blocks|key|289836|text|您需要使用Instagrams+API将您的username转换为id。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|289837|如果我没记错的话，您可以使用users/search查找用户名并从中获取id|289838|entityMap^0|5|E|M|8|X|2|0|E|C|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]|$9|M|A|N|B|C]|$9|O|A|P|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|H|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|I|$]]

You need to use <code>Instagrams API</code> to convert your <code>username</code> to <code>id</code>.

If I remember correctly you use <code>users/search</code> to find the username and get the id from there

blocks|key|289877|text|要获取您的id，请向Instagram+API+users/self/feed终结点发出经过身份验证的请求。在其他数据中，响应将包含用户名以及用户的id。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|289878|entityMap|0|LINK|mutability|MUTABLE|url|http://instagram.com/developer/endpoints/users/#get_users_feed^0|O|F|O|F|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@$9|O|A|P|B|C]]|D|@$9|Q|A|R|1|S]]|E|$]]|$1|F|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|G|$H|$5|I|J|K|E|$L|M]]]]

to get your id, make an authenticated request to the Instagram API <a href="http://instagram.com/developer/endpoints/users/#get_users_feed" rel="nofollow"><code>users/self/feed</code></a> endpoint. the response will contain, among other data, the username as well as the id of the user.

blocks|key|506713|text|尽管它不再列在API文档页面上，但我发现了一个thread，其中提到您可以使用self代替user-id作为users/{user-id}端点，它将返回当前经过身份验证的用户的信息。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|506714|因此，users/self与对users/{some-user-id}的显式调用相同，它将用户的id作为有效负载的一部分。通过身份验证后，只需调用users/self，结果将包含当前已通过身份验证的用户的id，如下所示：|506715|{
++++"data":+{
++++++++"id":+"1574083",
++++++++"username":+"snoopdogg",
++++++++"full_name":+"Snoop+Dogg",
++++++++"profile_picture":+"http://distillery.s3.amazonaws.com/profiles/profile_1574083_75sq_1295469061.jpg",
++++++++"bio":+"This+is+my+bio",
++++++++"website":+"http://snoopdogg.com",
++++++++"counts":+{
++++++++++++"media":+1320,
++++++++++++"follows":+420,
++++++++++++"followed_by":+3410
++++++++}
}|code-block|syntax|javascript|506716|entityMap|0|LINK|mutability|MUTABLE|url|https://groups.google.com/forum/?fromgroups=#!searchin/instagram-api-developers/get%252420authenticated%252420user%2527s%252420info/instagram-api-developers/pgdmEBYmDpo/oYPqHQkb0RsJ|1|http://instagram.com/developer/endpoints/users/#get_users^0|13|4|19|7|1I|F|N|6|0|1I|F|1|0|3|A|F|K|21|A|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]|$9|11|A|12|B|C]]|D|@$9|13|A|14|1|15]|$9|16|A|17|1|18]]|E|$]]|$1|F|3|G|5|6|7|19|8|@$9|1A|A|1B|B|C]|$9|1C|A|1D|B|C]|$9|1E|A|1F|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|1G|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|1H|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]|U|$5|P|Q|R|E|$S|V]]]]

Although it's not listed on the API doc page anymore, I found a <a href="https://groups.google.com/forum/?fromgroups=#!searchin/instagram-api-developers/get%2420authenticated%2420user%27s%2420info/instagram-api-developers/pgdmEBYmDpo/oYPqHQkb0RsJ" rel="nofollow">thread</a> that mentions that you can use <code>self</code> in place of <code>user-id</code> for the <a href="http://instagram.com/developer/endpoints/users/#get_users" rel="nofollow"><code>users/{user-id}</code></a> endpoint and it'll return the currently authenticated user's info.

