blocks|key|145890|text|你更新到5.6了吗？上面写着|type|unstyled|depth|inlineStyleRanges|entityRanges|data|145891|不再接受|145892|无效密钥和iv大小。如果输入无效，mcrypt_decrypt()现在将抛出警告并返回FALSE。以前，密钥和IV是用'\0‘字节填充到下一个有效大小的。|blockquote|145893|145894|145895|145896|阅读这句话的最后一行，您将在那里找到解决方案:)|145897|145898|+mcrypt_decrypt()：此算法不支持大小为15的键。仅支持大小为16、24或32的密钥|145899|145900|145901|这意味着你需要用\0来填充你的钥匙(这就是以前的版本为你做的)|offset|length|style|CODE|145902|$key=$key."\0";|code-block|syntax|javascript|145903|entityMap^0|0|0|0|0|0|0|0|0|0|0|0|8|2|0|0^^$0|@$1|2|3|4|5|6|7|13|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|14|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|15|8|@]|9|@]|A|$]]|$1|G|3|-4|5|6|7|16|8|@]|9|@]|A|$]]|$1|H|3|-4|5|6|7|17|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|18|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|19|8|@]|9|@]|A|$]]|$1|L|3|-4|5|6|7|1A|8|@]|9|@]|A|$]]|$1|M|3|N|5|F|7|1B|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|1C|8|@]|9|@]|A|$]]|$1|P|3|-4|5|6|7|1D|8|@]|9|@]|A|$]]|$1|Q|3|R|5|6|7|1E|8|@$S|1F|T|1G|U|V]]|9|@]|A|$]]|$1|W|3|X|5|Y|7|1H|8|@]|9|@]|A|$Z|10]]|$1|11|3|-4|5|6|7|1I|8|@]|9|@]|A|$]]]|12|$]]

Did you update to 5.6? It says 

<blockquote>
 Invalid key and iv sizes are no longer accepted. mcrypt_decrypt() will now throw a warning and return FALSE if the inputs are invalid. Previously keys and IVs were padded with '\0' bytes to the next valid size. 
</blockquote>

<a href="http://php.net/manual/en/function.mcrypt-decrypt.php">Reference</a>

Read the last line of that quote, and there you will find your solution :)

<blockquote>
 mcrypt_decrypt(): Key of size 15 not supported by this algorithm. Only keys of sizes 16, 24 or 32 supported
</blockquote>

That means you need to pad your key with <code>\0</code> (that's what previous versions were doing for you)

<pre><code>$key=$key."\0";
</code></pre>

blocks|key|2719449|text|我继续创建了一个基于Hanky+웃+Panky's+answer的函数。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2719450|这可以与任何密钥长度一起使用，以确保其大小正确。|2719451|function+pad_key($key){
++++//+key+is+too+large
++++if(strlen($key)+>+32)+return+false;

++++//+set+sizes
++++$sizes+=+array(16,24,32);

++++//+loop+through+sizes+and+pad+key
++++foreach($sizes+as+$s){
++++++++while(strlen($key)+<+$s)+$key+=+$key."\0";
++++++++if(strlen($key)+==+$s)+break;+//+finish+if+the+key+matches+a+size
++++}

++++//+return
++++return+$key;
}|code-block|syntax|javascript|2719452|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/27254578/4867^0|A|M|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|6|7|W|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|X|8|@]|9|@]|C|$I|J]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]]]

I went ahead and created a function based on <a href="https://stackoverflow.com/a/27254578/4867">Hanky 웃 Panky's answer</a>.

This can be used with any key length to make sure it's the correct size.

