我正在尝试检索目录中的所有图像,包括所有子目录。我目前正在使用
$images = glob("{images/portfolio/*.jpg,images/portfolio/*/*.jpg,images/portfolio/*/*/*.jpg,images/portfolio/*/*/*/*.jpg}",GLOB_BRACE);
这是可行的,但是结果是:
images/portfolio/1.jpg
images/portfolio/2.jpg
images/portfolio/subdirectory1/1.jpg
images/portfolio/subdirectory1/2.jpg
images/portfolio/subdirectory2/1.jpg
images/portfolio/subdirectory2/2.jpg
images/portfolio/subdirectory1/subdirectory1/1.jpg
images/portfolio/subdirectory1/subdirectory1/2.jpg
我希望它一次执行一个完整的目录分支,因此结果是:
images/portfolio/1.jpg
images/portfolio/2.jpg
images/portfolio/subdirectory1/1.jpg
images/portfolio/subdirectory1/2.jpg
images/portfolio/subdirectory1/subdirectory1/1.jpg
images/portfolio/subdirectory1/subdirectory1/2.jpg
images/portfolio/subdirectory2/1.jpg
images/portfolio/subdirectory2/2.jpg
非常感谢大家的帮助,干杯!
附注:如果我能得到portfolio下的所有子目录,而不必用通配符明确地说明每个目录,那就太好了。
发布于 2012-08-24 20:04:30
if ( ! function_exists('glob_recursive'))
{
// Does not support flag GLOB_BRACE
function glob_recursive($pattern, $flags = 0)
{
$files = glob($pattern, $flags);
foreach (glob(dirname($pattern).'/*', GLOB_ONLYDIR|GLOB_NOSORT) as $dir)
{
$files = array_merge($files, glob_recursive($dir.'/'.basename($pattern), $flags));
}
return $files;
}
}
发布于 2017-09-08 04:15:59
此函数支持GLOB_BRACE:
function rglob($pattern_in, $flags = 0) {
$patterns = array ();
if ($flags & GLOB_BRACE) {
$matches;
if (preg_match_all ( '#\{[^.\}]*\}#i', $pattern_in, $matches )) {
// Get all GLOB_BRACE entries.
$brace_entries = array ();
foreach ( $matches [0] as $index => $match ) {
$brace_entries [$index] = explode ( ',', substr ( $match, 1, - 1 ) );
}
// Create cartesian product.
// @source: https://stackoverflow.com/questions/6311779/finding-cartesian-product-with-php-associative-arrays
$cart = array (
array ()
);
foreach ( $brace_entries as $key => $values ) {
$append = array ();
foreach ( $cart as $product ) {
foreach ( $values as $item ) {
$product [$key] = $item;
$append [] = $product;
}
}
$cart = $append;
}
// Create multiple glob patterns based on the cartesian product.
foreach ( $cart as $vals ) {
$c_pattern = $pattern_in;
foreach ( $vals as $index => $val ) {
$c_pattern = preg_replace ( '/' . $matches [0] [$index] . '/', $val, $c_pattern, 1 );
}
$patterns [] = $c_pattern;
}
} else
$patterns [] = $pattern_in;
} else
$patterns [] = $pattern_in;
// @source: http://php.net/manual/en/function.glob.php#106595
$result = array ();
foreach ( $patterns as $pattern ) {
$files = glob ( $pattern, $flags );
foreach ( glob ( dirname ( $pattern ) . '/*', GLOB_ONLYDIR | GLOB_NOSORT ) as $dir ) {
$files = array_merge ( $files, rglob ( $dir . '/' . basename ( $pattern ), $flags ) );
}
$result = array_merge ( $result, $files );
}
return $result;
}
发布于 2017-11-19 02:34:34
简单的类:
<?php
class AllFiles {
public $files = [];
function __construct($folder) {
$this->read($folder);
}
function read($folder) {
$folders = glob("$folder/*", GLOB_ONLYDIR);
foreach ($folders as $folder) {
$this->files[] = $folder . "/";
$this->read( $folder );
}
$files = array_filter(glob("$folder/*"), 'is_file');
foreach ($files as $file) {
$this->files[] = $file;
}
}
function __toString() {
return implode( "\n", $this->files );
}
};
$allfiles = new AllFiles("baseq3");
echo $allfiles;
输出示例:
baseq3/gfx/
baseq3/gfx/2d/
baseq3/gfx/2d/numbers/
baseq3/gfx/2d/numbers/eight_32b.tga
baseq3/gfx/2d/numbers/five_32b.tga
baseq3/gfx/2d/numbers/four_32b.tga
baseq3/gfx/2d/numbers/minus_32b.tga
baseq3/gfx/2d/numbers/nine_32b.tga
如果你不想要列表中的文件夹,只需注释掉这一行:
$this->files[] = $folder . "/";
https://stackoverflow.com/questions/12109042
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