So, <code>users/self</code> is the same as an explicit call to <code>users/{some-user-id}</code> and contains the user's id as part of the payload. Once you're authenticated, just make a call to <code>users/self</code> and the result will include the currently authenticated user's id, like so:

<pre><code>{
 "data": {
 "id": "1574083",
 "username": "snoopdogg",
 "full_name": "Snoop Dogg",
 "profile_picture": "http://distillery.s3.amazonaws.com/profiles/profile_1574083_75sq_1295469061.jpg",
 "bio": "This is my bio",
 "website": "http://snoopdogg.com",
 "counts": {
 "media": 1320,
 "follows": 420,
 "followed_by": 3410
 }
}
</code></pre>

blocks|key|506779|text|在浏览器中输入此url以及您要查找的用户名和访问令牌。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|506780|https://api.instagram.com/v1/users/search?q=[USERNAME]&access_token=[ACCESS+TOKEN]|code-block|syntax|javascript|506781|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Enter this url in your browser with the users name you want to find and your access token

<pre><code>https://api.instagram.com/v1/users/search?q=[USERNAME]&amp;access_token=[ACCESS TOKEN]
</code></pre>

blocks|key|506836|text|Go+to+the+api+console+&复制文本字段中的链接https://api.instagram.com/v1/users/self，并使用您的instagram+id和密码进行身份验证，您将获得您的id作为响应|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|506837|entityMap|0|LINK|mutability|MUTABLE|url|http://instagram.com/developer/api-console/^0|X|13|0|L|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@$9|O|A|P|B|C]]|D|@$9|Q|A|R|1|S]]|E|$]]|$1|F|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|G|$H|$5|I|J|K|E|$L|M]]]]

<a href="http://instagram.com/developer/api-console/" rel="nofollow">Go to the api console</a> &amp; copy link <code>https://api.instagram.com/v1/users/self</code> in text field and authenticate using your instagram id &amp; password, you will get your id in response

blocks|key|290105|text|这可以通过apigee.com开发者站点上的Instagram+API+access+here来完成。登录后，单击"/users/search“API调用。从那里你可以搜索任何用户名并检索它的id。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|290106|{
"data":+[{
++++"username":+"jack",
++++"first_name":+"Jack",
++++"profile_picture":+"http://distillery.s3.amazonaws.com/profiles/profile_66_75sq.jpg",
++++"id":+"66",
++++"last_name":+"Dorsey"
},
{
++++"username":+"sammyjack",
++++"first_name":+"Sammy",
++++"profile_picture":+"http://distillery.s3.amazonaws.com/profiles/profile_29648_75sq_1294520029.jpg",
++++"id":+"29648",
++++"last_name":+"Jack"
},
{
++++"username":+"jacktiddy",
++++"first_name":+"Jack",
++++"profile_picture":+"http://distillery.s3.amazonaws.com/profiles/profile_13096_75sq_1286441317.jpg",
++++"id":+"13096",
++++"last_name":+"Tiddy"
}]}|code-block|syntax|javascript|290107|如果您已经有了访问代码，也可以这样做：https://api.instagram.com/v1/users/search?q=USERNAME&access_token=ACCESS_TOKEN|290108|entityMap|0|LINK|mutability|MUTABLE|url|http://instagram.com/developer/api-console/|1|https://api.instagram.com/v1/users/search?q=USERNAME&access_token=ACCESS_TOKEN^0|17|4|0|0|0|J|26|1|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@$A|V|B|W|1|X]]|C|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|Z|8|@]|9|@$A|10|B|11|1|12]]|C|$]]|$1|K|3|-4|5|6|7|13|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]|S|$5|N|O|P|C|$Q|T]]]]

This can be done through apigee.com Instagram API access <a href="http://instagram.com/developer/api-console/" rel="nofollow">here</a> on Instagram's developer site. After loging in, click on the "/users/search" API call. From there you can search any username and retrieve its id.

<pre><code>{
"data": [{
 "username": "jack",
 "first_name": "Jack",
 "profile_picture": "http://distillery.s3.amazonaws.com/profiles/profile_66_75sq.jpg",
 "id": "66",
 "last_name": "Dorsey"
},
{
 "username": "sammyjack",
 "first_name": "Sammy",
 "profile_picture": "http://distillery.s3.amazonaws.com/profiles/profile_29648_75sq_1294520029.jpg",
 "id": "29648",
 "last_name": "Jack"
},
{
 "username": "jacktiddy",
 "first_name": "Jack",
 "profile_picture": "http://distillery.s3.amazonaws.com/profiles/profile_13096_75sq_1286441317.jpg",
 "id": "13096",
 "last_name": "Tiddy"
}]}
</code></pre>

