如何使用非法名称访问此对象属性？
如何使用非法名称访问此对象属性？
提问于 2009-04-16 23:33:28
我使用的是某个人编写的用来与BaseCamp应用程序接口的PHP类。
我正在做的特定调用是检索待办事项列表中的项目，这很好用。
我的问题是，我不确定如何只访问返回的对象的todo-items属性。下面是返回对象的var_dump：
object(stdClass)[6]
public 'completed-count' => string '0' (length=1)
public 'description' => string 'Description String' (length=89)
public 'id' => string '12345' (length=7)
public 'milestone-id' => string '' (length=0)
public 'name' => string 'Error Reports' (length=13)
public 'position' => string '1' (length=1)
public 'private' => string 'false' (length=5)
public 'project-id' => string '58904' (length=7)
public 'tracked' => string 'false' (length=5)
public 'uncompleted-count' => string '1' (length=1)
public 'todo-items' =>
object(stdClass)[3]
public 'todo-item' =>
object(stdClass)[5]
public 'completed' => string 'false' (length=5)
public 'content' => string 'content string here' (length=133)
public 'created-on' => string '2009-04-16T20:33:31Z' (length=20)
public 'creator-id' => string '23423' (length=7)
public 'id' => string '234' (length=8)
public 'position' => string '1' (length=1)
public 'responsible-party-id' => string '2844499' (length=7)
public 'responsible-party-type' => string 'Person' (length=6)
public 'todo-list-id' => string '234234' (length=7)
public 'complete' => string 'false' (length=5)如何访问此对象的todo-items部分？
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原文链接：
https://stackoverflow.com/questions/758449
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