blocks|key|394675|text|我会从你的布局中删除android:inputType="textPassword"。这就是当方向改变时它会切换回密码的原因。因为每次方向改变，视图都会被重新创建。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|394676|至于第一个问题，试试这个：|394677|String+text+=+password.getText();
password.setText("");
password.setInputType(InputType.TYPE_TEXT_VARIATION_PASSWORD);
password.setText(text);|code-block|syntax|javascript|394678|基本上就是在更改输入类型之前清空文本，然后再添加回来。|394679|entityMap^0|A|W|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|T|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|U|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|V|8|@]|D|@]|E|$]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

I would remove <code>android:inputType="textPassword"</code> from your layout. That is why it is switching back to password when the orientation changes. Because each time the orientation changes the view is being recreated. 

As for the first problem try this:

<pre><code>String text = password.getText();
password.setText("");
password.setInputType(InputType.TYPE_TEXT_VARIATION_PASSWORD);
password.setText(text);
</code></pre>

basically emptying out the text before you change the input type and then add it back.

blocks|key|610814|text|以编程方式向该EditText添加一个额外的属性，就完成了：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|610815|password.setInputType(InputType.TYPE_CLASS_TEXT+%7C+InputType.TYPE_TEXT_VARIATION_PASSWORD);|code-block|syntax|javascript|610816|对于数字密码(pin)：|610817|password.setInputType(InputType.TYPE_CLASS_NUMBER+%7C+InputType.TYPE_NUMBER_VARIATION_PASSWORD);|610818|此外，请确保光标位于EditText中文本的末尾，因为当您更改输入类型时，光标将自动设置为起始点。因此，我建议使用以下代码：|610819|et_password.setInputType(InputType.TYPE_CLASS_TEXT+%7C+InputType.TYPE_TEXT_VARIATION_PASSWORD);
et_password.setSelection(et_password.getText().length());|610820|在使用数据绑定时，您可以使用以下代码：|610821|<data>
++++++++<import+type="android.text.InputType"/>
.
.
.
<EditText
android:inputType='@{someViewModel.isMasked+?+
(InputType.TYPE_CLASS_TEXT+%7C+InputType.TYPE_TEXT_VARIATION_PASSWORD)+:
InputType.TYPE_CLASS_TEXT+}'|610822|如果使用Kotlin：|610823|password.inputType+=+InputType.TYPE_CLASS_TEXT+or+InputType.TYPE_TEXT_VARIATION_PASSWORD|610824|entityMap^0|7|8|0|0|0|0|A|8|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@$9|13|A|14|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|15|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|16|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|17|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|18|8|@$9|19|A|1A|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|H|7|1B|8|@]|D|@]|E|$I|J]]|$1|S|3|T|5|6|7|1C|8|@]|D|@]|E|$]]|$1|U|3|V|5|H|7|1D|8|@]|D|@]|E|$I|J]]|$1|W|3|X|5|6|7|1E|8|@]|D|@]|E|$]]|$1|Y|3|Z|5|H|7|1F|8|@]|D|@]|E|$I|J]]|$1|10|3|-4|5|6|7|1G|8|@]|D|@]|E|$]]]|11|$]]

Add an extra attribute to that <code>EditText</code> programmatically and you are done:
<pre><code>password.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);
</code></pre>
For numeric password (pin):
<pre><code>password.setInputType(InputType.TYPE_CLASS_NUMBER | InputType.TYPE_NUMBER_VARIATION_PASSWORD);
</code></pre>
Also, make sure that the cursor is at the end of the text in the <code>EditText</code> because when you change the input type the cursor will be automatically set to the starting point. So I suggest using the following code:
<pre><code>et_password.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);
et_password.setSelection(et_password.getText().length());
</code></pre>
When using Data Binding, you can make use of the following code:
<pre><code>&lt;data&gt;
 &lt;import type=&quot;android.text.InputType&quot;/&gt;
.
.
.
&lt;EditText
android:inputType='@{someViewModel.isMasked ? 
(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD) :
InputType.TYPE_CLASS_TEXT }'
</code></pre>
If using Kotlin:
<pre><code>password.inputType = InputType.TYPE_CLASS_TEXT or InputType.TYPE_TEXT_VARIATION_PASSWORD
</code></pre>

blocks|key|394746|text|这对我很有效：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|394747|mytext.setInputType(InputType.TYPE_CLASS_NUMBER);|code-block|syntax|javascript|394748|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This worked for me:

<pre><code>mytext.setInputType(InputType.TYPE_CLASS_NUMBER);
</code></pre>

blocks|key|394805|text|使用此代码将密码更改为文本，反之亦然|type|unstyled|depth|inlineStyleRanges|entityRanges|data|394806|mCbShowPwd.setOnCheckedChangeListener(new+OnCheckedChangeListener()+{

++++++++++++public+void+onCheckedChanged(CompoundButton+buttonView,+boolean+isChecked)+{
++++++++++++++++//+checkbox+status+is+changed+from+uncheck+to+checked.
++++++++++++++++if+(!isChecked)+{
++++++++++++++++++++++++//+hide+password
++++++++++++++++++++mEtPwd.setTransformationMethod(PasswordTransformationMethod.getInstance());
++++++++++++++++}+else+{
++++++++++++++++++++++++//+show+password
++++++++++++++++++++mEtPwd.setTransformationMethod(HideReturnsTransformationMethod.getInstance());
++++++++++++++++}
++++++++++++}
++++++++});|code-block|syntax|javascript|394807|有关完整的示例代码，请参阅http://www.codeproject.com/Tips/518641/Show-hide-password-in-a-edit-text-view-password-ty|offset|length|394808|entityMap|0|LINK|mutability|MUTABLE|url|http://www.codeproject.com/Tips/518641/Show-hide-password-in-a-edit-text-view-password-ty^0|0|0|D|2H|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

use this code to change password to text and vice versa 

<pre><code>mCbShowPwd.setOnCheckedChangeListener(new OnCheckedChangeListener() {

 public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
 // checkbox status is changed from uncheck to checked.
 if (!isChecked) {
 // hide password
 mEtPwd.setTransformationMethod(PasswordTransformationMethod.getInstance());
 } else {
 // show password
 mEtPwd.setTransformationMethod(HideReturnsTransformationMethod.getInstance());
 }
 }
 });
</code></pre>

for full sample code refer <a href="http://www.codeproject.com/Tips/518641/Show-hide-password-in-a-edit-text-view-password-ty" rel="noreferrer">http://www.codeproject.com/Tips/518641/Show-hide-password-in-a-edit-text-view-password-ty</a>

blocks|key|610914|text|一些动态情况holder.edit_pin.setInputType(InputType.TYPE_CLASS_NUMBER);不会工作，所以最好同时使用这两个|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|610915|holder.edit_pin.setInputType(InputType.TYPE_CLASS_NUMBER);
holder.edit_pin.setTransformationMethod(PasswordTransformationMethod.getInstance());|code-block|syntax|javascript|610916|注意:这适用于使用动态控件时，如使用arrayaapter|610917|entityMap^0|6|1M|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|N|$]]

some dynamic situation <code>holder.edit_pin.setInputType(InputType.TYPE_CLASS_NUMBER);</code> will not work so better use both like that 

<pre><code>holder.edit_pin.setInputType(InputType.TYPE_CLASS_NUMBER);
holder.edit_pin.setTransformationMethod(PasswordTransformationMethod.getInstance());
</code></pre>

Note : this is suitable for when you are using dynamic controls like using arrayaapter

blocks|key|610956|text|这是用于显示/隐藏密码的图像/按钮的完整onClick处理程序。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|610957|++++new+OnClickListener()+{
++++++++@Override
++++++++public+void+onClick(View+v)+{
++++++++++++//+current+ursor+position
++++++++++++int+cursorPosition+=+edtPassword.getSelectionStart();

++++++++++++//+toggles+the+control+variable
++++++++++++isPassworsVisible+=+!isPassworsVisible;

++++++++++++//+sets+the+image+toggler+inside+edit+text
++++++++++++passwordVisible.setImageDrawable(getResources().getDrawable(isPassworsVisible+?+R.drawable.ic_eye_checked+:+R.drawable.ic_eye_unchecked));

++++++++++++//+apply+input+type
++++++++++++edtPassword.setInputType(isPassworsVisible+?+InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD+:+InputType.TYPE_CLASS_TEXT+%7C+InputType.TYPE_TEXT_VARIATION_PASSWORD);

++++++++++++//+returns+cursor+to+position
++++++++++++edtPassword.setSelection(cursorPosition);
++++++++}
++++};|code-block|syntax|javascript|610958|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This is the full onClick handler for the Image/Button to show/hide the password.