 
If you already have an access code, it can also be done like this:
<a href="https://api.instagram.com/v1/users/search?q=USERNAME&amp;access_token=ACCESS_TOKEN" rel="nofollow">https://api.instagram.com/v1/users/search?q=USERNAME&amp;access_token=ACCESS_TOKEN</a>

blocks|key|506940|text|人们可以检查Instagram用户页面来获取id，而不是使用API。PHP示例代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|506941|$html+=+file_get_contents("http://instagram.com/<username>");
$doc+=+new+DOMDocument();
$doc->loadHTML($html);

$xpath+=+new+DOMXPath($doc);
$js+=+$xpath->query('//body/script[@type="text/javascript"]')->item(1)->nodeValue;

$start+=+strpos($js,+'{');
$end+=+strrpos($js,+';');
$json+=+substr($js,+$start,+$end+-+$start);

$data+=+json_decode($json,+true);
$data+=+$data["entry_data"]["UserProfile"][0];
#+The+"userMedia"+entry+of+$data+now+has+the+same+structure+as+the+"data"+field
#+in+Instagram+API+responses+to+user+endpoints+queries

echo+$data["user"]["id"];|code-block|syntax|javascript|506942|当然，如果Instagram改变了它的页面格式，这段代码必须进行调整。|506943|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Instead of using the API, one can examine the Instagram userpage to get the id. Example code in PHP:

<pre class="lang-php prettyprint-override"><code>$html = file_get_contents("http://instagram.com/&lt;username&gt;");
$doc = new DOMDocument();
$doc-&gt;loadHTML($html);

$xpath = new DOMXPath($doc);
$js = $xpath-&gt;query('//body/script[@type="text/javascript"]')-&gt;item(1)-&gt;nodeValue;

$start = strpos($js, '{');
$end = strrpos($js, ';');
$json = substr($js, $start, $end - $start);

$data = json_decode($json, true);
$data = $data["entry_data"]["UserProfile"][0];
# The "userMedia" entry of $data now has the same structure as the "data" field
# in Instagram API responses to user endpoints queries

echo $data["user"]["id"];
</code></pre>

Of course, this code has to be adapted if Instagram changes its page format.

blocks|key|507001|text|嗯，你可以把这个链接叫做|type|unstyled|depth|inlineStyleRanges|entityRanges|data|507002|http://jelled.com/ajax/instagram?do=username&username=[USER_NAME_GOES_HERE]&format=json|offset|length|507003|entityMap|0|LINK|mutability|MUTABLE|url|http://jelled.com/ajax/instagram?do=username&username=%255bUSER_NAME_GOES_HERE%255d&format=json^0|0|0|2F|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|O|8|@]|9|@$D|P|E|Q|1|R]]|A|$]]|$1|F|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|G|$H|$5|I|J|K|A|$L|M]]]]

Well you can just call this link

<a href="http://jelled.com/ajax/instagram?do=username&amp;username=%5bUSER_NAME_GOES_HERE%5d&amp;format=json" rel="nofollow">http://jelled.com/ajax/instagram?do=username&amp;username=[USER_NAME_GOES_HERE]&amp;format=json</a>

blocks|key|507046|text|目前没有直接的Instagram+API来从用户名中获取用户id。您需要调用GET+/users/search接口，然后迭代结果，并检查username字段的值是否等于您的用户名，然后获取id。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|507047|entityMap|0|LINK|mutability|MUTABLE|url|http://instagram.com/developer/endpoints/users/#get_users_search^0|1W|8|2M|2|12|H|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@$9|O|A|P|B|C]|$9|Q|A|R|B|C]]|D|@$9|S|A|T|1|U]]|E|$]]|$1|F|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|G|$H|$5|I|J|K|E|$L|M]]]]

Currently there is no direct Instagram API to get user id from user name. You need to call the <a href="http://instagram.com/developer/endpoints/users/#get_users_search">GET /users/search</a> API and then iterate the results and check if the <code>username</code> field value is equal to your username or not, then you grab the <code>id</code>.

