到目前为止,我使用PyQt类完成了以下工作:
all_Addresses = QNetworkInterface.allAddresses() #list-of-QHostAddress
for addr in all_Addresses:
print(addr.toString())
输出:
172.16.0.186 - Virtual Interface IP address
192.168.10.2 - Physical interface IP address. I want this one.
127.0.0.1
使用socket
import socket
print(socket.gethostbyname(socket.gethostname()))
输出:
172.16.0.186 - When openVPN is on
192.168.10.2 - When its off
发布于 2011-06-06 18:27:48
您应该使用netifaces。它是跨平台设计的,包含Windows的专用代码,以及在不同的UNIX/类UNIX平台上工作的各种通用版本。
从netifaces版本0.10.0开始,支持Python3。
使用情况摘要
>>> from netifaces import AF_INET, AF_INET6, AF_LINK, AF_PACKET, AF_BRIDGE
>>> import netifaces as ni
>>> ni.interfaces()
['lo', 'eth0', 'eth1', 'vboxnet0', 'dummy1']
>>>
>>> ni.ifaddresses('eth0')[AF_LINK] # NOTE: AF_LINK is an alias for AF_PACKET
[{'broadcast': 'ff:ff:ff:ff:ff:ff', 'addr': '00:02:55:7b:b2:f6'}]
>>> ni.ifaddresses('eth0')[AF_INET]
[{'broadcast': '172.16.161.7', 'netmask': '255.255.255.248', 'addr': '172.16.161.6'}]
>>>
>>> # eth0 ipv4 interface address
>>> ni.ifaddresses('eth0')[AF_INET][0]['addr']
'172.16.161.6'
>>>>
详细信息
Windows支持:
大多数MS Windows安装不需要编译器。如果您收到有关安装MS Visual python for Windows的警告,请使用very careful,因为您需要将用于python的编译器版本与用于模块的编译器版本进行匹配。
netifaces数据结构的详细示例:
>>> import netifaces as ni
>>> ni.interfaces()
['lo', 'eth0', 'eth1', 'vboxnet0', 'dummy1']
>>> ni.ifaddresses('eth0')
{
17: [
{
'broadcast': 'ff:ff:ff:ff:ff:ff',
'addr': '00:02:55:7b:b2:f6'
}
],
2: [
{
'broadcast': '172.16.161.7',
'netmask': '255.255.255.248',
'addr': '172.16.161.6'
}
],
10: [
{
'netmask': 'ffff:ffff:ffff:ffff::',
'addr': 'fe80::202:55ff:fe7b:b2f6%eth0'
}
]
}
>>>
>>> print(ni.ifaddresses.__doc__)
Obtain information about the specified network interface.
Returns a dict whose keys are equal to the address family constants,
e.g. netifaces.AF_INET, and whose values are a list of addresses in
that family that are attached to the network interface.
>>>
>>> # for the IPv4 address of eth0
>>> ni.ifaddresses('eth0')[2][0]['addr']
'172.16.161.6'
用于索引协议的数字来自/usr/include/linux/socket.h
(在Linux中)...编辑:我的3.2内核在这里有它们:/usr/src/linux-headers-3.2.0-4-common/include/linux/socket.h
#define AF_INET 2 /* Internet IP Protocol */
#define AF_INET6 10 /* IP version 6 */
#define AF_PACKET 17 /* Packet family */
好消息是,您不必记住所有这些头常量,它们包含在netifaces中
>>> from netifaces import AF_INET, AF_INET6, AF_LINK, AF_PACKET, AF_BRIDGE
>>> import netifaces as ni
发布于 2014-12-11 21:22:36
在给定接口名称的情况下,使用Linux SIOCGIFADDR ioctl查找与网络接口关联的IP地址,例如"eth0
“。该地址将作为包含点分四元组的字符串返回。
import socket
import fcntl
import struct
def get_ip_address(ifname):
s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
return socket.inet_ntoa(fcntl.ioctl(
s.fileno(),
0x8915, # SIOCGIFADDR
struct.pack('256s', ifname[:15])
)[20:24])
>>> get_ip_address('lo')
'127.0.0.1'
>>> get_ip_address('eth0')
'38.113.228.130'
发布于 2013-07-16 12:24:41
我使用这个解决方案。实际上这有点棘手,而且它只适用于linux系列。
import commands
intf = 'eth0'
intf_ip = commands.getoutput("ip address show dev " + intf).split()
intf_ip = intf_ip[intf_ip.index('inet') + 1].split('/')[0]
print intf_ip
这些代码利用了linux系列操作系统上的ip
命令。它会分割ip
命令的输出,只获取这些接口的IPv4地址。您可以将值intf
更改为eth1
或p2p1
。
https://stackoverflow.com/questions/6243276
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