blocks|key|3227384|text|"415不支持的媒体类型“错误告诉您服务器将不接受您的POST请求。您的请求是完全正确的，这是错误配置的服务器。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3227385|MappingJacksonHttpMessageConverter会自动将请求的content-type头设置为application/json，我猜您的服务器正在拒绝这个请求。你还没有告诉我们任何关于你的服务器设置的信息，所以我不能给你任何建议。|offset|length|style|CODE|3227386|entityMap^0|0|0|Y|1L|G|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|K|8|@$D|L|E|M|F|G]|$D|N|E|O|F|G]]|9|@]|A|$]]|$1|H|3|-4|5|6|7|P|8|@]|9|@]|A|$]]]|I|$]]

The "415 Unsupported Media Type" error is telling you that the server will not accept your POST request. Your request is absolutely fine, it's the server that's mis-configured.

<code>MappingJacksonHttpMessageConverter</code> will automatically set the request content-type header to <code>application/json</code>, and my guess is that your server is rejecting that. You haven't told us anything about your server setup, though, so I can't really advise you on that.

blocks|key|292277|text|按照指定的here，我想您需要为MappingJacksonHttpMessageConverter添加一个messageConverter|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|292278|entityMap|0|LINK|mutability|MUTABLE|url|http://static.springsource.org/spring/docs/3.0.x/spring-framework-reference/html/mvc.html#mvc-ann-requestbody^0|G|Y|1I|G|5|4|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@$9|O|A|P|B|C]|$9|Q|A|R|B|C]]|D|@$9|S|A|T|1|U]]|E|$]]|$1|F|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|G|$H|$5|I|J|K|E|$L|M]]]]

As specified <a href="http://static.springsource.org/spring/docs/3.0.x/spring-framework-reference/html/mvc.html#mvc-ann-requestbody" rel="noreferrer">here</a> I guess you need to add a <code>messageConverter</code> for <code>MappingJacksonHttpMessageConverter</code>

blocks|key|3227417|text|如果您使用的是Spring3.0，避免org.springframework.web.client.HttpClientErrorException:+415不支持的媒体类型异常的一个简单方法是在您的类路径中包含jackson+jar文件，并使用mvc:annotation-driven配置元素。As+specified+here。|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|CODE|entityRanges|data|3227418|我费了好大劲才弄明白为什么MappingJacksonHttpMessageConverter没有任何特殊的配置，mvc-ajax应用程序就能正常工作。如果你读过我上面紧密链接的那篇文章：|3227419|3227420|在幕后，Spring+MVC委托给一个HttpMessageConverter来执行序列化。在本例中，Spring+MVC调用了一个构建在Jackson+JSON处理器上的MappingJacksonHttpMessageConverter。当您使用mvc:注解驱动的配置元素并在类路径中出现Jackson时，将自动启用此实现。|blockquote|3227421|3227422|entityMap|0|LINK|mutability|MUTABLE|url|http://blog.springsource.com/2010/01/25/ajax-simplifications-in-spring-3-0/|1|https://src.springframework.org/svn/spring-samples/mvc-ajax/trunk/^0|J|1W|3F|L|45|H|0|0|D|Y|1L|8|1|0|0|0|0^^$0|@$1|2|3|4|5|6|7|X|8|@$9|Y|A|Z|B|C]|$9|10|A|11|B|D]]|E|@$9|12|A|13|1|14]]|F|$]]|$1|G|3|H|5|6|7|15|8|@$9|16|A|17|B|D]]|E|@$9|18|A|19|1|1A]]|F|$]]|$1|I|3|-4|5|6|7|1B|8|@]|E|@]|F|$]]|$1|J|3|K|5|L|7|1C|8|@]|E|@]|F|$]]|$1|M|3|-4|5|6|7|1D|8|@]|E|@]|F|$]]|$1|N|3|-4|5|6|7|1E|8|@]|E|@]|F|$]]]|O|$P|$5|Q|R|S|F|$T|U]]|V|$5|Q|R|S|F|$T|W]]]]

If you are using Spring 3.0, an easy way to avoid the org.springframework.web.client.HttpClientErrorException: 415 Unsupported Media Type exception, is to include the jackson jar files in your classpath, and use <code>mvc:annotation-driven</code> config element. <a href="http://blog.springsource.com/2010/01/25/ajax-simplifications-in-spring-3-0/">As specified here</a>.

