blocks|key|2967321|text|mySmallVuln.Published+=+new+DateTime(1998,04,30);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2967322|或者像这样|unstyled|2967323|var+date+=+DateTime.MinValue;
if+(DateTime.TryParse("1998/04/30",+out+date))
{
++++//Sucess...
++++mySmallVuln.Published+=+date;
}|2967324|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>mySmallVuln.Published = new DateTime(1998,04,30);
</code></pre>

Or perhaps like this

<pre><code>var date = DateTime.MinValue;
if (DateTime.TryParse("1998/04/30", out date))
{
 //Sucess...
 mySmallVuln.Published = date;
}
</code></pre>

blocks|key|164021|text|使用这个|type|unstyled|depth|inlineStyleRanges|entityRanges|data|164022|//年、月、日|164023|mySmallVuln.Published=new+DateTime(2011,11,4);|code-block|syntax|javascript|164024|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

use this

// year,month,day

<pre><code>mySmallVuln.Published=new DateTime(2011,11,4);
</code></pre>

blocks|key|160403|text|要初始化DateTime值，可以使用DateTime构造函数：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|160404|mySmallVuln.Published+=+new+DateTime(1998,04,30);|code-block|syntax|javascript|160405|entityMap^0|4|8|I|8|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|L|$]]

To initialize a <code>DateTime</code> value you can use the <code>DateTime</code> constructor:

<pre><code>mySmallVuln.Published = new DateTime(1998,04,30);
</code></pre>

blocks|key|2967371|text|两者都是一样的..。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2967372|1|offset|length|style|BOLD|2967373|mySmallVuln.Published+=+new+DateTime(1998,04,30,0,0,0);
mySmallVuln.LastUpdated+=+new+DateTime(2007,11,05,0,0,0);|code-block|syntax|javascript|2967374|2|2967375|mySmallVuln.Published+=+new+DateTime(1998,04,30);
mySmallVuln.LastUpdated+=+new+DateTime(2007,11,05);|2967376|在第一种方法中，您可以在最后三个参数的参数中分别指定小时、分钟和秒。|2967377|entityMap^0|0|0|1|0|0|0|1|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@$D|W|E|X|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|Y|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|Z|8|@$D|10|E|11|F|G]]|9|@]|A|$]]|$1|O|3|P|5|J|7|12|8|@]|9|@]|A|$K|L]]|$1|Q|3|R|5|6|7|13|8|@]|9|@]|A|$]]|$1|S|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|T|$]]

Both are same....

1

<pre><code>mySmallVuln.Published = new DateTime(1998,04,30,0,0,0);
mySmallVuln.LastUpdated = new DateTime(2007,11,05,0,0,0);
</code></pre>

2 

<pre><code>mySmallVuln.Published = new DateTime(1998,04,30);
mySmallVuln.LastUpdated = new DateTime(2007,11,05);
</code></pre>

in the first method you can assign hour minute and second respectively in parameter at the last three parameter.

blocks|key|2967398|text|您可以解析一个字符串，就像您的字符串一样。或者，您可以使用数字实例化DateTime对象。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2967399|DateTime+date1+=+new+DateTime(1998,+04,+30);
DateTime+date2+=+DateTime.ParseExact("1998,04,30",+"yyyy,MM,dd",+CultureInfo.InvariantCulture);|code-block|syntax|javascript|2967400|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can either parse a string, like yours. Or you can instansiate a DateTime object with numbers.

<pre><code>DateTime date1 = new DateTime(1998, 04, 30);
DateTime date2 = DateTime.ParseExact("1998,04,30", "yyyy,MM,dd", CultureInfo.InvariantCulture);
</code></pre>

