blocks|key|1987950|text|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1987951|$+git+show-branch+--list
++[master]+test
*+[testbranch]+test
$+git+show-branch+testbranch
[testbranch]+test
$+echo+$?
0
$+git+show-branch+nonexistantbranch
fatal:+bad+sha1+reference+nonexistantbranch
$+echo+$?
128|code-block|syntax|javascript|1987952|因此，refs？==+0将指示分支存在，并且您根本不需要深入研究refs/head/的管道。只要不将-r传递给show-branch，它将只在本地分支上运行。|offset|length|style|CODE|1987953|entityMap^0|0|0|1E|2|0^^$0|@$1|2|3|-4|4|5|6|N|7|@]|8|@]|9|$]]|$1|A|3|B|4|C|6|O|7|@]|8|@]|9|$D|E]]|$1|F|3|G|4|5|6|P|7|@$H|Q|I|R|J|K]]|8|@]|9|$]]|$1|L|3|-4|4|5|6|S|7|@]|8|@]|9|$]]]|M|$]]

I think you can use <code>git show-branch</code> here.

<pre><code>$ git show-branch --list
 [master] test
* [testbranch] test
$ git show-branch testbranch
[testbranch] test
$ echo $?
0
$ git show-branch nonexistantbranch
fatal: bad sha1 reference nonexistantbranch
$ echo $?
128
</code></pre>

So, $? == 0 would indicate that the branch exists and you don't have to dig in to the plumbing of refs/heads/ at all. As long as you don't pass <code>-r</code> to show-branch, it will only operate on local branches.

blocks|key|1774214|text|据我所知，这是在脚本中做到这一点的最佳方式。我不确定还有更多要添加的，但可能只有一个答案是“该命令可以做您想要的一切”:)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1774215|您可能需要注意的唯一一件事是分支名称中可能包含令人惊讶的字符，因此您可能希望引用<branch-name>。|offset|length|style|CODE|1774216|entityMap^0|0|14|D|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|K|8|@$D|L|E|M|F|G]]|9|@]|A|$]]|$1|H|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|I|$]]

As far as I know, that's the best way to do it in a script. I'm not sure there's much more to add to that, but there might as well be one answer that just says "That command does everything you want" :)

The only thing you might want to be careful of is that branch names can have surprising characters in them, so you may want to quote <code>&lt;branch-name&gt;</code>.

blocks|key|1774261|text|就快到了。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1774262|只需省略--verify和--quiet，如果分支存在，则得到散列，如果分支不存在，则什么也得不到。|offset|length|style|CODE|1774263|将其赋给一个变量并检查是否有空字符串。|1774264|exists=`git+show-ref+refs/heads/<branch-name>`
if+[+-n+"$exists"+];+then
++++echo+'branch+exists!'
fi|code-block|syntax|javascript|1774265|entityMap^0|0|4|8|D|7|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@$D|S|E|T|F|G]|$D|U|E|V|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|W|8|@]|9|@]|A|$]]|$1|J|3|K|5|L|7|X|8|@]|9|@]|A|$M|N]]|$1|O|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|P|$]]

Almost there.

Just leave out the <code>--verify</code> and <code>--quiet</code> and you get either the hash if the branch exists or nothing if it doesn't.

Assign it to a variable and check for an empty string.

<pre><code>exists=`git show-ref refs/heads/&lt;branch-name&gt;`
if [ -n "$exists" ]; then
 echo 'branch exists!'
fi
</code></pre>

blocks|key|1988057|text|如果您可以设法包含grep。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1988058|git+branch+%7C+grep+-q+<branch>|code-block|syntax|javascript|1988059|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you can manage to include grep.

<pre><code>git branch | grep -q &lt;branch&gt;
</code></pre>

blocks|key|1774347|text|让我们称它为git+is_localbranch+(您需要在.gitconfig中添加别名)。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1774348|用法：|1774349|$+git+is_localbranch+BRANCH|code-block|syntax|javascript|1774350|来源：|1774351|git+branch+%7C+grep+-w+$1+>+/dev/null
if+[+$?+=+0+]
then
++echo+"branch+exists"
fi|1774352|entityMap^0|6|I|U|A|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|X|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|Y|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|Z|8|@]|D|@]|E|$]]|$1|O|3|P|5|J|7|10|8|@]|D|@]|E|$K|L]]|$1|Q|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|R|$]]

Let's call it <code>git is_localbranch</code> (you need to add alias in <code>.gitconfig</code>).