I was pulling my hair out trying to figure out why the <a href="https://src.springframework.org/svn/spring-samples/mvc-ajax/trunk/">mvc-ajax</a> app worked without any special config for the <code>MappingJacksonHttpMessageConverter</code>. If you read the article I linked above closely: 

<blockquote>
 Underneath the covers, Spring MVC
 delegates to a HttpMessageConverter to
 perform the serialization. In this
 case, Spring MVC invokes a
 MappingJacksonHttpMessageConverter
 built on the Jackson JSON processor.
 This implementation is enabled
 automatically when you use the
 mvc:annotation-driven configuration
 element with Jackson present in your
 classpath.
</blockquote>

blocks|key|3227424|text|这个技巧对我很有效：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3227425|HttpHeaders+headers+=+new+HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);

HttpEntity<String>+entity+=+new+HttpEntity<String>(requestJson,+headers);
ResponseEntity<String>+response+=+restTemplate.put(url,+entity);|code-block|syntax|javascript|3227426|我希望这能帮到你|3227427|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

This technique worked for me:

<pre><code>HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);

HttpEntity&lt;String&gt; entity = new HttpEntity&lt;String&gt;(requestJson, headers);
ResponseEntity&lt;String&gt; response = restTemplate.put(url, entity);
</code></pre>

I hope this helps

blocks|key|290181|text|我一直在JSONObjects中使用rest模板，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|290182|//+create+request+body
JSONObject+request+=+new+JSONObject();
request.put("username",+name);
request.put("password",+password);

//+set+headers
HttpHeaders+headers+=+new+HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);
HttpEntity<String>+entity+=+new+HttpEntity<String>(request.toString(),+headers);

//+send+request+and+parse+result
ResponseEntity<String>+loginResponse+=+restTemplate
++.exchange(urlString,+HttpMethod.POST,+entity,+String.class);
if+(loginResponse.getStatusCode()+==+HttpStatus.OK)+{
++JSONObject+userJson+=+new+JSONObject(loginResponse.getBody());
}+else+if+(loginResponse.getStatusCode()+==+HttpStatus.UNAUTHORIZED)+{
++//+nono...+bad+credentials
}|code-block|syntax|javascript|290183|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I've been using rest template with JSONObjects as follow:

<pre><code>// create request body
JSONObject request = new JSONObject();
request.put("username", name);
request.put("password", password);

// set headers
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);
HttpEntity&lt;String&gt; entity = new HttpEntity&lt;String&gt;(request.toString(), headers);

// send request and parse result
ResponseEntity&lt;String&gt; loginResponse = restTemplate
 .exchange(urlString, HttpMethod.POST, entity, String.class);
if (loginResponse.getStatusCode() == HttpStatus.OK) {
 JSONObject userJson = new JSONObject(loginResponse.getBody());
} else if (loginResponse.getStatusCode() == HttpStatus.UNAUTHORIZED) {
 // nono... bad credentials
}
</code></pre>

blocks|key|3227429|text|For+me在此设置中出现错误：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3227430|AndroidAnnotations+Spring+Android+RestTemplate+Module和...|offset|length|style|CODE|3227431|GsonHttpMessageConverter|3227432|Android注解在转换为生成不带参数的POST请求时有一些问题。简单的参数new+Object()为我解决了这个问题。|3227433|entityMap^0|0|0|I|J|Y|0|0|O|0|K|4|12|C|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|O|8|@$D|P|E|Q|F|G]|$D|R|E|S|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|T|8|@$D|U|E|V|F|G]]|9|@]|A|$]]|$1|J|3|K|5|6|7|W|8|@$D|X|E|Y|F|G]|$D|Z|E|10|F|G]]|9|@]|A|$]]|$1|L|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|M|$]]

For me error occurred with this setup:

<code>AndroidAnnotations</code>
<code>Spring Android RestTemplate Module</code>
and ...

<code>GsonHttpMessageConverter</code>

Android annotations has some problems with this converted to generate <code>POST</code> request without parameter. Simply parameter <code>new Object()</code> solved it for me.

blocks|key|3013386|text|在尝试调试REST端点时，我遇到了这个问题。下面是一个基本的示例，它使用Spring的RestTemplate类来发出我使用的POST请求。我花了相当长的时间把不同地方的代码拼凑在一起，得到一个工作版本。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3013387|RestTemplate+restTemplate+=+new+RestTemplate();

String+url+=+"endpoint+url";
String+requestJson+=+"{\"queriedQuestion\":\"Is+there+pain+in+your+hand?\"}";
HttpHeaders+headers+=+new+HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);

HttpEntity<String>+entity+=+new+HttpEntity<String>(requestJson,headers);
String+answer+=+restTemplate.postForObject(url,+entity,+String.class);
System.out.println(answer);|code-block|syntax|javascript|3013388|对于特定的JSON解析器，我的rest端点在字段名两边使用了所需的双引号，这就是为什么我在requestJson字符串中转义了双引号。|3013389|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

I ran across this problem when attempting to debug a REST endpoint. Here is a basic example using Spring's RestTemplate class to make a POST request that I used. It took me quite a bit of a long time to piece together code from different places to get a working version.