blocks|key|2754802|text|您正在使用只能包含一个字符的字符文字''。如果您想使用字符串文字，请改用""。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2754803|C#不支持DateTime-literals，而不支持VB.NET+(#4/30/1998#)。|2754804|除此之外，字符串不是DateTime。如果你有一个字符串，你需要先把它解析成DateTime：|2754805|string+published+=+"1998,04,30";
DateTime+dtPublished+=+DateTime.ParseExact(published,+"yyyy,MM,dd",+CultureInfo.InvariantCulture);
mySmallVuln.Published+=+dtPublished;+|code-block|syntax|javascript|2754806|或者您可以通过构造函数创建一个DateTime：|2754807|DateTime+dtPublished+=+new+DateTime(1998,+04,+30);|2754808|或者，由于字符串包含年、月和日作为字符串，因此可以使用String.Split和int.Parse|2754809|string[]+tokens+=+published.Split(',');
if+(tokens.Length+==+3+&&+tokens.All(t+=>+t.All(Char.IsDigit)))
{
++++int+year+=+int.Parse(tokens[0]);
++++int+month+=+int.Parse(tokens[1]);
++++int+day+=+int.Parse(tokens[2]);
++++dtPublished+=+new+DateTime(year,+month,+day);
}|2754810|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/3eaydw6e.aspx^0|I|2|10|2|0|5|8|Z|B|R|6|0|0|A|8|12|8|0|0|F|8|0|0|R|C|14|9|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@$9|15|A|16|B|C]|$9|17|A|18|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|19|8|@$9|1A|A|1B|B|C]|$9|1C|A|1D|B|C]]|D|@$9|1E|A|1F|1|1G]]|E|$]]|$1|H|3|I|5|6|7|1H|8|@$9|1I|A|1J|B|C]|$9|1K|A|1L|B|C]]|D|@]|E|$]]|$1|J|3|K|5|L|7|1M|8|@]|D|@]|E|$M|N]]|$1|O|3|P|5|6|7|1N|8|@$9|1O|A|1P|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|L|7|1Q|8|@]|D|@]|E|$M|N]]|$1|S|3|T|5|6|7|1R|8|@$9|1S|A|1T|B|C]|$9|1U|A|1V|B|C]]|D|@]|E|$]]|$1|U|3|V|5|L|7|1W|8|@]|D|@]|E|$M|N]]|$1|W|3|-4|5|6|7|1X|8|@]|D|@]|E|$]]]|X|$Y|$5|Z|10|11|E|$12|13]]]]

You are using a character literal <code>''</code> which can only contain one character. If you want to use a string literal use <code>""</code> instead.

C# does not support <code>DateTime</code>-literals as opposed to <a href="http://msdn.microsoft.com/en-us/library/3eaydw6e.aspx" rel="nofollow">VB.NET</a> (<code>#4/30/1998#</code>).

Apart from that, a string is not a <code>DateTime</code>. If you have a string you need to parse it to <code>DateTime</code> first:

<pre><code>string published = "1998,04,30";
DateTime dtPublished = DateTime.ParseExact(published, "yyyy,MM,dd", CultureInfo.InvariantCulture);
mySmallVuln.Published = dtPublished; 
</code></pre>

or you can create a <code>DateTime</code> via constructor:

<pre><code>DateTime dtPublished = new DateTime(1998, 04, 30);
</code></pre>

or, since your string contains the year, month and day as strings, using <code>String.Split</code> and <code>int.Parse</code>:

<pre><code>string[] tokens = published.Split(',');
if (tokens.Length == 3 &amp;&amp; tokens.All(t =&gt; t.All(Char.IsDigit)))
{
 int year = int.Parse(tokens[0]);
 int month = int.Parse(tokens[1]);
 int day = int.Parse(tokens[2]);
 dtPublished = new DateTime(year, month, day);
}
</code></pre>

blocks|key|2754877|text|不幸的是，C#不支持日期文字。您应该更改代码并使用new+DateTime(..)实例化DateTime对象，正如thomas在他的回答中所举例说明的那样。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2754878|只是为了扩展这个主题:+VB.NET支持使用#字符的日期文字(具有讽刺意味)。下面是它们在MSDN+documentation中的表达方式|2754879|Dim+d+As+Date
d+=+#+8/23/1970+3:45:39AM+#
d+=+#+8/23/1970+#++++++++++++++'+Date+value:+8/23/1970+12:00:00AM.
d+=+#+3:45:39AM+#++++++++++++++'+Date+value:+1/1/1+3:45:39AM.
d+=+#+3:45:39+#++++++++++++++++'+Date+value:+1/1/1+3:45:39AM.
d+=+#+13:45:39+#+++++++++++++++'+Date+value:+1/1/1+1:45:39PM.
d+=+#+1AM+#++++++++++++++++++++'+Date+value:+1/1/1+1:00:00AM.
d+=+#+13:45:39PM+#+++++++++++++'+This+date+value+is+not+valid.|code-block|syntax|javascript|2754880|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/aa711653%2528v=vs.71%2529.aspx^0|P|G|0|19|I|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|X|8|@]|D|@$9|Y|A|Z|1|10]]|E|$]]|$1|H|3|I|5|J|7|11|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|12|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]]]

Unfortunately, C# does not support Date literals. You should change your code and instantiate the DateTime objects using <code>new DateTime(..)</code>, as thomas exemplified in his answer.

