blocks|key|1506629|text|if+(php_sapi_name()+==+'cli')+{+++
+++if+(isset($_SERVER['TERM']))+{+++
++++++echo+"The+script+was+run+from+a+manual+invocation+on+a+shell";+++
+++}+else+{+++
++++++echo+"The+script+was+run+from+the+crontab+entry";+++
+++}+++
}+else+{+
+++echo+"The+script+was+run+from+a+webserver,+or+something+else";+++
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1506630|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>if (php_sapi_name() == 'cli') { 
 if (isset($_SERVER['TERM'])) { 
 echo "The script was run from a manual invocation on a shell"; 
 } else { 
 echo "The script was run from the crontab entry"; 
 } 
} else { 
 echo "The script was run from a webserver, or something else"; 
}
</code></pre>

blocks|key|1721385|text|您可以设置一个额外的参数，或者在crontab中添加一行，例如：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1721386|CRON=running|code-block|syntax|javascript|1721387|然后你可以检查你的环境变量中是否有"CRON“。另外，尝试检查$SHELL变量，我不确定是否/什么cron将其设置为。|1721388|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You can setup an extra parameter, or add a line in your crontab, perhaps:

<pre><code>CRON=running
</code></pre>

And then you can check your environment variables for "CRON". Also, try checking the $SHELL variable, I'm not sure if/what cron sets it to.

blocks|key|1721604|text|正确的方法是对标准输出文件描述符使用posix_isatty()函数，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1721605|if+(posix_isatty(STDOUT))
++++/*+do+interactive+terminal+stuff+here+*/|code-block|syntax|javascript|1721606|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

The right approach is to use the posix_isatty() function on e.g. the stdout file descriptor, like so:

<pre><code>if (posix_isatty(STDOUT))
 /* do interactive terminal stuff here */
</code></pre>

blocks|key|1506614|text|我认为最通用的解决方案是在cron命令中添加一个环境变量，然后在代码中查找它。它将在所有系统上运行。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1506615|如果cron执行的命令是，例如：|1506616|"/usr/bin/php+-q+/var/www/vhosts/myuser/index.php"|code-block|syntax|javascript|1506617|将其更改为|1506618|"CRON_MODE=1+/usr/bin/php+-q+/var/www/vhosts/myuser/index.php"|1506619|然后你可以在代码中检查它：|1506620|if+(!getenv('CRON_MODE'))
++++print+"Sorry,+only+CRON+can+access+this+script";|1506621|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|V|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|W|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|X|8|@]|9|@]|A|$]]|$1|O|3|P|5|F|7|Y|8|@]|9|@]|A|$G|H]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

I think that the most universal solution is to add an environment variable to the cron command, and look for it on the code. It will work on every system.

If the command executed by the cron is, for example:

<pre><code>"/usr/bin/php -q /var/www/vhosts/myuser/index.php"
</code></pre>

Change it to

<pre><code>"CRON_MODE=1 /usr/bin/php -q /var/www/vhosts/myuser/index.php"
</code></pre>

Then you can check it on the code:

<pre><code>if (!getenv('CRON_MODE'))
 print "Sorry, only CRON can access this script";
</code></pre>

blocks|key|1721756|text|很恐怖。试一试|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1721757|if+(!isset($_SERVER['HTTP_USER_AGENT']))+{|code-block|syntax|javascript|1721758|而不是。PHP客户端二进制文件不发送它。当PHP被用作模块(即apache)时，Term+Type才起作用，但当通过CGI接口运行php时，请使用上面的示例！|1721759|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Creepy. Try 

<pre><code>if (!isset($_SERVER['HTTP_USER_AGENT'])) {
</code></pre>

instead. PHP Client Binary dont send it. Term Type just works when PHP is used as module (ie apache) but when running php through CGI interface, use the example above!

blocks|key|1506067|text|据我所知，可能最简单的解决方案是自己提供一个额外的参数来告诉脚本它是如何被调用的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1506068|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

Not that I know of - probably the simplest solution is providing an extra parameter yourself to tell the script how it was invoked.

blocks|key|1721285|text|我会查看$_ENV+(var_dump()+it)，检查您是否注意到运行它时与cronjob运行它时的不同。除此之外，我不认为有一个“官方”开关来告诉你发生了什么。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1721286|entityMap^0|4|5|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

I would look into <code>$_ENV</code> (var_dump() it) and check if you notice a difference when you run it vs. when the cronjob runs it. Aside from that I don't think there is an "official" switch that tells you what happened.

