+1,+5)]+
mymap+=+plt.get_cmap("Reds")
#+get+the+colors+from+the+color+map
my_colors+=+mymap(colors)
#+here+you+give+floats+as+color+to+scatter+and+a+color+map
#+scatter+"translates"+this
axes[0].scatter(data[:,+0],+data[:,+1],+s=40,
++++++++++++++++c=colors,+edgecolors='None',
++++++++++++++++cmap=mymap)
for+n+in+range(5):
++++#+here+you+give+a+color+to+scatter
++++axes[1].scatter(data[n,+0],+data[n,+1],+s=40,
++++++++++++++++++++color=my_colors[n],+edgecolors='None',
++++++++++++++++++++label="point+%25d"+%25(n))
#+by+default+legend+would+show+multiple+scatterpoints+(as+you+would+normally
#+plot+multiple+points+with+scatter)
#+I+reduce+the+number+to+one+here
plt.legend(scatterpoints=1)
plt.tight_layout()
plt.show()|code-block|syntax|javascript|1719566|​|1719567|📷|atomic|offset|length|1719568|1719569|但是，如果您只想绘制10个值，并且想要为每个值命名，则应该考虑使用不同的名称，例如，此example中的条形图。另一个机会是使用带有自定义颜色周期的plt.plot，就像在这个example中一样。|style|CODE|1719570|entityMap|0|IMAGE|mutability|IMMUTABLE|imageUrl|https://ask.qcloudimg.com/http-save/yehe-900000/26bc1bc36e3794658c711bfb1aa2c9e0.png|imageAlt|1|LINK|MUTABLE|url|http://matplotlib.sourceforge.net/examples/pylab_examples/barh_demo.html|2|http://matplotlib.sourceforge.net/examples/api/color_cycle.html^0|0|0|0|0|1|0|0|0|22|8|17|7|1|2G|7|2|0^^$0|@$1|2|3|4|5|6|7|18|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|19|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|1A|8|@]|9|@]|A|$]]|$1|I|3|J|5|K|7|1B|8|@]|9|@$L|1C|M|1D|1|1E]]|A|$]]|$1|N|3|H|5|6|7|1F|8|@]|9|@]|A|$]]|$1|O|3|P|5|6|7|1G|8|@$L|1H|M|1I|Q|R]]|9|@$L|1J|M|1K|1|1L]|$L|1M|M|1N|1|1O]]|A|$]]|$1|S|3|-4|5|6|7|1P|8|@]|9|@]|A|$]]]|T|$U|$5|V|W|X|A|$Y|Z|10|-4]]|11|$5|12|W|13|A|$14|15]]|16|$5|12|W|13|A|$14|17]]]]

If you really want to do this (what you describe in your edit), you have to "pull" the colors from your colormap (I have commented all changes I made to your code):

<pre><code>import numpy as np
import matplotlib.pyplot as plt 

# plt.subplots instead of plt.subplot
# create a figure and two subplots side by side, they share the
# x and the y-axis
fig, axes = plt.subplots(ncols=2, sharey=True, sharex=True)
data = np.random.random([10, 2]) 
# np.r_ instead of lists
colors = np.r_[np.linspace(0.1, 1, 5), np.linspace(0.1, 1, 5)] 
mymap = plt.get_cmap("Reds")
# get the colors from the color map
my_colors = mymap(colors)
# here you give floats as color to scatter and a color map
# scatter "translates" this
axes[0].scatter(data[:, 0], data[:, 1], s=40,
 c=colors, edgecolors='None',
 cmap=mymap)
for n in range(5):
 # here you give a color to scatter
 axes[1].scatter(data[n, 0], data[n, 1], s=40,
 color=my_colors[n], edgecolors='None',
 label="point %d" %(n))
# by default legend would show multiple scatterpoints (as you would normally
# plot multiple points with scatter)
# I reduce the number to one here
plt.legend(scatterpoints=1)
plt.tight_layout()
plt.show()
</code></pre>

<img src="https://i.stack.imgur.com/OyOoe.png" alt="colored-scatter">

However, if you only want to plot 10 values and want to name every single one,
you should consider using something different, for instance a bar chart as in this
<a href="http://matplotlib.sourceforge.net/examples/pylab_examples/barh_demo.html" rel="noreferrer">example</a>. Another opportunity would be to use <code>plt.plot</code> with a custom color cycle, like in this <a href="http://matplotlib.sourceforge.net/examples/api/color_cycle.html" rel="noreferrer">example</a>.

blocks|key|1933262|text|这样如何：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1933263|import+matplotlib.pyplot+as+plt
import+numpy+as+np


reds+=+plt.get_cmap("Reds")
x+=+np.linspace(0,+10,+10)
y+=+np.log(x)