<pre><code>RestTemplate restTemplate = new RestTemplate();

String url = "endpoint url";
String requestJson = "{\"queriedQuestion\":\"Is there pain in your hand?\"}";
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);

HttpEntity&lt;String&gt; entity = new HttpEntity&lt;String&gt;(requestJson,headers);
String answer = restTemplate.postForObject(url, entity, String.class);
System.out.println(answer);
</code></pre>

The particular JSON parser my rest endpoint was using needed double quotes around field names so that's why I've escaped the double quotes in my requestJson String.

blocks|key|295222|text|我遇到了这个问题，我在客户端使用Spring的RestTemplate，在服务器端使用Spring+Web。这两个API都有非常差的错误报告，这使得它们非常难以开发。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|295223|经过几个小时的各种尝试之后，我发现这个问题是由于为POST主体而不是预期的列表传入空引用而导致的。我假设RestTemplate不能从空对象确定内容类型，但不会抱怨这一点。在添加了正确的头之后，在进入我的服务方法之前，我开始在Spring中获得一个不同的服务器端异常。|295224|修复方法是从客户端传入一个空列表，而不是null。由于默认的content-type用于非空对象，因此不需要标头。|295225|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

I was getting this problem and I'm using Spring's RestTemplate on the client and Spring Web on the server. Both APIs have very poor error reporting, making them extremely difficult to develop with. 

After many hours of trying all sorts of experiments I figured out that the issue was being caused by passing in a null reference for the POST body instead of the expected List. I presume that RestTemplate cannot determine the content-type from a null object, but doesn't complain about it. After adding the correct headers, I started getting a different server-side exception in Spring before entering my service method. 

The fix was to pass in an empty List from the client instead of null. No headers are required since the default content-type is used for non-null objects.

blocks|key|3013414|text|这段代码对我来说很有效；|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3013415|RestTemplate+restTemplate+=+new+RestTemplate();
Payment+payment+=+new+Payment("Aa4bhs");
MultiValueMap<String,+Object>+map+=+new+LinkedMultiValueMap<String,+Object>();
map.add("payment",+payment);
HttpEntity<MultiValueMap<String,+Object>>+httpEntity+=+new+HttpEntity<MultiValueMap<String,+Object>>(map,+headerObject);

Payment+res+=+restTemplate.postForObject(url,+httpEntity,+Payment.class);|code-block|syntax|javascript|3013416|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This code is working for me;

<pre><code>RestTemplate restTemplate = new RestTemplate();
Payment payment = new Payment("Aa4bhs");
MultiValueMap&lt;String, Object&gt; map = new LinkedMultiValueMap&lt;String, Object&gt;();
map.add("payment", payment);
HttpEntity&lt;MultiValueMap&lt;String, Object&gt;&gt; httpEntity = new HttpEntity&lt;MultiValueMap&lt;String, Object&gt;&gt;(map, headerObject);

Payment res = restTemplate.postForObject(url, httpEntity, Payment.class);
</code></pre>

blocks|key|290213|text|我就是这样做的，而且效果很好。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|290214|HttpHeaders+headers+=+createHttpHeaders(map);
public+HttpHeaders+createHttpHeaders(Map<String,+String>+map)
{+++
++++HttpHeaders+headers+=+new+HttpHeaders();
++++headers.setContentType(MediaType.APPLICATION_JSON);
++++for+(Entry<String,+String>+entry+:+map.entrySet())+{
++++++++headers.add(entry.getKey(),entry.getValue());
++++}
++++return+headers;
}|code-block|syntax|javascript|290215|//在此处传入头部|290216|+String+requestJson+=+"{+//+Construct+your+JSON+here+}";
logger.info("Request+JSON+="%2BrequestJson);
HttpEntity<String>+entity+=+new+HttpEntity<String>(requestJson,+headers);
ResponseEntity<String>+response+=+restTemplate.exchange(url,+HttpMethod.POST,+entity,+String.class);
logger.info("Result+-+status+("%2B+response.getStatusCode()+%2B+")+has+body:+"+%2B+response.hasBody());
logger.info("Response+="%2Bresponse.getBody());|290217|希望这能有所帮助|290218|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

I'm doing in this way and it works .

