blocks|key|619676|text|只需像这样调用parentViewController，您就可以再往前走：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|619677|self.parentViewController.parentViewController+...以此类推，直到你找到合适的那个。|offset|length|style|CODE|619678|entityMap^0|0|0|1A|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|K|8|@$D|L|E|M|F|G]]|9|@]|A|$]]|$1|H|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|I|$]]

You can always go further back just by calling parentViewController like so:

<code>self.parentViewController.parentViewController</code> .... and so on until you reach the right one.

blocks|key|619786|text|我做这类事情的方法是简单地创建一个委托。在AskPasswordViewController的标题中，放入|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|619787|id+delegate;|code-block|syntax|javascript|619788|和|619789|@property+(nonatomic,+assign)+id+delegate;|619790|在实现文件中综合它。然后，在分配/初始化模态控制器之后，在呈现它之前，设置modalViewController.delegate+=+self;。然后，在模态控制器中，您可以调用self.delegate来从呈现它的视图控制器获取信息。我希望这能帮到你|619791|entityMap^0|L|P|0|0|0|0|11|10|2I|D|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|Y|8|@$9|Z|A|10|B|C]|$9|11|A|12|B|C]]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|13|8|@]|D|@]|E|$]]]|R|$]]

The way I'd go about something like this is to simply create a delegate. In <code>AskPasswordViewController</code>'s header, put

<pre><code>id delegate;
</code></pre>

and 

<pre><code>@property (nonatomic, assign) id delegate;
</code></pre>

Synthesize it in the implementation file. Then after you alloc/init the modal controller, and before you present it, set <code>modalViewController.delegate = self;</code>. Then within the modal controller, you can call <code>self.delegate</code> to get information from the view controller that presented it. I hope this helps

blocks|key|619829|text|//You+have+to+get+the+root,+iterate+through+the+root's+ViewControllers+and+then+ask+for+the+ParentViewController.
++++UINavigationController+​*root+=+(UINavigationController*​)[[(AppDelegate*)+[[UIApplication+sharedApplication]delegate]+window]+rootViewController];
+++++++++++for+(UIViewController+*VC+in+root.viewControllers)+{
+++++++++++++++if([VC+isKindOfClass:[YourParentViewController+class]]){
+++++++++++++++++++YourParentViewController*++parent+=+(YourParentViewController*)VC;
+++++++++++++++++++[parent+callMethod];+//+your+code+here
+++++++++++++++++++[self+dismissViewControllerAnimated:YES+completion:nil];
+++++++++++++++}
+++++++++++}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|619830|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>//You have to get the root, iterate through the root's ViewControllers and then ask for the ParentViewController.
 UINavigationController ​*root = (UINavigationController*​)[[(AppDelegate*) [[UIApplication sharedApplication]delegate] window] rootViewController];
 for (UIViewController *VC in root.viewControllers) {
 if([VC isKindOfClass:[YourParentViewController class]]){
 YourParentViewController* parent = (YourParentViewController*)VC;
 [parent callMethod]; // your code here
 [self dismissViewControllerAnimated:YES completion:nil];
 }
 }
</code></pre>

blocks|key|619851|text|除了Vibhor+Goyal+-有时，self.presentingViewController注册为NavigationController。因此，请尝试：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|619852|if+let+vc+=+self.presentingViewController.childViewControllers.last+as?+YourViewController+{
//+do+stuff+here
}|code-block|syntax|javascript|619853|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Addition to Vibhor Goyal
- Sometimes, self.presentingViewController registers as NavigationController. Therefore try:

<pre><code>if let vc = self.presentingViewController.childViewControllers.last as? YourViewController {
// do stuff here
}
</code></pre>

blocks|key|619904|text|如果presentingViewController给了你意想不到的结果，而你又不想去摆弄它，那就这么做吧：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|619905|class+MyViewController:+UIViewController+{

++++private+weak+var+presenter:+UIViewController?

++++init(presenter:+UIViewController)+{
++++++++self.presenter+=+presenter
++++++++super.init(nibName:+nil,+bundle:+nil)
++++++++...
++++}
++++
++++...
}|code-block|syntax|javascript|619906|entityMap^0|2|O|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

If <code>presentingViewController</code> gives you unexpected results and you don't want to fiddle with it, just do:
<pre><code>class MyViewController: UIViewController {

 private weak var presenter: UIViewController?

 init(presenter: UIViewController) {
 self.presenter = presenter
 super.init(nibName: nil, bundle: nil)
 ...
 }
 
 ...
}
</code></pre>

I'm presenting a ViewController modally.
How can I access the parent view controller ?

My architecture is TabBarController=>VC1=>VC2=>VC3=>MVC1, and I want to reach VC3 from MVC1.

In VC3, I have this code : 

<pre><code>- (void) editAd{
 AskPasswordViewController *modalViewController = [[AskPasswordViewController alloc] initWithNibName:@"AskPasswordView" bundle:nil];

 NSLog(@"modalparent class=%@", [[modalViewController parentViewController] class]);

 [self presentModalViewController:modalViewController animated:YES];
 [modalViewController release];
}
</code></pre>

I tried this in MVC1:

<pre><code>- (void) sendRequest {
 NSLog(@"classe : %@",[[self parentViewController] class] );
}
</code></pre>

but it returns my TabBarViewController...

Access modal view controller parent

我正在介绍一个模态的ViewController。如何访问父视图控制器？我的架构是TabBarController=>VC1=>VC2=>VC3=>MVC1，我想从MVC1到达VC3。在VC3中，我有这样的代码：- (void) editAd{    AskPasswordViewController *modalVi...

问访问模式视图控制器父级
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