Usage:

<pre><code>$ git is_localbranch BRANCH
</code></pre>

Source:

<pre><code>git branch | grep -w $1 &gt; /dev/null
if [ $? = 0 ]
then
 echo "branch exists"
fi
</code></pre>

blocks|key|1774441|text|当我在一个搜索引擎上搜索“git+check+if分支存在”时，这个页面是我看到的第一个页面。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1774442|我得到了我想要的，但我想提供一个更新的答案，因为最初的帖子是2011年的。|1774443|git+rev-parse+--verify+<branch_name>|code-block|syntax|javascript|1774444|这基本上与接受的答案相同，但您不需要键入"refs/heads/“|1774445|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|O|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

When I search for 'git check if branch exists' on a search engine, this page is the first one I see.

I get what I want, but I'd like to provide a updated answer since the original post was from 2011.

<pre><code>git rev-parse --verify &lt;branch_name&gt;
</code></pre>

This is essentially the same as the accepted answer, but you don't need type in "refs/heads/"

blocks|key|1774562|text|在windows批处理脚本上则略有不同，|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1774563|git+rev-parse+--verify+<branch>

if+%25ERRORLEVEL%25+==+0++(
++++echo+"Yes"
)+else+(
++++echo+"No"
)|code-block|syntax|javascript|1774564|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

On windows batch script it is bit different,

<pre><code>git rev-parse --verify &lt;branch&gt;

if %ERRORLEVEL% == 0 (
 echo "Yes"
) else (
 echo "No"
)
</code></pre>

blocks|key|1775029|text|要在脚本中使用，我建议使用以下命令：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1775030|git+ls-remote+--heads+<repo_url>+"<branch_name>"+%7C+wc+-l|code-block|syntax|javascript|1775031|指定本地存储库(如果位于本地存储库的目录结构中)、本地存储库的路径或远程存储库的地址。|1775032|1775033|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|M|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|N|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|O|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|P|8|@]|9|@]|A|$]]]|K|$]]

For use in a script, I recommend the following command:

<pre><code>git ls-remote --heads &lt;repo_url&gt; "&lt;branch_name&gt;" | wc -l
</code></pre>

Note that <code>&lt;repo_url&gt;</code> can just be a "." to specify the local repo if you are inside its directory structure, the path to a local repo, or the address of a remote repo. 

The command returns a 0 if the <code>&lt;branch_name&gt;</code> is not present of 1 if present.

blocks|key|1775082|text|git+branch+--list+$branch_name+%7C+grep+$branch_name|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1775083|然后检查返回值是0还是1。|unstyled|1775084|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>git branch --list $branch_name | grep $branch_name
</code></pre>

then check the return value is 0 or 1.

blocks|key|1988951|text|我对初始问题的“更新”的“建议编辑”的审查结果是“它应该写成一个评论或答案”，所以我把它贴在这里：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1988952|建议的another+way不仅将验证分支，还将验证任何具有@jhuynh名称的引用。|offset|length|1988953|git+rev-parse+--verify+<reference-name>
#+$?+==+0+means+reference+with+<reference-name>+exists.|code-block|syntax|javascript|1988954|关于初始询问的“更新”问题解释如下：|1988955|让我们假设并检查'master.000‘只是一个标签，这样的本地分支不存在，grep返回一个条目wchich是一个标签。但是，如果引用存在，rev-parse将返回0，即使这样的本地分支不存在。这是一个错误的匹配，正如@paul-s所提到的|1988956|$+git+show-ref+%7Cgrep+master.000

f0686b8c16401be87e72f9466083d29295b86f4a+refs/tags/master.000
$+git+rev-parse+--verify+master.000
f0686b8c16401be87e72f9466083d29295b86f4a
$+echo+$?
0|1988957|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/28776049/140185|1|https://stackoverflow.com/users/1442899/jhuynh|2|https://stackoverflow.com/users/1305447/paul-s^0|0|3|B|0|U|7|1|0|0|0|31|7|2|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|13|8|@]|9|@$D|14|E|15|1|16]|$D|17|E|18|1|19]]|A|$]]|$1|F|3|G|5|H|7|1A|8|@]|9|@]|A|$I|J]]|$1|K|3|L|5|6|7|1B|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|1C|8|@]|9|@$D|1D|E|1E|1|1F]]|A|$]]|$1|O|3|P|5|H|7|1G|8|@]|9|@]|A|$I|J]]|$1|Q|3|-4|5|6|7|1H|8|@]|9|@]|A|$]]]|R|$S|$5|T|U|V|A|$W|X]]|Y|$5|T|U|V|A|$W|Z]]|10|$5|T|U|V|A|$W|11]]]]

The outcome of review on my 'Suggested Edit' to the 'Update' on initial question was 'It should have been written as a comment or an answer', so I'm posting it here:

The <a href="https://stackoverflow.com/a/28776049/140185">another way</a> proposed will not only verify branches but any reference with such name <a href="https://stackoverflow.com/users/1442899/jhuynh">@jhuynh</a>. 