<pre><code>HttpHeaders headers = createHttpHeaders(map);
public HttpHeaders createHttpHeaders(Map&lt;String, String&gt; map)
{ 
 HttpHeaders headers = new HttpHeaders();
 headers.setContentType(MediaType.APPLICATION_JSON);
 for (Entry&lt;String, String&gt; entry : map.entrySet()) {
 headers.add(entry.getKey(),entry.getValue());
 }
 return headers;
}
</code></pre>

// Pass headers here

<pre><code> String requestJson = "{ // Construct your JSON here }";
logger.info("Request JSON ="+requestJson);
HttpEntity&lt;String&gt; entity = new HttpEntity&lt;String&gt;(requestJson, headers);
ResponseEntity&lt;String&gt; response = restTemplate.exchange(url, HttpMethod.POST, entity, String.class);
logger.info("Result - status ("+ response.getStatusCode() + ") has body: " + response.hasBody());
logger.info("Response ="+response.getBody());
</code></pre>

Hope this helps

blocks|key|3013436|text|如果您不想处理响应|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3013437|private+RestTemplate+restTemplate+=+new+RestTemplate();
restTemplate.postForObject(serviceURL,+request,+Void.class);|code-block|syntax|javascript|3013438|如果您需要响应流程|3013439|String+result+=+restTemplate.postForObject(url,+entity,+String.class);|3013440|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

If you dont want to process response 

<pre><code>private RestTemplate restTemplate = new RestTemplate();
restTemplate.postForObject(serviceURL, request, Void.class);
</code></pre>

If you need response to process

<pre><code>String result = restTemplate.postForObject(url, entity, String.class);
</code></pre>

blocks|key|3013447|text|为什么要比必须更努力地工作呢？postForEntity接受一个简单的Map对象作为输入。在Spring中为给定的REST端点编写测试时，下面的代码对我来说很好用。我相信这是在Spring中发出JSON+POST请求的最简单的方式：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3013448|@Test
public+void+shouldLoginSuccessfully()+{
++//+'restTemplate'+below+has+been+@Autowired+prior+to+this
++Map+map+=+new+HashMap<String,+String>();
++map.put("username",+"bob123");
++map.put("password",+"myP@ssw0rd");
++ResponseEntity<Void>+resp+=+restTemplate.postForEntity(
++++++"http://localhost:8000/login",
++++++map,
++++++Void.class);
++assertThat(resp.getStatusCode()).isEqualTo(HttpStatus.OK);
}|code-block|syntax|javascript|3013449|entityMap^0|F|D|Z|3|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|L|$]]

Why work harder than you have to? <code>postForEntity</code> accepts a simple <code>Map</code> object as input. The following works fine for me while writing tests for a given REST endpoint in Spring. I believe it's the simplest possible way of making a JSON POST request in Spring:

<pre><code>@Test
public void shouldLoginSuccessfully() {
 // 'restTemplate' below has been @Autowired prior to this
 Map map = new HashMap&lt;String, String&gt;();
 map.put("username", "bob123");
 map.put("password", "myP@ssw0rd");
 ResponseEntity&lt;Void&gt; resp = restTemplate.postForEntity(
 "http://localhost:8000/login",
 map,
 Void.class);
 assertThat(resp.getStatusCode()).isEqualTo(HttpStatus.OK);
}
</code></pre>

blocks|key|290240|text|如果您不想自己映射JSON，可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|290241|RestTemplate+restTemplate+=+new+RestTemplate();
restTemplate.setMessageConverters(Arrays.asList(new+MappingJackson2HttpMessageConverter()));
ResponseEntity<String>+result+=+restTemplate.postForEntity(uri,+yourObject,+String.class);|code-block|syntax|javascript|290242|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you don't want to map the JSON by yourself, you can do it as follows:

<pre><code>RestTemplate restTemplate = new RestTemplate();
restTemplate.setMessageConverters(Arrays.asList(new MappingJackson2HttpMessageConverter()));
ResponseEntity&lt;String&gt; result = restTemplate.postForEntity(uri, yourObject, String.class);
</code></pre>

