能否提供参数给Ruby中的map语法?

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你可能熟悉下面的Ruby:

a.map(&:method)

在irb中尝试以下内容:

>> a=[:a, 'a', 1, 1.0]
=> [:a, "a", 1, 1.0]
>> a.map(&:class)
=> [Symbol, String, Fixnum, Float]

如何转换下面的语法?

a = [1,3,5,7,9]
a.map {|x| x + 2}

提问于
用户回答回答于

像这样创建一个简单的补丁:

class Symbol
  def with(*args, &block)
    ->(caller, *rest) { caller.send(self, *rest, *args, &block) }
  end
end

不仅可以做到这一点:

a = [1,3,5,7,9]
a.map(&:+.with(2))
# => [3, 5, 7, 9, 11] 

比如传递多个参数:

arr = ["abc", "babc", "great", "fruit"]
arr.map(&:center.with(20, '*'))
# => ["********abc*********", "********babc********", "*******great********", "*******fruit********"]
arr.map(&:[].with(1, 3))
# => ["bc", "abc", "rea", "rui"]
arr.map(&:[].with(/a(.*)/))
# => ["abc", "abc", "at", nil] 
arr.map(&:[].with(/a(.*)/, 1))
# => ["bc", "bc", "t", nil] 

甚至可以使用inject,它将两个参数传递给块:

%w(abecd ab cd).inject(&:gsub.with('cde'))
# => "cdeeecde" 

[['0', '1'], ['2', '3']].map(&:map.with(&:to_i))
# => [[0, 1], [2, 3]]
[%w(a b), %w(c d)].map(&:inject.with(&:+))
# => ["ab", "cd"] 
[(1..5), (6..10)].map(&:map.with(&:*.with(2)))
# => [[2, 4, 6, 8, 10], [12, 14, 16, 18, 20]] 

class Symbol
  def call(*args, &block)
    ->(caller, *rest) { caller.send(self, *rest, *args, &block) }
  end
end

a = [1,3,5,7,9]
a.map(&:+.(2))
# => [3, 5, 7, 9, 11] 

[(1..5), (6..10)].map(&:map.(&:*.(2)))
# => [[2, 4, 6, 8, 10], [12, 14, 16, 18, 20]] 
用户回答回答于

Arup-iMac:$ pry
[1] pry(main)> a = [1,3,5,7,9]
=> [1, 3, 5, 7, 9]
[2] pry(main)> a.map(&2.method(:+))
=> [3, 5, 7, 9, 11]
[3] pry(main)> 

下面是它的工作原理:

[3] pry(main)> 2.method(:+)
=> #<Method: Fixnum#+>
[4] pry(main)> 2.method(:+).to_proc
=> #<Proc:0x000001030cb990 (lambda)>
[5] pry(main)> 2.method(:+).to_proc.call(1)
=> 3

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