blocks|key|1506357|text|在我的环境中，我发现如果从命令行运行，TERM是在$_SERVER中设置的，但如果通过Apache作为web请求运行，则没有设置。我将这段代码放在我的脚本的顶部，我可以从命令行运行，也可以通过web浏览器访问：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1506358|if+(isset($_SERVER{'TERM'}))
{
++++class::doStuffShell();
}
else
{
++++class::doStuffWeb();
}|code-block|syntax|javascript|1506359|entityMap^0|J|4|P|8|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|L|$]]

In my environment, I found that <code>TERM</code> was set in <code>$_SERVER</code> if run from the command line, but not set if run via Apache as a web request. I put this at the top of my script that I might run from the command line, or might access via a web browser:

<pre><code>if (isset($_SERVER{'TERM'}))
{
 class::doStuffShell();
}
else
{
 class::doStuffWeb();
}
</code></pre>

blocks|key|1506688|text|getenv('TERM')|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1506689|填充SO的30个字符。|unstyled|1506690|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>getenv('TERM')
</code></pre>

Padding for SO's 30 char min.

blocks|key|1506154|text|在cron命令中，将?source=cron添加到脚本路径的末尾。然后，在您的脚本中，检查$_GET['source']。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1506155|编辑:对不起，这是一个shell脚本，所以不能使用qs。我认为，您可以以php+script.php+arg1+arg2的形式传递参数，然后用$argv读取它们。|1506156|entityMap^0|A|C|19|F|0|10|O|1Z|5|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]|$9|M|A|N|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|H|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|I|$]]

In the cron command, add <code>?source=cron</code> to the end of the script path. Then, in your script, check <code>$_GET['source']</code>.

EDIT: sorry, it's a shell script so can't use qs. You can, I think, pass arguments in the form <code>php script.php arg1 arg2</code> and then read them with <code>$argv</code>.

blocks|key|1506740|text|另一种选择是测试一个特定的环境变量，该变量是在通过web调用php文件时设置的，如果通过命令行运行则不设置。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1506741|在我的web服务器上，我正在测试APACHE_RUN_DIR环境变量是否设置如下：|1506742|if+(isset($_ENV["APACHE_RUN_DIR"]))+{
++//+I'm+called+by+a+web+user
}
else+{
++//+I'm+called+by+crontab
}+|code-block|syntax|javascript|1506743|为了确保它能在你的web服务器上工作，你可以用下面的语句在你的web服务器上放一个虚拟的php文件：|1506744|<?php+var_dump($_ENV);++?>|1506745|然后1)使用web浏览器加载它，2)像这样从命令行加载它|1506746|/usr/bin/php+/var/www/yourpath/dummy.php|1506747|比较差异并测试相应的变量。|1506748|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|W|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|X|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|Y|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|Z|8|@]|9|@]|A|$]]|$1|O|3|P|5|F|7|10|8|@]|9|@]|A|$G|H]]|$1|Q|3|R|5|6|7|11|8|@]|9|@]|A|$]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

Another option would be to test a specific environment variable that is set when the php file is invoked through the web and not set if runned by the commandline.

On my web server I'm testing if the APACHE_RUN_DIR environment variable is set like this :

<pre><code>if (isset($_ENV["APACHE_RUN_DIR"])) {
 // I'm called by a web user
}
else {
 // I'm called by crontab
} 
</code></pre>

To make sure it will work on your web server, you can put a dummy php file on your web server with this single statement :

<pre><code>&lt;?php var_dump($_ENV); ?&gt;
</code></pre>

Then 1) load it with your web browser and 2) load it from the commandline like this

<pre><code>/usr/bin/php /var/www/yourpath/dummy.php
</code></pre>

Compare the differences and test the appropriate variable.

blocks|key|1506236|text|如果从命令行界面运行，则$_SERVER['SESSIONNAME']包含Console。也许这会有帮助。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1506237|entityMap^0|C|N|11|7|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|M|8|@]|D|@]|E|$]]]|G|$]]

<code>$_SERVER['SESSIONNAME']</code> contains <code>Console</code> if run from the CLI. Maybe that helps.

blocks|key|1506245|text|if(!$_SERVER['HTTP_HOST'])+{
+blabla();
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1506246|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>if(!$_SERVER['HTTP_HOST']) {
 blabla();
}
</code></pre>

blocks|key|1721494|text|我认为最好在命令行中运行cron+commmand，并在命令行中添加一个不会手动运行的选项。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1721495|cron会这样做：|1721496|command+ext_updates=1|code-block|syntax|javascript|1721497|使用手册可以做到：|1721498|command+|1721499|只需在脚本本身中添加一个选项，使ext_updates参数的默认值为false。|1721500|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|U|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

I think it would be better to run the cron commmand with an additional option at the command line that you wouldn't run manually. 

cron would do:

<pre><code>command ext_updates=1
</code></pre>

manual would do:

<pre><code>command 
</code></pre>

Just add an option in the script itself to have the ext_updates param to have a default value of false.

