下面是我写的方法:
public List<Map<String, Object>> loadNotYetInEmployee(int shift, Date date,
int transitionVal, String type, User user) {
DateTime datetime = new DateTime(date);
datetime = datetime
.plus(Period.minutes(shiftTiming.getSession1InTime()));
List<Map<String, Object>> result = new ArrayList<Map<String, Object>>();
sql = SqlMapUtils.getSql("attendance.attendancestatus.latein",
parameters);
result = getJdbcTemplate().queryForList(sql);
for (int i = 0; i < result.size(); i++) {
Date punchInTime = (Date) result.get(i).get("punchtime");
DateTime punchTime = new DateTime(punchInTime);
}
return result;
}
现在,从我的方法中,您可以看到我在名为datetime
的对象中有一个Joda-Time DateTime对象,从我的结果中,我得到了一个时间戳,我正在将其转换为jodatime punchTime
。现在我想找出这两个日期之间的差异,我该怎么做呢?
发布于 2012-10-12 12:01:18
这将以毫秒为单位显示两个DateTime对象之间的差异:
DateTime d1 = new DateTime();
DateTime d2 = new DateTime();
long diffInMillis = d2.getMillis() - d1.getMillis();
发布于 2012-10-12 11:59:39
就像..。
DateTime today = new DateTime();
DateTime yesterday = today.minusDays(1);
Duration duration = new Duration(yesterday, today);
System.out.println(duration.getStandardDays());
System.out.println(duration.getStandardHours());
System.out.println(duration.getStandardMinutes());
哪种输出
1
24
1440
或
System.out.println(Minutes.minutesBetween(yesterday, today).getMinutes());
这可能是你想要的更多
发布于 2018-02-07 04:02:52
就像..。
Minutes.minutesBetween(getStart(), getEnd()).getMinutes();
https://stackoverflow.com/questions/12851934
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