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如何显示图片和获取鼠标点击坐标
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Stack Overflow用户
提问于 2011-03-31 22:06:31
回答 5查看 44K关注 0票数 31

我想知道是否有可能在Python (Windows)中显示一些图片,然后用鼠标单击此图片,并获得此点击相对于图片边缘的坐标。

谢谢!

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回答 5

Stack Overflow用户

回答已采纳

发布于 2011-03-31 23:11:54

是的,一旦你理解了tkinter,这是可能的,也是相当容易的,这里有一个快速脚本:

代码语言:javascript
复制
from Tkinter import *
from tkFileDialog import askopenfilename
import Image, ImageTk

if __name__ == "__main__":
    root = Tk()

    #setting up a tkinter canvas with scrollbars
    frame = Frame(root, bd=2, relief=SUNKEN)
    frame.grid_rowconfigure(0, weight=1)
    frame.grid_columnconfigure(0, weight=1)
    xscroll = Scrollbar(frame, orient=HORIZONTAL)
    xscroll.grid(row=1, column=0, sticky=E+W)
    yscroll = Scrollbar(frame)
    yscroll.grid(row=0, column=1, sticky=N+S)
    canvas = Canvas(frame, bd=0, xscrollcommand=xscroll.set, yscrollcommand=yscroll.set)
    canvas.grid(row=0, column=0, sticky=N+S+E+W)
    xscroll.config(command=canvas.xview)
    yscroll.config(command=canvas.yview)
    frame.pack(fill=BOTH,expand=1)

    #adding the image
    File = askopenfilename(parent=root, initialdir="C:/",title='Choose an image.')
    img = ImageTk.PhotoImage(Image.open(File))
    canvas.create_image(0,0,image=img,anchor="nw")
    canvas.config(scrollregion=canvas.bbox(ALL))

    #function to be called when mouse is clicked
    def printcoords(event):
        #outputting x and y coords to console
        print (event.x,event.y)
    #mouseclick event
    canvas.bind("<Button 1>",printcoords)

    root.mainloop()

未编辑时,它将使用默认的窗口坐标系打印到控制台。canvas小部件将左上角设置为0,0点,因此您可能需要修改printcoord函数。要获得加载的图片尺寸,您可以使用canvas.bbox(ALL),并且您可能希望切换到使用canvasx和canvasy坐标,而不是它的原样。如果你是tkinter的新手,谷歌应该能够帮助你完成它:)。

票数 38
EN

Stack Overflow用户

发布于 2011-04-01 00:28:16

这是我不久前用wxPython和各种wxPython教程拼凑出来的一个版本。这会将鼠标单击坐标打印到单独的输出窗口。(使用Python 2.6.2、wxPython 2.8.10.1)

在底部的filepath变量中输入图像的路径。

代码语言:javascript
复制
import wx

class MyCanvas(wx.ScrolledWindow):
    def __init__(self, parent, id = -1, size = wx.DefaultSize, filepath = None):
        wx.ScrolledWindow.__init__(self, parent, id, (0, 0), size=size, style=wx.SUNKEN_BORDER)

        self.image = wx.Image(filepath)
        self.w = self.image.GetWidth()
        self.h = self.image.GetHeight()
        self.bmp = wx.BitmapFromImage(self.image)

        self.SetVirtualSize((self.w, self.h))
        self.SetScrollRate(20,20)
        self.SetBackgroundColour(wx.Colour(0,0,0))

        self.buffer = wx.EmptyBitmap(self.w, self.h)
        dc = wx.BufferedDC(None, self.buffer)
        dc.SetBackground(wx.Brush(self.GetBackgroundColour()))
        dc.Clear()
        self.DoDrawing(dc)

        self.Bind(wx.EVT_PAINT, self.OnPaint)
        self.Bind(wx.EVT_LEFT_UP, self.OnClick)

    def OnClick(self, event):
        pos = self.CalcUnscrolledPosition(event.GetPosition())
        print '%d, %d' %(pos.x, pos.y)

    def OnPaint(self, event):
        dc = wx.BufferedPaintDC(self, self.buffer, wx.BUFFER_VIRTUAL_AREA)

    def DoDrawing(self, dc):
        dc.DrawBitmap(self.bmp, 0, 0)

class MyFrame(wx.Frame): 
    def __init__(self, parent=None, id=-1, filepath = None): 
        wx.Frame.__init__(self, parent, id, title=filepath)
        self.canvas = MyCanvas(self, -1, filepath = filepath)

        self.canvas.SetMinSize((self.canvas.w, self.canvas.h))
        self.canvas.SetMaxSize((self.canvas.w, self.canvas.h))
        self.canvas.SetBackgroundColour(wx.Colour(0, 0, 0))
        vert = wx.BoxSizer(wx.VERTICAL)
        horz = wx.BoxSizer(wx.HORIZONTAL)
        vert.Add(horz,0, wx.EXPAND,0)
        vert.Add(self.canvas,1,wx.EXPAND,0)
        self.SetSizer(vert)
        vert.Fit(self)
        self.Layout()

if __name__ == '__main__':
    app = wx.App()
    app.SetOutputWindowAttributes(title='stdout')  
    wx.InitAllImageHandlers()

    filepath = 'ENTER FILEPATH HERE'
    if filepath:
        print filepath
        myframe = MyFrame(filepath=filepath)
        myframe.Center()
        myframe.Show()
        app.MainLoop()
票数 6
EN

Stack Overflow用户

发布于 2017-02-03 04:08:18

以下是bigjim答案的修订版。它可以在python 3.4+中工作(没有测试其他任何东西)。我没有麻烦的PIL部分,因为tkinter的PhotoImage可以处理gif和pgm,这足以演示这一点。

lambda函数处理事件(窗口)坐标和图像坐标之间的转换。

我还添加了对press vs release的支持,因为我需要那个特定的功能。

代码语言:javascript
复制
from tkinter import *
from tkinter.filedialog import askopenfilename

event2canvas = lambda e, c: (c.canvasx(e.x), c.canvasy(e.y))

if __name__ == "__main__":
    root = Tk()

    #setting up a tkinter canvas with scrollbars
    frame = Frame(root, bd=2, relief=SUNKEN)
    frame.grid_rowconfigure(0, weight=1)
    frame.grid_columnconfigure(0, weight=1)
    xscroll = Scrollbar(frame, orient=HORIZONTAL)
    xscroll.grid(row=1, column=0, sticky=E+W)
    yscroll = Scrollbar(frame)
    yscroll.grid(row=0, column=1, sticky=N+S)
    canvas = Canvas(frame, bd=0, xscrollcommand=xscroll.set, yscrollcommand=yscroll.set)
    canvas.grid(row=0, column=0, sticky=N+S+E+W)
    xscroll.config(command=canvas.xview)
    yscroll.config(command=canvas.yview)
    frame.pack(fill=BOTH,expand=1)

    #adding the image
    File = askopenfilename(parent=root, initialdir="M:/",title='Choose an image.')
    print("opening %s" % File)
    img = PhotoImage(file=File)
    canvas.create_image(0,0,image=img,anchor="nw")
    canvas.config(scrollregion=canvas.bbox(ALL))

    #function to be called when mouse is clicked
    def printcoords(event):
        #outputting x and y coords to console
        cx, cy = event2canvas(event, canvas)
        print ("(%d, %d) / (%d, %d)" % (event.x,event.y,cx,cy))
    #mouseclick event
    canvas.bind("<ButtonPress-1>",printcoords)
    canvas.bind("<ButtonRelease-1>",printcoords)

    root.mainloop()
票数 6
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/5501192

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