<pre><code>function pad_key($key){
 // key is too large
 if(strlen($key) &gt; 32) return false;

 // set sizes
 $sizes = array(16,24,32);

 // loop through sizes and pad key
 foreach($sizes as $s){
 while(strlen($key) &lt; $s) $key = $key."\0";
 if(strlen($key) == $s) break; // finish if the key matches a size
 }

 // return
 return $key;
}
</code></pre>

blocks|key|142300|text|你不需要在钥匙上填上"\0“。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|142301|我在迁移到新的PHP+7服务器时也遇到了同样的问题，我得到了这样的消息：|142302|142303|+mcrypt_decrypt()：此算法不支持大小为19的键。仅支持大小为16、24或32的密钥。|blockquote|142304|142305|142306|我在代码中的关键字是一个19个字符的字符串，我只需将其更改为32个字符的字符串，一切又都正常了。|142307|因此，如错误消息所示，请使用有效的大小密钥。|142308|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Q|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|R|8|@]|9|@]|A|$]]|$1|E|3|F|5|G|7|S|8|@]|9|@]|A|$]]|$1|H|3|-4|5|6|7|T|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|U|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|V|8|@]|9|@]|A|$]]|$1|L|3|M|5|6|7|W|8|@]|9|@]|A|$]]|$1|N|3|-4|5|6|7|X|8|@]|9|@]|A|$]]]|O|$]]

You don't need to pad the key with "\0". 

I had the same issue when migrating to a new PHP 7 server and I got the message : 

<blockquote>
 mcrypt_decrypt(): Key of size 19 not supported by this algorithm. Only
 keys of sizes 16, 24 or 32 supported.
</blockquote>

The key I had in the code was a string of 19 characters, I simply changed it to a string of 32 characters and everything was fine again.

So as the error message suggests, use a valid size key.

blocks|key|2719467|text|我在OSTicket+1.6ST上遇到了这个问题(是的，我知道老版本)。托管公司刚刚升级到PHP5.6，它打破了cron.php的邮件抓取。我发布了这篇文章，希望能帮助其他人更快地解决这个问题。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2719468|您必须编辑文件"include/class.misc.php“。|2719469|将@troskater编写的答案中提供的函数"pad_key“添加到"include/class.misc.php”文件，然后在函数"decrypt“change的第51行|2719470|2719471|+return+trim(mcrypt_decrypt(MCRYPT_RIJNDAEL_256，$salt，...|blockquote|offset|length|style|BOLD|2719472|2719473|2719474|改为使用|2719475|2719476|+return+trim(mcrypt_decrypt(MCRYPT_RIJNDAEL_256，+...|2719477|2719478|entityMap^0|0|0|0|0|1C|5|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|X|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Y|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|Z|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|10|8|@]|9|@]|A|$]]|$1|G|3|H|5|I|7|11|8|@$J|12|K|13|L|M]]|9|@]|A|$]]|$1|N|3|-4|5|6|7|14|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|15|8|@]|9|@]|A|$]]|$1|P|3|Q|5|6|7|16|8|@]|9|@]|A|$]]|$1|R|3|-4|5|6|7|17|8|@]|9|@]|A|$]]|$1|S|3|T|5|I|7|18|8|@]|9|@]|A|$]]|$1|U|3|-4|5|6|7|19|8|@]|9|@]|A|$]]|$1|V|3|-4|5|6|7|1A|8|@]|9|@]|A|$]]]|W|$]]

I had this issue with OSTicket 1.6 ST (yes old version I know). Hosting company just went to PHP 5.6 and it broke the Mail Fetch for cron.php. I'm posting this hoping it helps others fix this issue faster. 

You have to edit the file "include/class.misc.php". 

Add the function "pad_key" provided in the answer authored by @troskater to the "include/class.misc.php" file and then on line 51 in the function "decrypt" change

<blockquote>
 return trim(mcrypt_decrypt(MCRYPT_RIJNDAEL_256, $salt,...
</blockquote>

to instead use 

<blockquote>
 return trim(mcrypt_decrypt(MCRYPT_RIJNDAEL_256, pad_key($salt),...
</blockquote>

blocks|key|144604|text|对于Laravel+5|type|unstyled|depth|inlineStyleRanges|entityRanges|data|144605|只需运行php+artisan+key:generate|offset|length|style|CODE|144606|Application+key+[EaaJgaD0uFDEg7tpvMOqKfAQ46Bqi8Va]+set+successfully.|code-block|syntax|javascript|144607|如果没有看到密钥更新，只需将其粘贴到.env文件中即可。|144608|APP_KEY=EaaJgaD0uFDEg7tpvMOqKfAQ46Bqi8Va|144609|刷新页面|144610|entityMap^0|0|4|O|0|0|I|4|0|0|14|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@$D|W|E|X|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|Y|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|Z|8|@$D|10|E|11|F|G]]|9|@]|A|$]]|$1|O|3|P|5|6|7|12|8|@$D|13|E|14|F|G]]|9|@]|A|$]]|$1|Q|3|R|5|6|7|15|8|@]|9|@]|A|$]]|$1|S|3|-4|5|6|7|16|8|@]|9|@]|A|$]]]|T|$]]

