blocks|key|225739|text|正如user2246674所说的，使用success和error作为ajax函数的参数是有效的。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|225740|为了与先例答案一致，请阅读文档：|225741|225742|+弃用通知：|blockquote|BOLD|225743|225744|jqXHR.success()、jqXHR.error()和jqXHR.complete()回调在jQuery+1.8中将被弃用。要为最终删除它们的代码做好准备，请改用jqXHR.done()、jqXHR.fail()和jqXHR.always()。|225745|225746|如果使用回调操作函数(例如使用方法链接)，请使用.done()、.fail()和.always()，而不是success()、error()和complete()。|225747|entityMap^0|J|7|R|5|0|0|0|1|4|0|0|0|0|O|7|W|7|14|9|1H|9|1R|7|1Z|A|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Z|8|@]|D|@]|E|$]]|$1|H|3|-4|5|6|7|10|8|@]|D|@]|E|$]]|$1|I|3|J|5|K|7|11|8|@$9|12|A|13|B|L]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|14|8|@]|D|@]|E|$]]|$1|N|3|O|5|6|7|15|8|@]|D|@]|E|$]]|$1|P|3|-4|5|6|7|16|8|@]|D|@]|E|$]]|$1|Q|3|R|5|6|7|17|8|@$9|18|A|19|B|C]|$9|1A|A|1B|B|C]|$9|1C|A|1D|B|C]|$9|1E|A|1F|B|C]|$9|1G|A|1H|B|C]|$9|1I|A|1J|B|C]]|D|@]|E|$]]|$1|S|3|-4|5|6|7|1K|8|@]|D|@]|E|$]]]|T|$]]

As stated by user2246674, using <code>success</code> and <code>error</code> as parameter of the ajax function is valid.
To be consistent with precedent answer, reading the doc :
<blockquote>
Deprecation Notice:
The jqXHR.success(), jqXHR.error(), and jqXHR.complete() callbacks will be deprecated in jQuery 1.8. To prepare your code for their eventual removal, use jqXHR.done(), jqXHR.fail(), and jqXHR.always() instead.
</blockquote>
If you are using the callback-manipulation function (using method-chaining for example), use <code>.done()</code>, <code>.fail()</code> and <code>.always()</code> instead of <code>success()</code>, <code>error()</code> and <code>complete()</code>.

blocks|key|3093092|text|我想在@Michael+Laffargue的帖子上添加一些东西：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3093093|jqXHR.done()更快！|offset|length|style|CODE|3093094|jqXHR.success()在回调中有一些加载时间，有时可能会过度杀死脚本。我以前发现这很难。|3093095|更新：|BOLD|3093096|使用jqXHR.done()、jqXHR.fail()和jqXHR.always()，您可以更好地处理ajax请求。通常，您可以在一些变量或对象中定义ajax，并在代码的任何部分使用该变量或对象，从而更快地获取数据。一个很好的例子：|3093097|/*+Initialize+some+your+AJAX+function+*/
function+call_ajax(attr){
++++var+settings=$.extend({
++++++++call++++++++++++:+'users',
++++++++option++++++++++:+'list'
++++},+attr+);

++++return+$.ajax({
++++++++type:+"POST",
++++++++url:+"//exapmple.com//ajax.php",
++++++++data:+settings,
++++++++cache+:+false
++++});
}

/*+....+Somewhere+in+your+code+.....+*/

call_ajax({
++++/*+...+*/
++++id+:+10,
++++option+:+'edit_user'
++++change+:+{
++++++++++name+:+'John+Doe'
++++}
++++/*+...+*/
}).done(function(data){

++++/*+DO+SOMETHING+AWESOME+*/

});|code-block|syntax|javascript|3093098|entityMap^0|0|0|C|0|0|F|0|0|3|0|2|C|F|C|S|E|0|0^^$0|@$1|2|3|4|5|6|7|V|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|W|8|@$D|X|E|Y|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|Z|8|@$D|10|E|11|F|G]]|9|@]|A|$]]|$1|J|3|K|5|6|7|12|8|@$D|13|E|14|F|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|15|8|@$D|16|E|17|F|G]|$D|18|E|19|F|G]|$D|1A|E|1B|F|G]]|9|@]|A|$]]|$1|O|3|P|5|Q|7|1C|8|@]|9|@]|A|$R|S]]|$1|T|3|-4|5|6|7|1D|8|@]|9|@]|A|$]]]|U|$]]

I want to add something on @Michael Laffargue's post:

<code>jqXHR.done()</code> is faster!

<code>jqXHR.success()</code> have some load time in callback and sometimes can overkill script. I find that on hard way before.