blocks|key|292386|text|我在spring+boot中尝试了如下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|292387|ParameterizedTypeReference<Map<String,+Object>>+typeRef+=+new+ParameterizedTypeReference<Map<String,+Object>>()+{};
public+Map<String,+Object>+processResponse(String+urlendpoint)
{
++++try{
++++
++++++++HttpHeaders+headers+=+new+HttpHeaders();
++++++++headers.setContentType(MediaType.APPLICATION_JSON);
++++++++//reqobj
++++++++JSONObject+request+=+new+JSONObject();
++++++++request.put("username",+name);
++++++++//Or+Hashmap+
++++++++Map<String,+Object>+reqbody+=++new+HashMap<>();
++++++++reqbody.put("username",username);
++++++++Gson+gson+=+new+Gson();//mvn+plugin+to+convert+map+to+String
++++++++HttpEntity<String>+entity+=+new+HttpEntity<>(+gson.toJson(reqbody),+headers);
++++++++ResponseEntity<Map<String,+Object>>+response+=+resttemplate.exchange(urlendpoint,+HttpMethod.POST,+entity,+typeRef);//example+of+post+req+with+json+as+request+payload
++++++++if(Integer.parseInt(response.getStatusCode().toString())+==+HttpURLConnection.HTTP_OK)
++++++++{
++++++++++++Map<String,+Object>++responsedetails+=+response.getBody();
++++++++++++System.out.println(responsedetails);//whole+json+response+as+map+object
++++++++++++return+responsedetails;
++++++++}
++++}+catch+(Exception+e)+{
++++++++//+TODO:+handle+exception
++++++++System.err.println(e);
++++}
++++return+null;
}|code-block|syntax|javascript|292388|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I tried as following in spring boot:
<pre><code>ParameterizedTypeReference&lt;Map&lt;String, Object&gt;&gt; typeRef = new ParameterizedTypeReference&lt;Map&lt;String, Object&gt;&gt;() {};
public Map&lt;String, Object&gt; processResponse(String urlendpoint)
{
 try{
 
 HttpHeaders headers = new HttpHeaders();
 headers.setContentType(MediaType.APPLICATION_JSON);
 //reqobj
 JSONObject request = new JSONObject();
 request.put(&quot;username&quot;, name);
 //Or Hashmap 
 Map&lt;String, Object&gt; reqbody = new HashMap&lt;&gt;();
 reqbody.put(&quot;username&quot;,username);
 Gson gson = new Gson();//mvn plugin to convert map to String
 HttpEntity&lt;String&gt; entity = new HttpEntity&lt;&gt;( gson.toJson(reqbody), headers);
 ResponseEntity&lt;Map&lt;String, Object&gt;&gt; response = resttemplate.exchange(urlendpoint, HttpMethod.POST, entity, typeRef);//example of post req with json as request payload
 if(Integer.parseInt(response.getStatusCode().toString()) == HttpURLConnection.HTTP_OK)
 {
 Map&lt;String, Object&gt; responsedetails = response.getBody();
 System.out.println(responsedetails);//whole json response as map object
 return responsedetails;
 }
 } catch (Exception e) {
 // TODO: handle exception
 System.err.println(e);
 }
 return null;
}
</code></pre>

blocks|key|3013518|text|您可以将请求作为JSON对象进行|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3013519|JSONObject+request+=+new+JSONObject();
request.put("name","abc");+
ResponseEntity<JSONObject>+response+=restTemplate.postForEntity(append_url,request,JSONObject.class);++++++++++++++++++++++++++++++++++++++++++++++++++++++++++`enter+code+here`|code-block|syntax|javascript|3013520|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can make request as a JSON object
<pre><code>JSONObject request = new JSONObject();
request.put(&quot;name&quot;,&quot;abc&quot;); 
ResponseEntity&lt;JSONObject&gt; response =restTemplate.postForEntity(append_url,request,JSONObject.class); `enter code here`
</code></pre>

I didn't find any example how to solve my problem, so I want to ask you for help. I can't simply send POST request using RestTemplate object in JSON

Every time I get:

<blockquote>
 org.springframework.web.client.HttpClientErrorException: 415 Unsupported Media Type
</blockquote>

I use RestTemplate in this way:

<pre><code>...
restTemplate = new RestTemplate();
List&lt;HttpMessageConverter&lt;?&gt;&gt; list = new ArrayList&lt;HttpMessageConverter&lt;?&gt;&gt;();
list.add(new MappingJacksonHttpMessageConverter());
restTemplate.setMessageConverters(list);
...
Payment payment= new Payment("Aa4bhs");
Payment res = restTemplate.postForObject("http://localhost:8080/aurest/rest/payment", payment, Payment.class);
</code></pre>

What is my fault?

POST request via RestTemplate in JSON

服务器

Android

JSON

我没有找到任何解决我的问题的例子，所以我想向你寻求帮助。我不能简单地使用JSON中的RestTemplate对象发送POST请求每次我得到： org.springframework.web.client.HttpClientErrorException: 415不支持的媒体类型我以这种方式使用RestTemplate：...

问在JSON中通过RestTemplate发送POST请求
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