For Laravel 5

Just run <code>php artisan key:generate</code>:

<pre class="lang-none prettyprint-override"><code>Application key [EaaJgaD0uFDEg7tpvMOqKfAQ46Bqi8Va] set successfully.
</code></pre>

If you don't see your key updated, just paste it in your <code>.env</code> file.

<code>APP_KEY=EaaJgaD0uFDEg7tpvMOqKfAQ46Bqi8Va</code>

Refresh your page

blocks|key|2932102|text|我也有同样的问题，但我用下面的代码解决了它|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2932103|public+function+setKey($key)+{
++++$len+=+strlen($key);
++++if($len+<+24+&&+$len+!=+16){
++++++++$key+=+str_pad($key,+24,+"\0",+STR_PAD_RIGHT);+
++++}+elseif+($len+>+24+&&+$len+<+32)+{
++++++++$key+=+str_pad($key,+32,+"\0",+STR_PAD_RIGHT);+++++++
++++}elseif+($len+>+32){
++++++++$key+=+substr($key,+0,+32);
++++}
++++$this->key+=+$key;
+}|code-block|syntax|javascript|2932104|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I had the same problem, but fixed it with this

<pre><code>public function setKey($key) {
 $len = strlen($key);
 if($len &lt; 24 &amp;&amp; $len != 16){
 $key = str_pad($key, 24, "\0", STR_PAD_RIGHT); 
 } elseif ($len &gt; 24 &amp;&amp; $len &lt; 32) {
 $key = str_pad($key, 32, "\0", STR_PAD_RIGHT); 
 }elseif ($len &gt; 32){
 $key = substr($key, 0, 32);
 }
 $this-&gt;key = $key;
 }
</code></pre>

blocks|key|144641|text|如果您的加密代码如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|144642|<?php
++function+encryptCookie($value){
++++if(!$value){return+false;}
++++$key+=+'aNdRgUkXp2s5v8y/B?E(H%2BMbQeShVmYq';
++++$text+=+$value;
++++$iv_size+=+mcrypt_get_iv_size(MCRYPT_RIJNDAEL_256,+MCRYPT_MODE_ECB);
++++$iv+=+mcrypt_create_iv($iv_size,+MCRYPT_RAND);
++++$crypttext+=+mcrypt_encrypt(MCRYPT_RIJNDAEL_256,+$key,+$text,+MCRYPT_MODE_ECB,+$iv);
++++return+trim(base64_encode($crypttext));+//encode+for+cookie
+++}
+function+decryptCookie($value){
++++if(!$value){return+false;}
++++$key+=+'aNdRgUkXp2s5v8y/B?E(H%2BMbQeShVmYq';
++++$crypttext+=+base64_decode($value);+//decode+cookie
++++$iv_size+=+mcrypt_get_iv_size(MCRYPT_RIJNDAEL_256,+MCRYPT_MODE_ECB);
++++$iv+=+mcrypt_create_iv($iv_size,+MCRYPT_RAND);
++++$decrypttext+=+mcrypt_decrypt(MCRYPT_RIJNDAEL_256,+$key,+$crypttext,+MCRYPT_MODE_ECB,+$iv);
++++return+trim($decrypttext);
+++}
?>|code-block|syntax|javascript|144643|您需要将$key更改为128位或256位加密码。我只是简单地复制了从这里生成的代码：Generate+Code|offset|length|144644|我为我的代码创建了一个256位的代码，它由32个字符组成，因此修复了无效密钥大小为15或导致错误的任何数字的问题。因此，无论为$key设置了什么，您都需要将其更改为有效的代码，然后它应该可以正常工作。|144645|entityMap|0|LINK|mutability|MUTABLE|url|http://www.allkeysgenerator.com/Random/Security-Encryption-Key-Generator.aspx^0|0|0|16|D|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@$I|X|J|Y|1|Z]]|A|$]]|$1|K|3|L|5|6|7|10|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]]]

