blocks|key|204611|text|《守则》|type|unstyled|depth|inlineStyleRanges|entityRanges|data|204612|var+startDate+=+new+Date();
//+Do+your+operations
var+endDate+++=+new+Date();
var+seconds+=+(endDate.getTime()+-+startDate.getTime())+/+1000;|code-block|syntax|javascript|204613|或者更简单的(endDate+-+startDate)+/+1000，就像评论中指出的那样，除非你正在使用typescript。|offset|length|style|CODE|204614|204615|解释|204616|您需要为Date对象调用getTime()方法，然后简单地减去它们并除以1000+(因为它最初是以毫秒为单位)。另外，当您调用getDate()方法时，实际上获取的是一个介于1和31之间的整数(不是从零开始)，而不是调用getTime()方法获得的纪元时间，表示自1970年1月1日00:00以来的毫秒数|204617|204618|范围|204619|根据与日期相关的操作是什么，您可能希望投资于集成库，如date.js或moment.js，这将使开发人员的工作变得更容易，但这只是个人偏好的问题。|204620|例如，在moment.js中，我们会使用moment1.diff(moment2,+"seconds")，这很漂亮。|204621|204622|此答案的有用文档|204623|204624|Why+1970?|unordered-list-item|204625|Date+object|204626|Date's+getTime+method|204627|Date's+getDate+method|204628|Need+more+accuracy+than+just+seconds?|204629|204630|entityMap|0|LINK|mutability|MUTABLE|url|http://www.datejs.com/|1|https://momentjs.com/|2|3|http://en.wikipedia.org/wiki/Unix_time|4|http://msdn.microsoft.com/en-us/library/ie/cd9w2te4%2528v=vs.94%2529.aspx|5|http://msdn.microsoft.com/en-us/library/ie/7hcawkw2%2528v=vs.94%2529.aspx|6|http://msdn.microsoft.com/en-us/library/ie/217fw5tk%2528v=vs.94%2529.aspx|7|https://developer.mozilla.org/en-US/docs/Web/API/Performance/now^0|0|0|6|S|0|0|0|4|4|C|9|1R|9|32|9|0|0|0|R|7|0|Z|9|1|0|K|W|4|9|2|0|0|0|0|0|9|3|0|0|B|4|0|0|L|5|0|0|L|6|0|0|11|7|0|0^^$0|@$1|2|3|4|5|6|7|1Z|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|20|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|21|8|@$I|22|J|23|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|24|8|@]|9|@]|A|$]]|$1|N|3|O|5|6|7|25|8|@]|9|@]|A|$]]|$1|P|3|Q|5|6|7|26|8|@$I|27|J|28|K|L]|$I|29|J|2A|K|L]|$I|2B|J|2C|K|L]|$I|2D|J|2E|K|L]]|9|@]|A|$]]|$1|R|3|-4|5|6|7|2F|8|@]|9|@]|A|$]]|$1|S|3|T|5|6|7|2G|8|@]|9|@]|A|$]]|$1|U|3|V|5|6|7|2H|8|@]|9|@$I|2I|J|2J|1|2K]|$I|2L|J|2M|1|2N]]|A|$]]|$1|W|3|X|5|6|7|2O|8|@$I|2P|J|2Q|K|L]]|9|@$I|2R|J|2S|1|2T]]|A|$]]|$1|Y|3|-4|5|6|7|2U|8|@]|9|@]|A|$]]|$1|Z|3|10|5|6|7|2V|8|@]|9|@]|A|$]]|$1|11|3|-4|5|6|7|2W|8|@]|9|@]|A|$]]|$1|12|3|13|5|14|7|2X|8|@]|9|@$I|2Y|J|2Z|1|30]]|A|$]]|$1|15|3|16|5|14|7|31|8|@]|9|@$I|32|J|33|1|34]]|A|$]]|$1|17|3|18|5|14|7|35|8|@]|9|@$I|36|J|37|1|38]]|A|$]]|$1|19|3|1A|5|14|7|39|8|@]|9|@$I|3A|J|3B|1|3C]]|A|$]]|$1|1B|3|1C|5|14|7|3D|8|@]|9|@$I|3E|J|3F|1|3G]]|A|$]]|$1|1D|3|-4|5|6|7|3H|8|@]|9|@]|A|$]]|$1|1E|3|-4|5|6|7|3I|8|@]|9|@]|A|$]]]|1F|$1G|$5|1H|1I|1J|A|$1K|1L]]|1M|$5|1H|1I|1J|A|$1K|1N]]|1O|$5|1H|1I|1J|A|$1K|1N]]|1P|$5|1H|1I|1J|A|$1K|1Q]]|1R|$5|1H|1I|1J|A|$1K|1S]]|1T|$5|1H|1I|1J|A|$1K|1U]]|1V|$5|1H|1I|1J|A|$1K|1W]]|1X|$5|1H|1I|1J|A|$1K|1Y]]]]

