blocks|key|881357|text|我认为你将不得不建造它，我认为它将是一个细节类的项目。从获取更全面的需求开始。您希望识别哪些日期模式？列出你想让你的算法成功识别的例子。编写你的算法来满足你的例子。将您的示例放在测试套件中，这样当您以后获得不同的需求时，您可以确保您没有破坏旧的需求。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|881358|我预测你会写200条if-then-else语句。|881359|好吧，我确实有一个想法。熟悉sets、unions、coverage、intersection等概念。有一个简短的模式列表，你可以搜索，比如“10月份的每一天”、“11月份的每一天”和“12月份的每一天”。如果这些短模式包含在日期集中，那么可以定义一个union函数，它可以以智能的方式组合短模式。例如，假设您匹配了我上面提到的三种模式。如果你把它们放在一起Union，你会得到“每天都在十月到十二月”。你可以返回最简洁的unions+cover你的日期或类似的东西的set。|offset|length|style|CODE|881360|entityMap^0|0|0|E|4|J|6|Q|8|Z|C|3I|5|4Z|5|5V|6|62|5|6I|3|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|N|8|@$F|O|G|P|H|I]|$F|Q|G|R|H|I]|$F|S|G|T|H|I]|$F|U|G|V|H|I]|$F|W|G|X|H|I]|$F|Y|G|Z|H|I]|$F|10|G|11|H|I]|$F|12|G|13|H|I]|$F|14|G|15|H|I]]|9|@]|A|$]]|$1|J|3|-4|5|6|7|16|8|@]|9|@]|A|$]]]|K|$]]

I think you'll have to build it, and I think it will be a devil in the details kind of project. Start by getting much more thorough requirements. Which date patterns do you want to recognize? Come up with a list of examples that you want your algorithm to successfully identify. Write your algorithm to meet your examples. Put your examples in a test suite so when you get different requirements later you can make sure you didn't break the old ones.

I predict you will write 200 if-then-else statements.

OK, I do have one idea. Get familiar with the concepts of <code>sets</code>, <code>unions</code>, <code>coverage</code>, <code>intersection</code> and so on. Have a list of short patterns that you search for, say, "Every day in October", "Every day in November", and "Every day in December." If these short patterns are contained within the set of dates, then define a <code>union</code> function that can combine shorter patterns in intelligent ways. For example, let's say you matched the three patterns I mention above. If you <code>Union</code> them together you get, "Every day in October through December." You could aim to return the most succinct <code>set</code> of <code>unions</code> that <code>cover</code> your set of dates or something like that.

blocks|key|881465|text|看看你最喜欢的日历程序。看看它可以生成什么样的事件重复模式。对它们进行逆向工程。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|881466|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

Have a look at your favourite calendar program. See what patterns of event recurrence it can generate. Reverse engineer them.

blocks|key|881596|text|您可以访问系统日期或系统日期和时间，并根据调用或函数结果返回的日期和星期几在内存中构造粗略的日历点。然后使用相关月份中的天数对它们求和，并在输入中添加day变量的天数和/或访问从周日或周一开始的相关周的日历点，并计算或递增索引到正确的日期。使用固定字符构造文本字符串，并根据需要插入相关变量，如星期几的全名。可能需要多次遍历才能获得要显示或计数其出现的所有事件。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|881597|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

You could access the system date or system dateandtime and construct crude calendar points in memory based on the date and the day of the week as returned by the call or function result. Then use the number of days in relevant months to sum them and add on the number of days of the day variable in the input and/or access the calendar point for the relevant week starting sunday or monday and calculate or increment index forward to the correct day. Construct text string using fixed characters and insert the relevant variable such as the full name of the day of the week as required. There may be multiple traversals needed to obtain all the events of which the occurrences are to be displayed or counted.

blocks|key|881648|text|首先，找到一个序列，如果它存在：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|881649|step+=+{day,month,year}
period=0
for+d+=+1+to+dates.count-1
++++interval(d,step)=datedifference(s,date(d),date(d%2B1))
next
'+Find+frequency+with+largest+interval
for+s+=+year+downto+day
++++found=true
++++for+d+=+1+to+dates.count-2
++++++++if+interval(d,s)=interval(d%2B1,s)+then
++++++++++++found=false
++++++++++++exit+for
++++++++end+if
++++next
++++if+found+then
++++++++period=s
++++++++frequency=interval(1,s)
++++++++exit+for
++++end+if
next

if+period>0
++++Select+case+period
++++++case+day
++++++++if+frequency+mod+7+=+0+then
++++++++++say+"every"+dayname(date(1))
++++++++else
++++++++++say+"every"+frequency+"days"
++++++++end+if
++++++case+month
++++++++say+"every"+frequency+"months+on+day"+daynumber(date(1))
++++++case+years
++++++++say+"every"+frequency+"years+on"+daynumber(date(1))+monthname(date(1))
++++end+select
end+if|code-block|syntax|javascript|881650|最后，处理“在11月”，“从2007年到2010年”等，应该是显而易见的。|881651|HTH|881652|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

First, find a sequence, if it exists:

<pre><code>step = {day,month,year}
period=0
for d = 1 to dates.count-1
 interval(d,step)=datedifference(s,date(d),date(d+1))
next
' Find frequency with largest interval
for s = year downto day
 found=true
 for d = 1 to dates.count-2
 if interval(d,s)=interval(d+1,s) then
 found=false
 exit for
 end if
 next
 if found then
 period=s
 frequency=interval(1,s)
 exit for
 end if
next

if period&gt;0
 Select case period
 case day
 if frequency mod 7 = 0 then
 say "every" dayname(date(1))
 else
 say "every" frequency "days"
 end if
 case month
 say "every" frequency "months on day" daynumber(date(1))
 case years
 say "every" frequency "years on" daynumber(date(1)) monthname(date(1))
 end select
end if
</code></pre>

Finally, deal with "in November", "from 2007 to 2010" etc., should be obvious.

HTH

I am looking for a pattern, algorithm, or library that will take a set of dates and return a description of the recurrence if one exits, i.e. the set [11-01-2010, 11-08-2010, 11-15-2010, 11-22-2010, 11-29-2010] would yield something like "Every Monday in November".

Has anyone seen anything like this before or have any suggestions on the best way to implement it?

Determine Event Recurrence Pattern for a set of dates

我正在寻找一个模式，算法，或库，将采取一组日期，并返回一个描述，如果一个退出，即集合11-01-2010，11-08-2010，11-15-2010，11-22-2010，11-29-2010将产生类似“每周一在11月”。有没有人以前见过这样的东西，或者有任何关于实现它的最佳方式的建议？

问确定一组日期的事件重复模式
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