If your encryption code looks like this:

<pre><code>&lt;?php
 function encryptCookie($value){
 if(!$value){return false;}
 $key = 'aNdRgUkXp2s5v8y/B?E(H+MbQeShVmYq';
 $text = $value;
 $iv_size = mcrypt_get_iv_size(MCRYPT_RIJNDAEL_256, MCRYPT_MODE_ECB);
 $iv = mcrypt_create_iv($iv_size, MCRYPT_RAND);
 $crypttext = mcrypt_encrypt(MCRYPT_RIJNDAEL_256, $key, $text, MCRYPT_MODE_ECB, $iv);
 return trim(base64_encode($crypttext)); //encode for cookie
 }
 function decryptCookie($value){
 if(!$value){return false;}
 $key = 'aNdRgUkXp2s5v8y/B?E(H+MbQeShVmYq';
 $crypttext = base64_decode($value); //decode cookie
 $iv_size = mcrypt_get_iv_size(MCRYPT_RIJNDAEL_256, MCRYPT_MODE_ECB);
 $iv = mcrypt_create_iv($iv_size, MCRYPT_RAND);
 $decrypttext = mcrypt_decrypt(MCRYPT_RIJNDAEL_256, $key, $crypttext, MCRYPT_MODE_ECB, $iv);
 return trim($decrypttext);
 }
?&gt;
</code></pre>

You will want to change the $key to a 128 or 256 bit encrypted code. I simply copied a code that I generated from here: <a href="http://www.allkeysgenerator.com/Random/Security-Encryption-Key-Generator.aspx" rel="nofollow noreferrer">Generate Code</a>

I created a 256 bit code for mine which consists of 32 characters and thus fixes the issue of the invalid key size of 15 or whatever number is causing the error. So whatever is set for $key you need to change that to a valid code and then it should work fine.

blocks|key|144647|text|为此，您可以使用str_pad()。在最简单的形式下，这就足够了。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|144648|function+padKey($key)+
{
++++//+Get+the+current+key+size
++++$keySize+=+strlen($key);

++++//+Set+an+array+containing+the+valid+sizes
++++$validSizes+=+[16,24,32];

++++//+Loop+through+sizes+and+return+correct+padded+$key
++++foreach($validSizes+as+$validSize)+{
++++++++if+($keySize+<=+$validSize)+return+str_pad($key,+$validSize,+"\0");
++++}

++++//+Throw+an+exception+if+the+key+is+greater+than+the+max+size
++++throw+new+Exception("Key+size+is+too+large");+

}|code-block|syntax|javascript|144649|其他的答案会做得很好。我只是在这里利用内置的PHP函数str_pad，而不是在循环中附加"\0“。|144650|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You can just use str_pad() for this. In its simplest form, this will suffice.

<pre><code>function padKey($key) 
{
 // Get the current key size
 $keySize = strlen($key);

 // Set an array containing the valid sizes
 $validSizes = [16,24,32];

 // Loop through sizes and return correct padded $key
 foreach($validSizes as $validSize) {
 if ($keySize &lt;= $validSize) return str_pad($key, $validSize, "\0");
 }

 // Throw an exception if the key is greater than the max size
 throw new Exception("Key size is too large"); 

}
</code></pre>

The other answers will do just fine. I'm just taking advantage of the built in PHP function str_pad here instead of appending "\0" in a loop.

<blockquote>
 mcrypt_decrypt(): Key of size 15 not supported by this algorithm. Only keys of sizes 16, 24 or 32 supported
</blockquote>

How Can I fix this issue? my key is set - can not change it.
It has to be a local change, I think my local PHP version is too advanced for the project I loaded.
How can I fix this?

mcrypt_decrypt() error change key size

服务器

 mcrypt_decrypt()：此算法不支持大小为15的键。仅支持大小为16、24或32的密钥如何解决此问题？我的密钥已设置-无法更改它。这必须是一个本地更改，我认为我的本地PHP版本对于我加载的项目来说太高级了。我该如何解决这个问题呢？

问更改密钥大小时出现mcrypt_decrypt()错误
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