blocks|key|965746|text|您几乎可以做到这一点，您只是省略了0并忘记了量词。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|965747|word.matches("%5E[0-9,;]%2B$")|code-block|syntax|javascript|965748|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You almost have it, you just left out 0 and forgot the quantifier.

<pre><code>word.matches("^[0-9,;]+$")
</code></pre>

blocks|key|750241|text|试试word.matches("%5E[0-9,;]%2B$");|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|750242|entityMap^0|2|R|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

Try <code>word.matches("^[0-9,;]+$");</code>

blocks|key|750244|text|boolean+foundMatch+=+Pattern.matches("[0-9,;]%2B",+"131;23,87");|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|750245|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>boolean foundMatch = Pattern.matches("[0-9,;]+", "131;23,87");
</code></pre>

blocks|key|750289|text|word.matches("%5E[0-9,;]%2B$");你就快到了|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|750290|entityMap^0|0|R|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

<code>word.matches("^[0-9,;]+$");</code> you were almost there

blocks|key|965826|text|你已经完成了90%25的目标。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|965827|%5E[0-9,;]%2B$|offset|length|style|CODE|965828|以克拉开头的%5E表示行的开始。|965829|[表示字符集|965830|0-9表示字符0到9，逗号,表示逗号，分号表示;。|965831|结束的]表示字符集的结束。|965832|加号%2B表示必须存在一个或多个“前一项”。在这种情况下，这意味着您必须在先前声明的字符集中包含一个或多个字符。|965833|美元$表示行的结束。|965834|entityMap^0|0|0|A|0|6|1|0|0|1|0|0|3|D|1|N|1|0|3|1|0|2|1|0|2|1|0^^$0|@$1|2|3|4|5|6|7|V|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|W|8|@$D|X|E|Y|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|Z|8|@$D|10|E|11|F|G]]|9|@]|A|$]]|$1|J|3|K|5|6|7|12|8|@$D|13|E|14|F|G]]|9|@]|A|$]]|$1|L|3|M|5|6|7|15|8|@$D|16|E|17|F|G]|$D|18|E|19|F|G]|$D|1A|E|1B|F|G]]|9|@]|A|$]]|$1|N|3|O|5|6|7|1C|8|@$D|1D|E|1E|F|G]]|9|@]|A|$]]|$1|P|3|Q|5|6|7|1F|8|@$D|1G|E|1H|F|G]]|9|@]|A|$]]|$1|R|3|S|5|6|7|1I|8|@$D|1J|E|1K|F|G]]|9|@]|A|$]]|$1|T|3|-4|5|6|7|1L|8|@]|9|@]|A|$]]]|U|$]]

You are 90% of the way there.

<code>^[0-9,;]+$</code>

Starting with the carat <code>^</code> indicates a beginning of line.

The <code>[</code> indicates a character set

The <code>0-9</code> indicates characters 0 through 9, the comma <code>,</code> indicates comma, and the semicolon indicates a <code>;</code>.

The closing <code>]</code> indicates the end of the character set.

The plus <code>+</code> indicates that one or more of the "previous item" must be present. In this case it means that you must have one or more of the characters in the previously declared character set.

The dollar <code>$</code> indicates the end of the line.

blocks|key|750366|text|您当前的正则表达式将只匹配1个字符。您需要*(包括空字符串)或%2B(至少一个)来匹配多个字符，并且数字有一个快捷方式：\d+(字符串中需要\)。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|750367|word.matches("%5E[\\d,;]%2B$")+|code-block|syntax|javascript|750368|模式文档相当不错：http://download.oracle.com/javase/1.5.0/docs/api/java/util/regex/Pattern.html|offset|length|750369|您也可以在线试用您的正则表达式：http://www.regexplanet.com/simple/index.html|750370|entityMap|0|LINK|mutability|MUTABLE|url|http://download.oracle.com/javase/1.5.0/docs/api/java/util/regex/Pattern.html|1|http://www.regexplanet.com/simple/index.html^0|0|0|9|25|0|0|G|18|1|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@]|9|@$I|Z|J|10|1|11]]|A|$]]|$1|K|3|L|5|6|7|12|8|@]|9|@$I|13|J|14|1|15]]|A|$]]|$1|M|3|-4|5|6|7|16|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]|U|$5|P|Q|R|A|$S|V]]]]

You current regex will only match 1 character. you need either * (includes empty string) or + (at least one) to match multiple characters and numbers have a shortcut : \d (need \\ in a string).

<pre><code>word.matches("^[\\d,;]+$") 
</code></pre>

The Pattern documentation is pretty good : <a href="http://download.oracle.com/javase/1.5.0/docs/api/java/util/regex/Pattern.html" rel="nofollow">http://download.oracle.com/javase/1.5.0/docs/api/java/util/regex/Pattern.html</a>

Also you can try your regexps online at:
<a href="http://www.regexplanet.com/simple/index.html" rel="nofollow">http://www.regexplanet.com/simple/index.html</a>

What's a regular expression that will match a string only containing digits 0 through 9, a comma, and a semi-colon? I'm looking to use it in Java like so:

<pre><code>word.matches("^[1-9,;]$") //Or something like that...
</code></pre>

I'm new to regular expressions.

Regex match digits, comma and semicolon?

Java

匹配仅包含数字0到9、逗号和分号的字符串的正则表达式是什么？我希望在Java中使用它，如下所示：word.matches("^[1-9,;]$") //Or something like that...我是正则表达式的新手。

问正则表达式匹配数字、逗号和分号？
EN

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问正则表达式匹配数字、逗号和分号？
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