<pre><code> new OnClickListener() {
 @Override
 public void onClick(View v) {
 // current ursor position
 int cursorPosition = edtPassword.getSelectionStart();

 // toggles the control variable
 isPassworsVisible = !isPassworsVisible;

 // sets the image toggler inside edit text
 passwordVisible.setImageDrawable(getResources().getDrawable(isPassworsVisible ? R.drawable.ic_eye_checked : R.drawable.ic_eye_unchecked));

 // apply input type
 edtPassword.setInputType(isPassworsVisible ? InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD : InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);

 // returns cursor to position
 edtPassword.setSelection(cursorPosition);
 }
 };
</code></pre>

blocks|key|610981|text|只是对@Rajkiran提供的正确答案的额外评论，您可能想要添加|type|unstyled|depth|inlineStyleRanges|entityRanges|data|610982|etPassword.setInputType(InputType.TYPE_CLASS_TEXT+%7C+InputType.TYPE_TEXT_FLAG_NO_SUGGESTIONS);|code-block|syntax|javascript|610983|设置为正常输入状态，这样用户就不会被键盘的自动提示所困扰|610984|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Just an additional comment on the correct answer provided by @Rajkiran, you may want to add

<pre><code>etPassword.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_FLAG_NO_SUGGESTIONS);
</code></pre>

to the NORMAL input state so that the users wont be annoyed by the keyboard's auto-suggestion

blocks|key|611067|text|使用此代码将密码更改为文本，反之亦然。这段代码对我来说非常好用。试试这个..。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|611068|EditText+paswrd=(EditText)view.findViewById(R.id.paswrd);

CheckBox+showpass=(CheckBox)view.findViewById(R.id.showpass);
showpass.setOnClickListener(new+OnClickListener()+{

@Override
public+void+onClick(View+v)+{
++++if(((CheckBox)v).isChecked()){
++++++++paswrd.setInputType(InputType.TYPE_CLASS_TEXT);

++++}else{
++++++++paswrd.setInputType(InputType.TYPE_CLASS_TEXT%7CInputType.TYPE_TEXT_VARIATION_PASSWORD);
++++}

}
});|code-block|syntax|javascript|611069|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Use this code to change password to text and vice versa.
This code perfectly worked for me.
Try this..

<pre><code>EditText paswrd=(EditText)view.findViewById(R.id.paswrd);

CheckBox showpass=(CheckBox)view.findViewById(R.id.showpass);
showpass.setOnClickListener(new OnClickListener() {

@Override
public void onClick(View v) {
 if(((CheckBox)v).isChecked()){
 paswrd.setInputType(InputType.TYPE_CLASS_TEXT);

 }else{
 paswrd.setInputType(InputType.TYPE_CLASS_TEXT|InputType.TYPE_TEXT_VARIATION_PASSWORD);
 }

}
});
</code></pre>

blocks|key|611092|text|如果要在密码编辑文本中应用密码可见性，请完成代码。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|611093|创建句柄任何可绘制或复选框|611094|单击或选中/取消选中时，写入以下内容：|611095|+if+(edittext.getInputType()+==+(InputType.TYPE_CLASS_TEXT+%7C
++++++++++++++++++++InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD+)){

++++++++++++++++edittext.setInputType(InputType.TYPE_CLASS_TEXT+%7C
++++++++++++++++++++++++InputType.TYPE_TEXT_VARIATION_PASSWORD+);
++++++++++++}else{
++++++++++++++++edittext.setInputType(InputType.TYPE_CLASS_TEXT+%7C
++++++++++++++++++++++++InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD+);
++++++++++++}|code-block|syntax|javascript|611096|别忘了写这一行：|611097|+edittext.setSelection(edittext.getText().length());|611098|它会将光标重置到行尾。|611099|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|U|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|V|8|@]|9|@]|A|$I|J]]|$1|K|3|L|5|6|7|W|8|@]|9|@]|A|$]]|$1|M|3|N|5|H|7|X|8|@]|9|@]|A|$I|J]]|$1|O|3|P|5|6|7|Y|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

Complete code when you want to apply the Password visibility in Password edit text.