<h3>The Code</h3>
<pre><code>var startDate = new Date();
// Do your operations
var endDate   = new Date();
var seconds = (endDate.getTime() - startDate.getTime()) / 1000;
</code></pre>
<p>Or even simpler <code>(endDate - startDate) / 1000</code> as pointed out in the comments unless you're using typescript.</p>
<hr/>
<h3>The explanation</h3>
<p>You need to call the <code>getTime()</code> method for the <code>Date</code> objects, and then simply subtract them and divide by 1000 (since it's originally in milliseconds). As an extra, when you're calling the <code>getDate()</code> method, you're in fact getting the day of the month as an integer between 1 and 31 (not zero based) as opposed to the epoch time you'd get from calling the <code>getTime()</code> method, representing the number of milliseconds since <em>January 1st 1970, 00:00</em></p>
<hr/>
<h3>Rant</h3>
<p>Depending on what your date related operations are, you might want to invest in integrating a library such as <a href="http://www.datejs.com/" rel="noreferrer">date.js</a> or <a href="https://momentjs.com/" rel="noreferrer">moment.js</a> which make things <em>so much easier</em> for the developer, but that's just a matter of personal preference.</p>
<p>For example in <a href="https://momentjs.com/" rel="noreferrer">moment.js</a> we would do <code>moment1.diff(moment2, &quot;seconds&quot;)</code> which is beautiful.</p>
<hr />
<h3>Useful docs for this answer</h3>
<ul>
<li><a href="http://en.wikipedia.org/wiki/Unix_time" rel="noreferrer">Why 1970?</a></li>
<li><a href="http://msdn.microsoft.com/en-us/library/ie/cd9w2te4%28v=vs.94%29.aspx" rel="noreferrer">Date object</a></li>
<li><a href="http://msdn.microsoft.com/en-us/library/ie/7hcawkw2%28v=vs.94%29.aspx" rel="noreferrer">Date's getTime method</a></li>
<li><a href="http://msdn.microsoft.com/en-us/library/ie/217fw5tk%28v=vs.94%29.aspx" rel="noreferrer">Date's getDate method</a></li>
<li><a href="https://developer.mozilla.org/en-US/docs/Web/API/Performance/now" rel="noreferrer">Need more accuracy than just seconds?</a></li>
</ul>


blocks|key|204222|text|<script+type="text/javascript">
var+_initial+=+'2015-05-21T10:17:28.593Z';
var+fromTime+=+new+Date(_initial);
var+toTime+=+new+Date();

var+differenceTravel+=+toTime.getTime()+-+fromTime.getTime();
var+seconds+=+Math.floor((differenceTravel)+/+(1000));
document.write('%2B+seconds+%2B');
</script>|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|204223|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>&lt;script type="text/javascript"&gt;
var _initial = '2015-05-21T10:17:28.593Z';
var fromTime = new Date(_initial);
var toTime = new Date();

var differenceTravel = toTime.getTime() - fromTime.getTime();
var seconds = Math.floor((differenceTravel) / (1000));
document.write('+ seconds +');
&lt;/script&gt;
</code></pre>


blocks|key|2838282|text|您可以使用new+Date().getTime()来获取时间戳。然后，您可以计算结束和开始之间的差异，并最终将时间戳ms转换为s。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2838283|const+start+=+new+Date().getTime();
const+end+=+new+Date().getTime();

const+diff+=+end+-+start;
const+seconds+=+Math.floor(diff+/+1000+%25+60);|code-block|syntax|javascript|2838284|entityMap^0|5|K|1M|2|1R|1|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|U|8|@]|D|@]|E|$]]]|L|$]]

<p>You can use <code>new Date().getTime()</code> for getting timestamps. Then you can calculate the difference between end and start and finally transform the timestamp which is <code>ms</code> into <code>s</code>.</p>

<pre><code>const start = new Date().getTime();
const end = new Date().getTime();

const diff = end - start;
const seconds = Math.floor(diff / 1000 % 60);
</code></pre>


blocks|key|3051301|text|尝试使用高级编程语言中的专用函数。JavaScript+.getSeconds();适用于：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3051302|var+specifiedTime+=+new+Date("November+02,+2017+06:00:00");
var+specifiedTimeSeconds+=+specifiedTime.getSeconds();+

var+currentTime+=+new+Date();
var+currentTimeSeconds+=+currentTime.getSeconds();+

alert(specifiedTimeSeconds-currentTimeSeconds);|code-block|syntax|javascript|3051303|entityMap^0|S|E|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

<p>try using dedicated functions from high level programming languages. JavaScript <code>.getSeconds();</code> suits here:</p>