blocks|key|290277|text|首先在Instagram上创建应用程序并获取应用程序的客户端Id|type|unstyled|depth|inlineStyleRanges|entityRanges|data|290278|http://instagram.com/developer/|offset|length|290279|现在只需通过替换您的用户名和客户端Id+https://api.instagram.com/v1/users/search?q=[Your-username]&client_id=[Your-Client-Id]，将粘贴以下网址复制到浏览器窗口中|290280|您将获得一个Json结果，其中包含有关您的帐户的一般信息以及您的数字用户Id|290281|entityMap|0|LINK|mutability|MUTABLE|url|1|https://api.instagram.com/v1/users/search?q=[Your-username]&client_id=[Your-Client-Id]^0|0|0|V|0|0|K|2E|1|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@]|9|@$D|U|E|V|1|W]]|A|$]]|$1|F|3|G|5|6|7|X|8|@]|9|@$D|Y|E|Z|1|10]]|A|$]]|$1|H|3|I|5|6|7|11|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|K|$L|$5|M|N|O|A|$P|C]]|Q|$5|M|N|O|A|$P|R]]]]

First Create an Application on Instagram and get Client Id for your application

<a href="http://instagram.com/developer/" rel="nofollow">http://instagram.com/developer/</a>

Now just copy paste following Url into browser window by replacing your Username and your Client Id
<a href="https://api.instagram.com/v1/users/search?q=[Your-username]&amp;client_id=[Your-Client-Id]" rel="nofollow">https://api.instagram.com/v1/users/search?q=[Your-username]&amp;client_id=[Your-Client-Id]</a>

you will get a Json Result containing General Information about your account along with your Numeric user Id

blocks|key|507123|text|下面是如何从用户名中检索用户id的方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|507124|$url+=+"https://api.instagram.com/v1/users/search?q=[username]&access_token=[your_token]";
$obj+=+json_decode(@file_get_contents($url));
echo+$obj->data[0]->id;|code-block|syntax|javascript|507125|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here is how you can retrieve your user id from a username:

<pre><code>$url = "https://api.instagram.com/v1/users/search?q=[username]&amp;access_token=[your_token]";
$obj = json_decode(@file_get_contents($url));
echo $obj-&gt;data[0]-&gt;id;
</code></pre>

blocks|key|290352|text|https://api.instagram.com/v1/users/search?q="[USERNAME]"&access_token=[ACCESS+TOKEN]|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|290353|请注意引号。|unstyled|290354|这并不总是返回有效的结果，但比不带引号的结果更常见：|290355|https://api.instagram.com/v1/users/search?q="self"&count=1&access_token=[ACCESS+TOKEN]+|290356|返回用户"self“(id:+311176867)|290357|https://api.instagram.com/v1/users/search?q=self&count=1&access_token=[ACCESS+TOKEN]|290358|返回用户"super_selfie“(id:+1422944651)|290359|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|T|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|V|8|@]|9|@]|A|$B|C]]|$1|K|3|L|5|F|7|W|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|X|8|@]|9|@]|A|$B|C]]|$1|O|3|P|5|F|7|Y|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|F|7|Z|8|@]|9|@]|A|$]]]|R|$]]

<pre><code>https://api.instagram.com/v1/users/search?q="[USERNAME]"&amp;access_token=[ACCESS TOKEN]
</code></pre>

Please notice the quotation marks.

This does not always return a valid result but more often than non-quoted one:

<pre><code>https://api.instagram.com/v1/users/search?q="self"&amp;count=1&amp;access_token=[ACCESS TOKEN] 
</code></pre>

returns user "self" (id: 311176867)

<pre><code>https://api.instagram.com/v1/users/search?q=self&amp;count=1&amp;access_token=[ACCESS TOKEN]
</code></pre>

returns user "super_selfie" (id: 1422944651)

blocks|key|290389|text|这些答案中的大多数在6/1/2016+Instagram+API+changes之后都无效。现在最好的解决方案是here。转到instagram.com上的源，复制任何图片的链接地址，并将其粘贴到该页面的文本框中。就像一个护身符。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|290390|entityMap|0|LINK|mutability|MUTABLE|url|https://www.instagram.com/developer/changelog/|1|http://www.otzberg.net/iguserid/index.php^0|A|U|0|1K|4|1|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@$A|O|B|P|1|Q]|$A|R|B|S|1|T]]|C|$]]|$1|D|3|-4|5|6|7|U|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]|L|$5|G|H|I|C|$J|M]]]]