<pre><code>git rev-parse --verify &lt;reference-name&gt;
# $? == 0 means reference with &lt;reference-name&gt; exists.
</code></pre>

Issue with an 'Update' on initial quiestion explained:

Lets assume and check that 'master.000' is only a tag, such local branch does not exist, grep returns one entry wchich is a tag. Still rev-parse will return 0 if reference exists, even if such local branch does not exist. This is a false match, exactly as mentioned by <a href="https://stackoverflow.com/users/1305447/paul-s">@paul-s</a>

<pre><code>$ git show-ref |grep master.000

f0686b8c16401be87e72f9466083d29295b86f4a refs/tags/master.000
$ git rev-parse --verify master.000
f0686b8c16401be87e72f9466083d29295b86f4a
$ echo $?
0
</code></pre>

blocks|key|1989017|text|在脚本中使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1989018|git+show-ref+-q+--heads+<branch-name>|code-block|syntax|javascript|1989019|当且仅当<branch-name>作为本地分支存在时，它才会退出0。|offset|length|style|CODE|1989020|示例：|1989021|if+git+show-ref+-q+--heads+<branch-name>;+then
+++echo+'Branch+exists'
fi|1989022|entityMap^0|0|0|4|D|W|1|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@$I|V|J|W|K|L]|$I|X|J|Y|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|Z|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|10|8|@]|9|@]|A|$E|F]]|$1|Q|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|R|$]]

For use in a script:

<pre><code>git show-ref -q --heads &lt;branch-name&gt;
</code></pre>

This will exit <code>0</code> if and only if <code>&lt;branch-name&gt;</code> exists as a local branch.

Example:

<pre><code>if git show-ref -q --heads &lt;branch-name&gt;; then
 echo 'Branch exists'
fi
</code></pre>

blocks|key|1989093|text|git+show-ref和git+rev-parse对我的案子都不管用。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1989094|$+git+--version
git+version+2.21.0

$+git+show-branch+--list
*+[master]+mybranch+commit

$+BRANCH_NAME=mybranch
$+git+rev-parse+--verify+$BRANCH_NAME
fatal:+Needed+a+single+revision

$+git+show-ref+refs/heads/$BRANCH_NAME
<no+otput>
$+[+$?+==+0+]+&&+echo+"$BRANCH_NAME+exists"+%7C%7C+echo+"$BRANCH_NAME+not+exists"
mybranch+not+exists|code-block|syntax|javascript|1989095|我最终得到了这个|1989096|$+BRANCH_NAME=mybranch
$+SHOW_ALL=`git+show-branch+--all+%7C+grep+-w+$BRANCH_NAME`
$+[+$?+==+0+]+&&+echo+"$BRANCH_NAME+exists"+%7C%7C+echo+"$BRANCH_NAME+not+exists"
mybranch+exists|1989097|您还可以使用脚本文件执行此操作|1989098|#!/bin/sh
BRANCH_NAME=mybranch
if+grep+-Fqe+$BRANCH_NAME+<<+EOF
`git+show-branch+--all`
EOF
then
+++echo+"$BRANCH_NAME+exists"
else
+++echo+"$BRANCH_NAME+not+exists"
fi|1989099|entityMap^0|0|C|D|D|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|10|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|12|8|@]|D|@]|E|$]]|$1|Q|3|R|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|S|3|-4|5|6|7|14|8|@]|D|@]|E|$]]]|T|$]]

Neither <code>git show-ref</code> nor <code>git rev-parse</code> works on my case.
<pre class="lang-sh prettyprint-override"><code>$ git --version
git version 2.21.0

$ git show-branch --list
* [master] mybranch commit

$ BRANCH_NAME=mybranch
$ git rev-parse --verify $BRANCH_NAME
fatal: Needed a single revision