<pre><code>var specifiedTime = new Date("November 02, 2017 06:00:00");
var specifiedTimeSeconds = specifiedTime.getSeconds(); 

var currentTime = new Date();
var currentTimeSeconds = currentTime.getSeconds(); 

alert(specifiedTimeSeconds-currentTimeSeconds);
</code></pre>


blocks|key|201860|text|现在和10分钟后使用momentjs的时间差|type|unstyled|depth|inlineStyleRanges|entityRanges|data|201861|let+start_time+=+moment().format('YYYY-MM-DD+HH:mm:ss');
let+next_time+=+moment().add(10,+'m').format('YYYY-MM-DD+HH:mm:ss');

let+diff_milliseconds+=+Date.parse(next_time)+-+Date.parse(star_time);
let+diff_seconds+=+diff_milliseconds+*+1000;|code-block|syntax|javascript|201862|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>time difference between now and 10 minutes later using momentjs</p>

<pre><code>let start_time = moment().format('YYYY-MM-DD HH:mm:ss');
let next_time = moment().add(10, 'm').format('YYYY-MM-DD HH:mm:ss');

let diff_milliseconds = Date.parse(next_time) - Date.parse(star_time);
let diff_seconds = diff_milliseconds * 1000;
</code></pre>


blocks|key|204276|text|下面的代码将给出以秒为单位的时间差。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|204277|var+date1+=+new+Date();+//+current+date
var+date2+=+new+Date("06/26/2018");+//+mm/dd/yyyy+format
var+timeDiff+=+Math.abs(date2.getTime()+-+date1.getTime());+//+in+miliseconds
var+timeDiffInSecond+=+Math.ceil(timeDiff+/+1000);+//+in+second

alert(timeDiffInSecond+);|code-block|syntax|javascript|204278|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>Below code will give the time difference in second. </p>

<pre><code>var date1 = new Date(); // current date
var date2 = new Date("06/26/2018"); // mm/dd/yyyy format
var timeDiff = Math.abs(date2.getTime() - date1.getTime()); // in miliseconds
var timeDiffInSecond = Math.ceil(timeDiff / 1000); // in second

alert(timeDiffInSecond );
</code></pre>


blocks|key|204289|text|使用new+Date()定义两个日期。使用date2计算两个日期的时间差。getTime()+-+date1。getTime()；计算两个日期之间的天数，将两个日期的时间差除以no。一天中的毫秒(1000_60_60*24)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|204290|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

<p>Define two dates using new Date().
Calculate the time difference of two dates using date2. getTime() – date1. getTime();
Calculate the no. of days between two dates, divide the time difference of both the dates by no. of milliseconds in a day (1000<em>60</em>60*24)</p>


blocks|key|201922|text|准确和快速将在几秒钟内给出输出：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|201923|+let+startDate+=+new+Date()
+let+endDate+=+new+Date("yyyy-MM-dd'T'HH:mm:ssZ");
+let+seconds+=+Math.round((endDate.getTime()+-+startDate.getTime())+/+1000);|code-block|syntax|javascript|201924|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>Accurate and fast will give output in seconds:</p>
<pre><code> let startDate = new Date()
 let endDate = new Date(&quot;yyyy-MM-dd'T'HH:mm:ssZ&quot;);
 let seconds = Math.round((endDate.getTime() - startDate.getTime()) / 1000);
</code></pre>


<p>I'm trying to get a difference between two dates in seconds. The logic would be like this :</p>

<ul>
<li>set an initial date which would be now;</li>
<li>set a final date which would be the initial date plus some amount of seconds in future ( let's say 15 for instance )</li>
<li>get the difference between those two ( the amount of seconds )</li>
</ul>

<p>The reason why I'm doing it it with dates it's because the final date / time depends on some other variables and it's never the same ( it depends on how fast a user does something ) and I also store the initial date for other things.</p>

<p>I've been trying something like this : </p>

<pre><code>var _initial = new Date(),
    _initial = _initial.setDate(_initial.getDate()),
    _final = new Date(_initial);
    _final = _final.setDate(_final.getDate() + 15 / 1000 * 60);

var dif = Math.round((_final - _initial) / (1000 * 60));
</code></pre>

<p>The thing is that I never get the right difference. I tried dividing by <code>24 * 60</code> which would leave me with the seconds, but I never get it right. So what is it wrong with my logic ? I might be making some stupid mistake as it's quite late, but it bothers me that I cannot get it to work :)</p>


Get time difference between two dates in seconds

我在试着在几秒钟内得到两个日期之间的差异。逻辑是这样的：设置的初始日期是现在；设置的最终日期是初始日期加上将来的一些秒数(例如15 )获取这两个日期之间的差值(秒数)我之所以这样做，是因为最终的日期/时间取决于其他一些变量，它永远不会相同(这取决于用户做某事的速度)，而且我还会为其他事情存储初始日期。我一直在尝试这样的...

问获取两个日期之间的时间差，单位为秒
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