#+color+by+value+given+a+cmap
plt.subplot(121)
plt.scatter(x,+y,+c=x,+s=100,+cmap=reds)


#+color+by+value,+and+add+a+legend+for+each
plt.subplot(122)
norm+=+plt.normalize()
norm.autoscale(x)
for+i,+(x_val,+y_val)+in+enumerate(zip(x,+y)):
++++plt.plot(x_val,+y_val,+'o',+markersize=10,+
+++++++++++++color=reds(norm(x_val)),
+++++++++++++label='Point+%25s'+%25+i
+++++++++++++)
plt.legend(numpoints=1,+loc='lower+right')

plt.show()|code-block|syntax|javascript|1933264|​|1933265|📷|atomic|offset|length|1933266|1933267|代码应该是完全不言自明的，但如果你想让我复习任何东西，请大声说出来。|1933268|entityMap|0|IMAGE|mutability|IMMUTABLE|imageUrl|https://ask.qcloudimg.com/http-save/yehe-900000/62210b87fe16f8e5dce281bec189c7c0.png|imageAlt^0|0|0|0|0|1|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Z|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|10|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|11|8|@]|9|@]|A|$]]|$1|I|3|J|5|K|7|12|8|@]|9|@$L|13|M|14|1|15]]|A|$]]|$1|N|3|H|5|6|7|16|8|@]|9|@]|A|$]]|$1|O|3|P|5|6|7|17|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|18|8|@]|9|@]|A|$]]]|R|$S|$5|T|U|V|A|$W|X|Y|-4]]]]

How about:

<pre><code>import matplotlib.pyplot as plt
import numpy as np


reds = plt.get_cmap("Reds")
x = np.linspace(0, 10, 10)
y = np.log(x)

# color by value given a cmap
plt.subplot(121)
plt.scatter(x, y, c=x, s=100, cmap=reds)


# color by value, and add a legend for each
plt.subplot(122)
norm = plt.normalize()
norm.autoscale(x)
for i, (x_val, y_val) in enumerate(zip(x, y)):
 plt.plot(x_val, y_val, 'o', markersize=10, 
 color=reds(norm(x_val)),
 label='Point %s' % i
 )
plt.legend(numpoints=1, loc='lower right')

plt.show()
</code></pre>

<img src="https://i.stack.imgur.com/3Kd76.png" alt="code output">

The code should all be fairly self explanatory, but if you want me to go over anything, just shout.

I'm trying to shade points in a scatter plot based on a set of values (from 0 to 1) picked from one of the already defined color maps, like Blues or Reds. I tried this:

<pre><code>import matplotlib
import matplotlib.pyplot as plt
from numpy import *
from scipy import *
fig = plt.figure()
mymap = plt.get_cmap("Reds")
x = [8.4808517662594909, 11.749082788323497, 5.9075039082855652, 3.6156231827873615, 12.536817102137768, 11.749082788323497, 5.9075039082855652, 3.6156231827873615, 12.536817102137768]
spaced_colors = linspace(0, 1, 10)
print spaced_colors
plt.scatter(x, x,
 color=spaced_colors,
 cmap=mymap)
# this does not work either
plt.scatter(x, x,
 color=spaced_colors,
 cmap=plt.get_cmap("gray"))
</code></pre>

But it does not work, using either the Reds or gray color map. How can this be done?

edit: if I want to plot each point separately so it can have a separate legend, how can I do it? I tried:

<pre><code>fig = plt.figure()
mymap = plt.get_cmap("Reds")
data = np.random.random([10, 2])
colors = list(linspace(0.1, 1, 5)) + list(linspace(0.1, 1, 5))
print "colors: ", colors
plt.subplot(1, 2, 1)
plt.scatter(data[:, 0], data[:, 1],
 c=colors,
 cmap=mymap)
plt.subplot(1, 2, 2)
# attempt to plot first five points in five shades of red,
# with a separate legend for each point
for n in range(5):
 plt.scatter([data[n, 0]], [data[n, 1]],
 c=[colors[n]],
 cmap=mymap,
 label="point %d" %(n))
plt.legend()
</code></pre>

but it fails. I need to make a call to scatter for each point so that it can have a separate label=, but still want each point to have a different shade of the color map as its color.
thanks.

how to shade points in scatter based on colormap in matplotlib?

我正在尝试根据从已经定义的颜色贴图中挑选的一组值(从0到1)对散点图中的点进行着色，比如Blues或Red。我试过这个：import matplotlibimport matplotlib.pyplot as pltfrom numpy import *from scipy import *fig = plt.figu...

问如何根据matplotlib中的颜色映射对散点进行着色？
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