Create a handle [ Any drawable or Checkbox]

on click or on Checked/Uncheck write this:

<pre><code> if (edittext.getInputType() == (InputType.TYPE_CLASS_TEXT |
 InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD )){

 edittext.setInputType(InputType.TYPE_CLASS_TEXT |
 InputType.TYPE_TEXT_VARIATION_PASSWORD );
 }else{
 edittext.setInputType(InputType.TYPE_CLASS_TEXT |
 InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD );
 }
</code></pre>

Do not forget to write this line:

<pre><code> edittext.setSelection(edittext.getText().length());
</code></pre>

It resets the cursor to the end of line.

blocks|key|611113|text|Checkbox.setOnCheckedChangeListener(new+OnCheckedChangeListener()+{

++++++++++++public+void+onCheckedChanged(CompoundButton+buttonView,+boolean+isChecked)+{
++++++++++++++++//+checkbox+status+is+checked.
++++++++++++++++if+(isChecked)+{
++++++++++++++++++++++++//password+is+visible
+PasswordField.setTransformationMethod(HideReturnsTransformationMethod.getInstance());+++++
++++++++++++++++}+else+{
++++++++++++++++++++++++//password+gets+hided
+++++++++++++passwordField.setTransformationMethod(PasswordTransformationMethod.getInstance());+++++++
++++++++++++++++}
++++++++++++}
++++++++});|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|611114|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>Checkbox.setOnCheckedChangeListener(new OnCheckedChangeListener() {

 public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
 // checkbox status is checked.
 if (isChecked) {
 //password is visible
 PasswordField.setTransformationMethod(HideReturnsTransformationMethod.getInstance()); 
 } else {
 //password gets hided
 passwordField.setTransformationMethod(PasswordTransformationMethod.getInstance()); 
 }
 }
 });
</code></pre>

blocks|key|395095|text|添加了密码可见性切换功能，以支持库版本24.2.0，使您无需CheckBox即可直接从EditText切换密码。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|395096|您可以通过首先将支持库版本更新到24.2.0，然后在TextInputEditText上设置inputType为password来实现这一点。下面是如何做到这一点的：|395097|<android.support.design.widget.TextInputLayout
++++++++android:layout_width="match_parent"
++++++++android:layout_height="wrap_content">

++++++++<android.support.design.widget.TextInputEditText
++++++++++++android:layout_width="match_parent"
++++++++++++android:layout_height="wrap_content"
++++++++++++android:hint="@string/password"
++++++++++++android:inputType="textPassword"/>
</android.support.design.widget.TextInputLayout>|code-block|syntax|javascript|395098|您可以在TextInputLayout的开发人员文档中获得有关该新功能的更多信息。|395099|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.android.com/reference/android/support/design/widget/TextInputLayout.html^0|U|8|17|8|0|Q|H|1A|9|0|0|4|F|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|11|8|@$9|12|A|13|B|C]|$9|14|A|15|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|16|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|17|8|@]|D|@$9|18|A|19|1|1A]]|E|$]]|$1|O|3|-4|5|6|7|1B|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]]]

The Password Visibility Toggle feature has been added to support library version 24.2.0 enabling you to toggle the password straight from the <code>EditText</code> without the need for a <code>CheckBox</code>.

You can make that work basically by first updating your support library version to 24.2.0 and then setting an <code>inputType</code> of password on the <code>TextInputEditText</code>. Here's how to do that:

<pre><code>&lt;android.support.design.widget.TextInputLayout
 android:layout_width="match_parent"
 android:layout_height="wrap_content"&gt;

 &lt;android.support.design.widget.TextInputEditText
 android:layout_width="match_parent"
 android:layout_height="wrap_content"
 android:hint="@string/password"
 android:inputType="textPassword"/&gt;
&lt;/android.support.design.widget.TextInputLayout&gt;
</code></pre>

You can get more information about the new feature on the developer documentation for <a href="https://developer.android.com/reference/android/support/design/widget/TextInputLayout.html" rel="nofollow">TextInputLayout</a>.

