我想遍历一段XML中的所有元素,打印每个元素。我的问题是,我总是在staff1
标记之后得到一个空指针异常,即john 465456433 gmail1 area1 city1
下面是打印xml文件中所有元素的Java代码:
File fXmlFile = new File("file.xml");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(fXmlFile);
doc.getDocumentElement().normalize();
System.out.println("Root element :" + doc.getDocumentElement().getNodeName());
NodeList nList = doc.getElementsByTagName("*");
System.out.println("----------------------------");
Node n=null;
Element eElement=null;
for (int i = 0; i < nList.getLength(); i++) {
System.out.println(nList.getLength());
n= nList.item(i);
System.out.println("\nCurrent Element :" + n.getNodeName());
if (n.getNodeType() == Node.ELEMENT_NODE) {
eElement = (Element) n.getChildNodes();
System.out.println("\nCurrent Element :" + n.getNodeName());
name = eElement.getElementsByTagName("name").item(i).getTextContent(); //here throws null pointer exception after printing staff1 tag
phone = eElement.getElementsByTagName("phone").item(i).getTextContent();
email = eElement.getElementsByTagName("email").item(i).getTextContent();
area = eElement.getElementsByTagName("area").item(i).getTextContent();
city = eElement.getElementsByTagName("city").item(i).getTextContent();
}
n.getNextSibling();
}
XML文件:
<?xml version="1.0"?>
<company>
<staff1>
<name>john</name>
<phone>465456433</phone>
<email>gmail1</email>
<area>area1</area>
<city>city1</city>
</staff1>
<staff2>
<name>mary</name>
<phone>4655556433</phone>
<email>gmail2</email>
<area>area2</area>
<city>city2</city>
</staff2>
<staff3>
<name>furvi</name>
<phone>4655433</phone>
<email>gmail3</email>
<area>area3</area>
<city>city3</city>
</staff3>
</company>
预期输出:
john
465456433
gmail1
area1
city1
mary
4655556433
gmail2
area2
city2
furvi
4655433
gmail3
area3
city3
发布于 2015-06-06 20:14:10
public class XMLParser {
public static void main(String[] args){
try {
DocumentBuilder dBuilder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
Document doc = dBuilder.parse(new File("xml input"));
NodeList nl=doc.getDocumentElement().getChildNodes();
for(int k=0;k<nl.getLength();k++){
printTags((Node)nl.item(k));
}
} catch (Exception e) {/*err handling*/}
}
public static void printTags(Node nodes){
if(nodes.hasChildNodes() || nodes.getNodeType()!=3){
System.out.println(nodes.getNodeName()+" : "+nodes.getTextContent());
NodeList nl=nodes.getChildNodes();
for(int j=0;j<nl.getLength();j++)printTags(nl.item(j));
}
}
}
递归地遍历并打印出文档中的所有XML子标记,以防您不必更改代码来处理xml中的动态变化,前提是它是格式良好的xml。
发布于 2016-06-10 21:36:38
这是使用JDOM遍历XML元素的另一种方法。
List<Element> nodeNodes = inputNode.getChildren();
if (nodeNodes != null) {
for (Element nodeNode : nodeNodes) {
List<Element> elements = nodeNode.getChildren(elementName);
if (elements != null) {
elements.size();
nodeNodes.removeAll(elements);
}
}
发布于 2021-10-07 14:24:26
NodeList listaHijos = docEle.getChildNodes();
listaHijos = listaHijos.item(2).getChildNodes();
for (int i = 0; i < listaHijos.getLength(); i++) {
eElement = (Element) listaHijos.item(i);
n2 = eElement.getChildNodes();
for (int j = 0; j < n2.getLength(); j++) {
System.out.println("elem:" + n2.item(j).getNodeName() + " :" + n2.item(j).getTextContent() + "j" + j);
if (n2.item(j).getNodeName().equals("detallesAdicionales")) {
eElement = (Element) n2.item(j);
n6 = eElement.getChildNodes();
System.out.println("todo: " + n6.item(0).getAttributes().item(0) + n6.item(0).getAttributes().item(1));
System.out.println("todo2: " + n6.item(1).getAttributes().item(0) + n6.item(1).getAttributes().item(1));
System.out.println("todo3: " + n6.item(2).getAttributes().item(0) + n6.item(2).getAttributes().item(1));
System.out.println("nombre: " + n6.item(0).getAttributes().item(0).getTextContent());
System.out.println("valor: " + n6.item(0).getAttributes().item(1).getTextContent());
}
}
}
https://stackoverflow.com/questions/14566596
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