格式化表格ascii python
格式化表格ascii python
提问于 2019-09-01 05:02:50
您好，我试图在第二列之后添加一个空格，而不是将它添加到第一列，但是如果我试图以一种肮脏的方式添加它，比如'| '.join，我的单元格就会变得一团糟，但是我怎么能有输出的愿望呢？我也尝试过rjust(3)，但它不起作用
_id = ['1', '2', '3','4']
transport = ['http','tcp','https','dns']
agent = ['10.10.1.1','10.10.1.2','10.10.1.3','10.10.1.4']
username = ['DESKTOP-123\\user','root','user','user']
os = ['windows/amd64','linux/amd64','windows/amd64','linux/amd64']
seen = ['2019-08-31 13:10:08','2019-08-31 13:10:08','2019-08-31 13:10:08','2019-08-31 13:10:08']
titles = ['ID', 'Transport', 'Agent', 'Username','Operating System','Last Seen']
data = [titles] + list(zip(_id, transport, agent, username,os,seen))
def os():
print("\t")
for i, d in enumerate(data):
line = '|'.join(str(x).ljust(18) for x in d)
print(line)
if i == 0:
sep = '-' * 18 + '+'
line = ''.join(sep for x in d)
print(line)
print("\t")我想要有一个输出，在管道后面添加一个空格，第一列除外
|1 | 2 | 3 |
+--+---+---+
|4 | 5 | 6 |
|7 | 8 | 9 |回答 1
Stack Overflow用户
回答已采纳
发布于 2019-09-01 05:54:07
将枚举数据中的第一行定义替换为：
line = f'{str(d[0]).ljust(18)}| {"| ".join(str(x).ljust(17) for x in d if d.index(x) > 0)}'它应该是这样的：
_id = ['1', '2', '3','4']
transport = ['http','tcp','https','dns']
agent = ['10.10.1.1','10.10.1.2','10.10.1.3','10.10.1.4']
username = ['DESKTOP-123\\user','root','user','user']
os = ['windows/amd64','linux/amd64','windows/amd64','linux/amd64']
seen = ['2019-08-31 13:10:08','2019-08-31 13:10:08','2019-08-31 13:10:08','2019-08-31 13:10:08']
titles = ['ID', 'Transport', 'Agent', 'Username','Operating System','Last Seen']
data = [titles] + list(zip(_id, transport, agent, username,os,seen))
def os():
print("\t")
for i, d in enumerate(data):
line = f'{str(d[0]).ljust(18)}| {"| ".join(str(x).ljust(17) for x in d if d.index(x) > 0)}'
print(line)
if i == 0:
sep = '-' * 18 + '+'
line = ''.join(sep for x in d)
print(line)
print("\t")结果：
ID | Transport | Agent | Username | Operating System | Last Seen
------------------+------------------+------------------+------------------+------------------+------------------+
1 | http | 10.10.1.1 | DESKTOP-123\user | windows/amd64 | 2019-08-31 13:10:08
2 | tcp | 10.10.1.2 | root | linux/amd64 | 2019-08-31 13:10:08
3 | https | 10.10.1.3 | user | windows/amd64 | 2019-08-31 13:10:08
4 | dns | 10.10.1.4 | user | linux/amd64 | 2019-08-31 13:10:08页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/57741573
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