blocks|key|395129|text|我在寻找Visual+Studio+/+Xamarin的类似解决方案时，找到了这个帖子。下面是我使用Xamarin时的工作原理。请注意，此实现在模式之间切换时保留TYPE_TEXT_FLAG_NO_SUGGESTIONS标志。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|395130|EditText+et+=+FindViewById<EditText>(Resource.Id.ET);|395131|要显示字符，请执行以下操作：et.InputType+=+Android.Text.InputTypes.TextVariationVisiblePassword+%7C+Android.Text.InputTypes.TextFlagNoSuggestions;|395132|要隐藏字符，请执行以下操作：et.InputType+=+Android.Text.InputTypes.TextVariationPassword+%7C+Android.Text.InputTypes.ClassText;|395133|将位置设置为end：int+position+=+et.Text.Length;+et.SetSelection(position,+position);|395134|entityMap^0|29|T|0|0|1H|0|E|38|0|E|2P|0|A|U|15|10|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|V|8|@$9|W|A|X|B|C]]|D|@]|E|$]]|$1|J|3|K|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|L|3|M|5|6|7|11|8|@$9|12|A|13|B|C]|$9|14|A|15|B|C]]|D|@]|E|$]]|$1|N|3|-4|5|6|7|16|8|@]|D|@]|E|$]]]|O|$]]

My search for a similar solution for Visual Studio / Xamarin lead me to this thread. Below is what worked for me with Xamarin. Note that this implementation retains the <code>TYPE_TEXT_FLAG_NO_SUGGESTIONS</code> flag when switching between modes.

<code>EditText et = FindViewById&lt;EditText&gt;(Resource.Id.ET);</code>

To show characters:
<code>et.InputType = Android.Text.InputTypes.TextVariationVisiblePassword | Android.Text.InputTypes.TextFlagNoSuggestions;</code>

To hide characters:
<code>et.InputType = Android.Text.InputTypes.TextVariationPassword | Android.Text.InputTypes.ClassText;</code>

To set position to end:
<code>int position = et.Text.Length;</code>
<code>et.SetSelection(position, position);</code>

blocks|key|395169|text|我在checkbox上更改了输入类型，因此在我的OnCheckedChangeListener上这样做：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|395170|passwordEdit.setInputType(InputType.TYPE_CLASS_TEXT%7C+(isChecked?+InputType.TYPE_TEXT_VARIATION_PASSWORD%7C~InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD+:+InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD));|code-block|syntax|javascript|395171|它终于成功了。|395172|看起来像是TYPE_TEXT_VARIATION_VISIBLE_PASSWORD的布尔问题。颠倒这个标志，应该可以解决这个问题。|395173|在您的案例中：|395174|password.setInputType(InputType.TYPE_TEXT_VARIATION_PASSWORD%7C~InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD);|395175|entityMap^0|O|N|0|0|0|5|10|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@]|D|@]|E|$]]|$1|M|3|N|5|6|7|Z|8|@$9|10|A|11|B|C]]|D|@]|E|$]]|$1|O|3|P|5|6|7|12|8|@]|D|@]|E|$]]|$1|Q|3|R|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|S|3|-4|5|6|7|14|8|@]|D|@]|E|$]]]|T|$]]

I change the input type on my checkbox, so on my <code>OnCheckedChangeListener</code> i do:

<pre><code>passwordEdit.setInputType(InputType.TYPE_CLASS_TEXT| (isChecked? InputType.TYPE_TEXT_VARIATION_PASSWORD|~InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD : InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD));
</code></pre>

And it finally worked.

Seems like a boolean problem with <code>TYPE_TEXT_VARIATION_VISIBLE_PASSWORD</code>. Invert the flag and it should fix the problem.

In your case:

<pre><code>password.setInputType(InputType.TYPE_TEXT_VARIATION_PASSWORD|~InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD);
</code></pre>

blocks|key|395198|text|对于kotlin用户：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|395199|password.inputType+=+InputType.TYPE_CLASS_TEXT+or+InputType.TYPE_TEXT_VARIATION_PASSWORD|code-block|syntax|javascript|395200|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

For kotlin users:

<pre><code>password.inputType = InputType.TYPE_CLASS_TEXT or InputType.TYPE_TEXT_VARIATION_PASSWORD
</code></pre>

blocks|key|611265|text|基于我用Kotlin写的neeraj+t和Everton+Fernandes+Rosario的答案，其中password是布局中的EditText的id。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|611266|//+Show+passwords'+symbols.
private+fun+showPassword()+{
++++password.run+{
++++++++val+cursorPosition+=+selectionStart
++++++++transformationMethod+=+HideReturnsTransformationMethod.getInstance()
++++++++setSelection(cursorPosition)
++++}
}

//+Show+asterisks.
private+fun+hidePassword()+{
++++password.run+{
++++++++val+cursorPosition+=+selectionStart
++++++++transformationMethod+=+PasswordTransformationMethod.getInstance()
++++++++setSelection(cursorPosition)
++++}
}|code-block|syntax|javascript|611267|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/19109453/2914140|1|https://stackoverflow.com/a/28091065/2914140^0|1G|8|C|8|0|L|P|1|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@$9|X|A|Y|1|Z]|$9|10|A|11|1|12]]|E|$]]|$1|F|3|G|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|14|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]|S|$5|N|O|P|E|$Q|T]]]]

Based on answers of <a href="https://stackoverflow.com/a/19109453/2914140">neeraj t</a> and <a href="https://stackoverflow.com/a/28091065/2914140">Everton Fernandes Rosario</a> I wrote in Kotlin, where <code>password</code> is an id of an EditText in your layout.

<pre><code>// Show passwords' symbols.
private fun showPassword() {
 password.run {
 val cursorPosition = selectionStart
 transformationMethod = HideReturnsTransformationMethod.getInstance()
 setSelection(cursorPosition)
 }
}

// Show asterisks.
private fun hidePassword() {
 password.run {
 val cursorPosition = selectionStart
 transformationMethod = PasswordTransformationMethod.getInstance()
 setSelection(cursorPosition)
 }
}
</code></pre>

blocks|key|395290|text|使用转换方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|395291|要隐藏：|395292|editText.transformationMethod+=+PasswordTransformationMethod.getInstance()|code-block|syntax|javascript|395293|到可见：|395294|editText.transformationMethod+=+SingleLineTransformationMethod.getInstance()|395295|就这样。|395296|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|U|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Use Transformation method:

To Hide:

<pre><code>editText.transformationMethod = PasswordTransformationMethod.getInstance()
</code></pre>

To Visible:

<pre><code>editText.transformationMethod = SingleLineTransformationMethod.getInstance()
</code></pre>

That's it.

blocks|key|395305|text|etPost.setInputType(InputType.TYPE_TEXT_FLAG_MULTI_LINE+%7C+InputType.TYPE_TEXT_VARIATION_SHORT_MESSAGE)；|type|unstyled|depth|inlineStyleRanges|entityRanges|data|395306|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

etPost.setInputType(InputType.TYPE_TEXT_FLAG_MULTI_LINE | InputType.TYPE_TEXT_VARIATION_SHORT_MESSAGE);

In my application, I have an <code>EditText</code> whose default input type is set to <code>android:inputType=&quot;textPassword&quot;</code> by default. It has a <code>CheckBox</code> to its right, which is when checked, changes the input type of that EditText to NORMAL PLAIN TEXT. Code for that is
<pre><code>password.setInputType(InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD);
</code></pre>
My problem is, when that CheckBox is unchecked it should again set the input type to PASSWORD. I've done it using-
<pre><code>password.setInputType(InputType.TYPE_TEXT_VARIATION_PASSWORD);
</code></pre>
But, the text inside that edittext is still visible. And for surprise, when I change the orientation, it automatically sets the input type to PASSWORD and the text inside is bulleted (shown like a password).
Any way to achieve this?

Programmatically change input type of the EditText from PASSWORD to NORMAL & vice versa

Visual Studio

Android

Xamarin

Kotlin

在我的应用程序中，我有一个默认输入类型设置为android:inputType="textPassword"的EditText。它的右侧有一个CheckBox，选中后，它会将该EditText的输入类型更改为普通纯文本。其代码为password.setInputType(InputType.TYPE_TEXT_VARI...

问以编程方式将密码的输入类型从EditText更改为NORMAL，反之亦然
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问以编程方式将密码的输入类型从EditText更改为NORMAL，反之亦然EN

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问以编程方式将密码的输入类型从EditText更改为NORMAL，反之亦然
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