blocks|key|1506441|text|如果cli调用的输出被重定向(管道或文件)，则为posix_isatty(STDOUT)+return+FALSE+...|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1506442|entityMap^0|O|X|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

<code>posix_isatty(STDOUT) return FALSE</code> if the output of the cli call is redirected (pipe or file)...

blocks|key|1506655|text|这非常简单。Cron+Daemons始终导出MAILTO环境变量。检查它是否存在并且具有非空值-然后从cron运行。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1506656|entityMap^0|M|6|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

This is very easy. Cron Daemons always export <code>MAILTO</code> environment variable. Check if it exists and has a non-empty value - then you running from cron.

blocks|key|1506782|text|在我的Amazon+Linux服务器上，这就是我想要的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1506783|$isCron+=($_SERVER‘’HOME‘==+'/’)；|1506784|如果您只运行主目录，则会将其设置为您的主目录。如果您使用sudo来运行它，则主目录将设置为/root。|1506785|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

On my Amazon Linux server this is what worked for me:

$isCron = ( $_SERVER['HOME'] == '/' );

The home directory is set to yours if you just run it. If you use sudo to run it, the home directory is set to /root.

blocks|key|1506834|text|(array)+$argv将在cron作业运行时设置。该数组的第一个值是您在创建cron作业时使用的/path/to/文件。$argv中的以下值将是/path/to/文件后面的任何参数。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1506835|例如，如果您的cron作业命令如下所示：|1506836|php+/path/to/file.php+first+second+third|1506837|$argv的值为：["/path/to/file.php",+"first",+"second",+"third"]|1506838|然后，您可以：|1506839|if+(isset($argv)+&&+is_array($argv)+&&+in_array('first',+$argv))+{+/*+do+something+*/+}|1506840|entityMap^0|0|D|1Q|5|0|0|0|14|0|9|1D|0|0|0|2F|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]|$9|U|A|V|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|W|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|X|8|@$9|Y|A|Z|B|C]]|D|@]|E|$]]|$1|J|3|K|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@]|E|$]]|$1|L|3|M|5|6|7|13|8|@]|D|@]|E|$]]|$1|N|3|O|5|6|7|14|8|@$9|15|A|16|B|C]]|D|@]|E|$]]|$1|P|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|Q|$]]

<code>(array) $argv</code> will be set when the cron job runs.
The first value of the array will be the /path/to/file you used when creating the cron job.
The following values in <code>$argv</code> will be any parameters that followed the /path/to/file.
For example, if your cron job command looks like this:
<code>php /path/to/file.php first second third</code>
The value of $argv will be: <code>[&quot;/path/to/file.php&quot;, &quot;first&quot;, &quot;second&quot;, &quot;third&quot;]</code>
You can then:
<code>if (isset($argv) &amp;&amp; is_array($argv) &amp;&amp; in_array('first', $argv)) { /* do something */ }</code>

blocks|key|1506499|text|对我来说很简单..。只要count($_SERVER['argc'])，如果你有一个大于零的结果，它将在服务器上耗尽。您只需将您的自定义变量(如"CronJob"=true;+)添加到$_SERVER['argv']中|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1506500|entityMap^0|C|N|20|F|2K|G|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]|$9|M|A|N|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|O|8|@]|D|@]|E|$]]]|G|$]]

It's easy for me... Just <code>count($_SERVER['argc'])</code> and if you have a result higher than zero it will be running out of a server. You just need to add to your <code>$_SERVER['argv']</code> your custom variable, like <code>"CronJob"=true;</code>

I'm looking for way to PHP to detect if a script was run from a manual invocation on a shell (me logging in and running it), or if it was run from the crontab entry.

I have various maintenance type scripts written in php that i have set to run in my crontab. Occasionally, and I need to run them manually ahead of schedule or if something failed/broken, i need to run them a couple times.

The problem with this is that I also have some external notifications set into the tasks (posting to twitter, sending an email, etc) that I DONT want to happen everytime I run the script manually.

I'm using php5 (if it matters), its a fairly standard linux server environment.

Any ideas?

Can PHP detect if its run from a cron job or from the command line?

服务器

Linux

我正在寻找PHP的方法来检测脚本是从shell上的手动调用(我登录并运行它)运行的，还是从crontab条目运行的。我已经在我的crontab中设置了用php编写的各种维护类型的脚本。偶尔，我需要提前手动运行它们，或者如果某些东西失败/损坏，我需要运行它们几次。这样做的问题是，我也有一些外部通知设置到任务(发布到twitter，发送电子邮件，等等)，我不希望每次我手动运行脚本时发生。我使用的是ph

问PHP能检测到它是从cron作业还是从命令行运行吗？
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回答 19

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问PHP能检测到它是从cron作业还是从命令行运行吗？
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