$ git show-ref refs/heads/$BRANCH_NAME
&lt;no otput&gt;
$ [ $? == 0 ] &amp;&amp; echo &quot;$BRANCH_NAME exists&quot; || echo &quot;$BRANCH_NAME not exists&quot;
mybranch not exists
</code></pre>
I ended up with this
<pre class="lang-sh prettyprint-override"><code>$ BRANCH_NAME=mybranch
$ SHOW_ALL=`git show-branch --all | grep -w $BRANCH_NAME`
$ [ $? == 0 ] &amp;&amp; echo &quot;$BRANCH_NAME exists&quot; || echo &quot;$BRANCH_NAME not exists&quot;
mybranch exists
</code></pre>
You can do also with a script file
<pre class="lang-sh prettyprint-override"><code>#!/bin/sh
BRANCH_NAME=mybranch
if grep -Fqe $BRANCH_NAME &lt;&lt; EOF
`git show-branch --all`
EOF
then
 echo &quot;$BRANCH_NAME exists&quot;
else
 echo &quot;$BRANCH_NAME not exists&quot;
fi
</code></pre>

blocks|key|1989109|text|是的，有一个。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1989110|git+rev-parse+[<options>]+<args>…​|code-block|syntax|javascript|1989111|请参见https://git-scm.com/docs/git-rev-parse，您可以在其中找到一组参数和函数。|offset|length|1989112|git+rev-parse+--verify+<branch-name>|1989113|entityMap|0|LINK|mutability|MUTABLE|url|https://git-scm.com/docs/git-rev-parse^0|0|0|3|12|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@$I|X|J|Y|1|Z]]|A|$]]|$1|K|3|L|5|D|7|10|8|@]|9|@]|A|$E|F]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]]]

Yup, there is one.

<pre><code>git rev-parse [&lt;options&gt;] &lt;args&gt;…​
</code></pre>

See <a href="https://git-scm.com/docs/git-rev-parse" rel="nofollow noreferrer">https://git-scm.com/docs/git-rev-parse</a> where you can find the set of arguments and the function.

<pre><code>git rev-parse --verify &lt;branch-name&gt;
</code></pre>

blocks|key|1775296|text|git+show-branch+<BRANCH-NAME>+&>/dev/null+&&+echo+yes+%7C%7C+echo+no|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1775297|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>git show-branch &lt;BRANCH-NAME&gt; &amp;&gt;/dev/null &amp;&amp; echo yes || echo no
</code></pre>

blocks|key|1775394|text|这就是我实现它的方式，我认为看起来更稳定|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1775395|$branchExists+=+git+ls-remote+$gitUrl+$gitBranch
if(!([bool]$branchExists))
{
+++Write-Host+"branch+$branchName+does+not+exist"++
}+
else
{
+++Write-Host+"branch+$branchName+exists"+++++++++
}|code-block|syntax|javascript|1775396|如果分支存在，则branchExist变量的内容将类似于：|1775397|hashcode+of+branch+name+++++++++feature/my_branch|1775398|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

This is how I implemented it, looks more stable I think
<pre><code>$branchExists = git ls-remote $gitUrl $gitBranch
if(!([bool]$branchExists))
{
 Write-Host &quot;branch $branchName does not exist&quot; 
} 
else
{
 Write-Host &quot;branch $branchName exists&quot; 
}
</code></pre>
If the branch exists the content of the branchExist variable would be something like:
<pre><code>hashcode of branch name feature/my_branch
</code></pre>

I am using the following command to find out if a local git branch with <code>branch-name</code> exists in my repository. Is this correct? Is there a better way?

Please note that I am doing this inside a script. For this reason I'd like to <a href="https://mirrors.edge.kernel.org/pub/software/scm/git/docs/#_low_level_commands_plumbing" rel="noreferrer">use plumbing commands</a> if possible. 

<pre class="lang-sh prettyprint-override"><code>git show-ref --verify --quiet refs/heads/&lt;branch-name&gt;
# $? == 0 means local branch with &lt;branch-name&gt; exists. 
</code></pre>

Is there a better way to find out if a local git branch exists?

我使用以下命令来查看我的存储库中是否存在带有branch-name的本地git分支。这是正确的吗？有没有更好的方法？请注意，我是在脚本中执行此操作的。出于这个原因，如果可能的话，我想使用。git show-ref --verify --quiet refs/heads/<branch-name># $? == 0 me...

问有没有更好的方法来找出本地git分支是否存在？
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问有没有更好的方法来找出本地git分支是否存在？
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