UPDATE:

Using <code>jqXHR.done()</code>, <code>jqXHR.fail()</code> and <code>jqXHR.always()</code> you can better manipulate with ajax request. Generaly you can define ajax in some variable or object and use that variable or object in any part of your code and get data faster. Good example:

<pre><code>/* Initialize some your AJAX function */
function call_ajax(attr){
 var settings=$.extend({
 call : 'users',
 option : 'list'
 }, attr );

 return $.ajax({
 type: "POST",
 url: "//exapmple.com//ajax.php",
 data: settings,
 cache : false
 });
}

/* .... Somewhere in your code ..... */

call_ajax({
 /* ... */
 id : 10,
 option : 'edit_user'
 change : {
 name : 'John Doe'
 }
 /* ... */
}).done(function(data){

 /* DO SOMETHING AWESOME */

});
</code></pre>

blocks|key|3093124|text|简而言之|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3093125|$.ajax("info.txt").done(function(data)+{
++alert(data);
}).fail(function(data){
++alert("Try+again+champ!");
});|code-block|syntax|javascript|3093126|如果它得到了info.text，那么它就会发出警报，无论你添加了什么函数，或者如果有任何函数，如何无法从服务器检索info.text，那么它就会发出警报或错误函数。|3093127|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

In simple words 

<pre><code>$.ajax("info.txt").done(function(data) {
 alert(data);
}).fail(function(data){
 alert("Try again champ!");
});
</code></pre>

if its get the info.text then it will alert and whatever function you add or if any how unable to retrieve info.text from the server then alert or error function.

blocks|key|2879038|text|当我们要将JQuery从1.x迁移到现有的旧应用程序中的2x或3.x时，我们将使用.done，.fail而不是success，error，因为JQuery+up灰度将被弃用。这些methods.For示例当我们调用服务器web方法时，服务器返回promise对象到调用方法(Ajax方法)，此promise对象包含.done，.fail..etc+methods.Hence。我们将对成功和失败响应进行相同的操作。下面是示例(它是POST请求的相同方法，我们可以构造请求类型，如GET...)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2879039|+$.ajax({
++++++++++++type:+"POST",
++++++++++++url:+url,
++++++++++++data:+'{"name"+:"sheo"}',
++++++++++++contentType:+"application/json;+charset=utf-8",
++++++++++++async:+false,
++++++++++++cache:+false
++++++++++++}).done(function+(Response)+{
++++++++++++++++++//do+something+when+get+response++++++++++++})
+++++++++++.fail(function+(Response)+{
++++++++++++++++++++//do+something+when+any+error+occurs.
++++++++++++++++});|code-block|syntax|javascript|2879040|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

When we are going to migrate JQuery from 1.x to 2x or 3.x in our old existing application , then we will use .done,.fail instead of success,error as JQuery up gradation is going to be deprecated these methods.For example when we make a call to server web methods then server returns promise objects to the calling methods(Ajax methods) and this promise objects contains .done,.fail..etc methods.Hence we will the same for success and failure response. Below is the example(it is for POST request same way we can construct for request type like GET...)

<pre><code> $.ajax({
 type: "POST",
 url: url,
 data: '{"name" :"sheo"}',
 contentType: "application/json; charset=utf-8",
 async: false,
 cache: false
 }).done(function (Response) {
 //do something when get response })
 .fail(function (Response) {
 //do something when any error occurs.
 });
</code></pre>

I have coded like this:

<pre><code>$.ajax({ cache: false,
 url: "/Admin/Contents/GetData",
 data: { accountID: AccountID },
 success: function (data) {
 $('#CityID').html(data);
 },
 error: function (ajaxContext) {
 alert(ajaxContext.responseText)
 }
});
</code></pre>

But when I look at the jQuery <a href="http://api.jquery.com/jQuery.ajax/" rel="noreferrer"><code>.ajax()</code> documentation</a> at the end it seems to suggest I should be coding like this below or at least it suggests adding a <code>.done()</code> and a <code>.fail()</code>:

<pre><code>var request = $.ajax({ cache: false,
 url: "/Admin/Contents/GetData",
 data: { accountID: AccountID }
});

request.done(function (data) {
 xxx;
});
request.fail(function (jqXHR, textStatus) {
 xxx;
});
</code></pre>

Update

If I code like this is it the same or is there some advantage to breaking it into three ?

<pre><code>$.ajax({ cache: false,
 url: "/Admin/Contents/GetData",
 data: { accountID: AccountID }
}).done(function (data) {
 xxx;
}).fail(function (jqXHR, textStatus) {
 xxx;
});
</code></pre>

Should I use .done() and .fail() for new jQuery AJAX code instead of success and error

服务器

jQuery

我的代码是这样的：$.ajax({ cache: false,    url: "/Admin/Contents/GetData",    data: { accountID: AccountID },    success: function (data) {        $('#CityID').html(dat...

问我是否应该为新的jQuery AJAX代码使用.done()和.fail()，而不是使用成功和错误
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问我是否应该为新的jQuery AJAX代码使用.done()和.fail()，而不是使用成功和错误
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