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社区首页 >问答首页 >PHP get文件列表,包括子目录

PHP get文件列表,包括子目录
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Stack Overflow用户
提问于 2012-08-24 20:00:21
回答 3查看 42.9K关注 0票数 28

我正在尝试检索目录中的所有图像,包括所有子目录。我目前正在使用

代码语言:javascript
复制
$images = glob("{images/portfolio/*.jpg,images/portfolio/*/*.jpg,images/portfolio/*/*/*.jpg,images/portfolio/*/*/*/*.jpg}",GLOB_BRACE);

这是可行的,但是结果是:

代码语言:javascript
复制
images/portfolio/1.jpg
images/portfolio/2.jpg
images/portfolio/subdirectory1/1.jpg
images/portfolio/subdirectory1/2.jpg
images/portfolio/subdirectory2/1.jpg
images/portfolio/subdirectory2/2.jpg
images/portfolio/subdirectory1/subdirectory1/1.jpg
images/portfolio/subdirectory1/subdirectory1/2.jpg

我希望它一次执行一个完整的目录分支,因此结果是:

代码语言:javascript
复制
images/portfolio/1.jpg
images/portfolio/2.jpg
images/portfolio/subdirectory1/1.jpg
images/portfolio/subdirectory1/2.jpg
images/portfolio/subdirectory1/subdirectory1/1.jpg
images/portfolio/subdirectory1/subdirectory1/2.jpg
images/portfolio/subdirectory2/1.jpg
images/portfolio/subdirectory2/2.jpg

非常感谢大家的帮助,干杯!

附注:如果我能得到portfolio下的所有子目录,而不必用通配符明确地说明每个目录,那就太好了。

EN

回答 3

Stack Overflow用户

回答已采纳

发布于 2012-08-24 20:04:30

来自glob example

代码语言:javascript
复制
if ( ! function_exists('glob_recursive'))
{
    // Does not support flag GLOB_BRACE        
   function glob_recursive($pattern, $flags = 0)
   {
     $files = glob($pattern, $flags);
     foreach (glob(dirname($pattern).'/*', GLOB_ONLYDIR|GLOB_NOSORT) as $dir)
     {
       $files = array_merge($files, glob_recursive($dir.'/'.basename($pattern), $flags));
     }
     return $files;
   }
}
票数 34
EN

Stack Overflow用户

发布于 2017-09-08 04:15:59

此函数支持GLOB_BRACE:

代码语言:javascript
复制
function rglob($pattern_in, $flags = 0) {
    $patterns = array ();
    if ($flags & GLOB_BRACE) {
        $matches;
        if (preg_match_all ( '#\{[^.\}]*\}#i', $pattern_in, $matches )) {
            // Get all GLOB_BRACE entries.
            $brace_entries = array ();
            foreach ( $matches [0] as $index => $match ) {
                $brace_entries [$index] = explode ( ',', substr ( $match, 1, - 1 ) );
            }

            // Create cartesian product.
            // @source: https://stackoverflow.com/questions/6311779/finding-cartesian-product-with-php-associative-arrays
            $cart = array (
                    array () 
            );
            foreach ( $brace_entries as $key => $values ) {
                $append = array ();
                foreach ( $cart as $product ) {
                    foreach ( $values as $item ) {
                        $product [$key] = $item;
                        $append [] = $product;
                    }
                }
                $cart = $append;
            }

            // Create multiple glob patterns based on the cartesian product.
            foreach ( $cart as $vals ) {
                $c_pattern = $pattern_in;
                foreach ( $vals as $index => $val ) {
                    $c_pattern = preg_replace ( '/' . $matches [0] [$index] . '/', $val, $c_pattern, 1 );
                }
                $patterns [] = $c_pattern;
            }
        } else
            $patterns [] = $pattern_in;
    } else
        $patterns [] = $pattern_in;

    // @source: http://php.net/manual/en/function.glob.php#106595
    $result = array ();
    foreach ( $patterns as $pattern ) {
        $files = glob ( $pattern, $flags );
        foreach ( glob ( dirname ( $pattern ) . '/*', GLOB_ONLYDIR | GLOB_NOSORT ) as $dir ) {
            $files = array_merge ( $files, rglob ( $dir . '/' . basename ( $pattern ), $flags ) );
        }
        $result = array_merge ( $result, $files );
    }
    return $result;
}
票数 1
EN

Stack Overflow用户

发布于 2017-11-19 02:34:34

简单的类:

代码语言:javascript
复制
<?php
    class AllFiles {
        public $files = [];
        function __construct($folder) {
            $this->read($folder);           
        }
        function read($folder) {
            $folders = glob("$folder/*", GLOB_ONLYDIR);
            foreach ($folders as $folder) {
                $this->files[] = $folder . "/";
                $this->read( $folder );
            }
            $files = array_filter(glob("$folder/*"), 'is_file');
            foreach ($files as $file) {
                $this->files[] = $file;             
            }
        }
        function __toString() {
            return implode( "\n", $this->files );
        }
    };

    $allfiles = new AllFiles("baseq3");
    echo $allfiles;

输出示例:

代码语言:javascript
复制
baseq3/gfx/
baseq3/gfx/2d/
baseq3/gfx/2d/numbers/
baseq3/gfx/2d/numbers/eight_32b.tga
baseq3/gfx/2d/numbers/five_32b.tga
baseq3/gfx/2d/numbers/four_32b.tga
baseq3/gfx/2d/numbers/minus_32b.tga
baseq3/gfx/2d/numbers/nine_32b.tga

如果你不想要列表中的文件夹,只需注释掉这一行:

代码语言:javascript
复制
$this->files[] = $folder . "/";
票数 1
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/12109042

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