Just for the sake of expanding on this topic: VB.NET supports date literals using the # character (ironically). This is how they can be expressed, from the <a href="http://msdn.microsoft.com/en-us/library/aa711653%28v=vs.71%29.aspx" rel="nofollow">MSDN documentation</a>:

<pre><code>Dim d As Date
d = # 8/23/1970 3:45:39AM #
d = # 8/23/1970 # ' Date value: 8/23/1970 12:00:00AM.
d = # 3:45:39AM # ' Date value: 1/1/1 3:45:39AM.
d = # 3:45:39 # ' Date value: 1/1/1 3:45:39AM.
d = # 13:45:39 # ' Date value: 1/1/1 1:45:39PM.
d = # 1AM # ' Date value: 1/1/1 1:00:00AM.
d = # 13:45:39PM # ' This date value is not valid.
</code></pre>

blocks|key|161433|text|如果你搜索你得到的错误，你将会find|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|161434|161435|这是因为，在C#中，单引号('')表示(或封装)单个字符，而双引号("")用于字符串。|blockquote|161436|161437|161438|因此，您将尝试：|161439|DateTime+foo+=+"2014,02,20";|code-block|syntax|javascript|161440|这会产生：|161441|161442|不能将类型“string”隐式转换为“System.DateTime”|161443|161444|161445|现在，如果您搜索该错误，您将使用find|161446|int+StartYear+=+2012;
int+StartMonth+=+06;
int+StartDay+=+15;

DateTime+dt+=+new+DateTime(StartYear,+StartMonth,+StartDay);|161447|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/5606664/getting-a-too-many-characters-in-charater-literal-error-please-help|1|https://stackoverflow.com/questions/11094587/cannot-implicitly-convert-type-string-to-system-date-time-but-declare-in-datetim^0|F|4|0|0|0|0|0|0|0|0|0|0|0|0|0|G|4|1|0|0^^$0|@$1|2|3|4|5|6|7|1B|8|@]|9|@$A|1C|B|1D|1|1E]]|C|$]]|$1|D|3|-4|5|6|7|1F|8|@]|9|@]|C|$]]|$1|E|3|F|5|G|7|1G|8|@]|9|@]|C|$]]|$1|H|3|-4|5|6|7|1H|8|@]|9|@]|C|$]]|$1|I|3|-4|5|6|7|1I|8|@]|9|@]|C|$]]|$1|J|3|K|5|6|7|1J|8|@]|9|@]|C|$]]|$1|L|3|M|5|N|7|1K|8|@]|9|@]|C|$O|P]]|$1|Q|3|R|5|6|7|1L|8|@]|9|@]|C|$]]|$1|S|3|-4|5|6|7|1M|8|@]|9|@]|C|$]]|$1|T|3|U|5|G|7|1N|8|@]|9|@]|C|$]]|$1|V|3|-4|5|6|7|1O|8|@]|9|@]|C|$]]|$1|W|3|-4|5|6|7|1P|8|@]|9|@]|C|$]]|$1|X|3|Y|5|6|7|1Q|8|@]|9|@$A|1R|B|1S|1|1T]]|C|$]]|$1|Z|3|10|5|N|7|1U|8|@]|9|@]|C|$O|P]]|$1|11|3|-4|5|6|7|1V|8|@]|9|@]|C|$]]]|12|$13|$5|14|15|16|C|$17|18]]|19|$5|14|15|16|C|$17|1A]]]]

If you search for the error you get, you'll <a href="https://stackoverflow.com/questions/5606664/getting-a-too-many-characters-in-charater-literal-error-please-help">find</a>:

<blockquote>
 This is because, in C#, single quotes ('') denote (or encapsulate) a single character, whereas double quotes ("") are used for a string of characters.
</blockquote>

So you'll try:

<pre><code>DateTime foo = "2014,02,20";
</code></pre>

Which yields:

<blockquote>
 Cannot implicitly convert type 'string' to 'System.DateTime'
</blockquote>

Now if you search for that error, you'll <a href="https://stackoverflow.com/questions/11094587/cannot-implicitly-convert-type-string-to-system-date-time-but-declare-in-datetim">find</a>:

<pre><code>int StartYear = 2012;
int StartMonth = 06;
int StartDay = 15;

DateTime dt = new DateTime(StartYear, StartMonth, StartDay);
</code></pre>

blocks|key|160473|text|+DateTime+d+=+default(DateTime);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|160474|default关键字也适用于所有数据类型！|unstyled|160475|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code> DateTime d = default(DateTime);
</code></pre>

The default keyword works for all data types too!

I am absolutly new in C# (I came from Java) and I have a very stupid problem

I have to initialize some DateTime fields into an object but I have some problems doing it.

In particular I am trying to inizialize these fields in this way:

<pre><code>mySmallVuln.Published = '1998,04,30';
mySmallVuln.LastUpdated = '2007,11,05';
</code></pre>

But Visual Studio sign me it as error 

<blockquote>
 Too many characters in character literal
</blockquote>

What am I missing? How to solve it?

How to initialize a DateTime field?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我是C#的新手(我来自Java)，我有一个非常愚蠢的问题我必须将一些DateTime字段初始化为一个对象，但我在做这件事时遇到了一些问题。特别是，我正在尝试以这种方式初始化这些字段：mySmallVuln.Published = '1998,04,30';mySmallVuln.LastUpdated = '2007,...

问如何初始化DateTime字段？
EN

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问如何初始化DateTime字段？
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