Most of these answers are invalid after the <a href="https://www.instagram.com/developer/changelog/" rel="nofollow">6/1/2016 Instagram API changes</a>. The best solution now is <a href="http://www.otzberg.net/iguserid/index.php" rel="nofollow">here</a>. Go to your feed on instagram.com, copy the link address for any of your pictures, and paste it into the textbox on that page. Worked like a charm.

blocks|key|290456|text|这是一个非常简单的网站，对我来说效果很好：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|290457|http://www.instaid.co.uk/|offset|length|290458|或者，您可以执行以下操作，将'+username‘替换为您的Instagram用户名|290459|https://www.instagram.com/username/?__a=1|290460|或者，你可以登录到你的Instagram账户，使用谷歌开发工具，查看已经存储的cookie。'ds_user_id‘是您的用户ID|290461|​|290462|📷|atomic|290463|290464|entityMap|0|LINK|mutability|MUTABLE|url|1|2|IMAGE|IMMUTABLE|imageUrl|https://ask.qcloudimg.com/http-save/yehe-900000/94e13c6a44e403a3f0b75af7b8650ee7.png|imageAlt^0|0|0|P|0|0|0|0|15|1|0|0|0|0|1|2|0|0^^$0|@$1|2|3|4|5|6|7|15|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|16|8|@]|9|@$D|17|E|18|1|19]]|A|$]]|$1|F|3|G|5|6|7|1A|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|1B|8|@]|9|@$D|1C|E|1D|1|1E]]|A|$]]|$1|J|3|K|5|6|7|1F|8|@]|9|@]|A|$]]|$1|L|3|M|5|6|7|1G|8|@]|9|@]|A|$]]|$1|N|3|O|5|P|7|1H|8|@]|9|@$D|1I|E|1J|1|1K]]|A|$]]|$1|Q|3|M|5|6|7|1L|8|@]|9|@]|A|$]]|$1|R|3|-4|5|6|7|1M|8|@]|9|@]|A|$]]]|S|$T|$5|U|V|W|A|$X|C]]|Y|$5|U|V|W|A|$X|I]]|Z|$5|10|V|11|A|$12|13|14|-4]]]]

Here is a really easy website that works well for me:

<a href="http://www.instaid.co.uk/" rel="nofollow noreferrer">http://www.instaid.co.uk/</a>

Or you can do the following replacing 'username' with your Instagram username

<a href="https://www.instagram.com/username/?__a=1" rel="nofollow noreferrer">https://www.instagram.com/username/?__a=1</a>

Or you can login to your Instagram account and use google dev tools and look at the cookies that have been stored. 'ds_user_id' is your user ID

<a href="https://i.stack.imgur.com/97NDA.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/97NDA.png" alt="enter image description here"></a>

blocks|key|507296|text|我尝试了上述所有的解决方案，但都不起作用。我猜Instagram加速了他们的变化。但是，我尝试了浏览器控制台方法，并尝试了一下，找到了这个命令，它为我提供了用户ID。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|507297|window._sharedData.entry_data.ProfilePage[0].graphql.user.id|code-block|syntax|javascript|507298|您只需访问配置文件的页面，并在控制台中输入此命令。不过，您可能需要刷新页面才能正常工作。(我不得不把这篇文章作为答案，因为我的声誉很低)|507299|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

I tried all the aforementioned solutions and none works. I guess Instagram has accelerated their changes. I tried, however, the browser console method and played around a bit and found this command that gave me the user ID.

<pre><code>window._sharedData.entry_data.ProfilePage[0].graphql.user.id
</code></pre>

You just visit a profile's page and enter this command in the console. You might need to refresh the page for this to work though. (I had to post this as an answer, because of my low reputation)

I'm in the process of embedding my image feed in my website using JSON, the URL needs my user id so I can retrieve this feed.

So, where can I find/get my user id?

Instagram how to get my user id from username?

身份验证

JSON

我正在使用JSON在我的网站中嵌入我的图像提要，URL需要我的用户id，这样我就可以检索这个提要。那么，我在哪里可以找到/获取我的用户id呢？

问Instagram如何从用户名中获取我的用户名？
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