blocks|key|119272|text|你应该简单地写成|type|unstyled|depth|inlineStyleRanges|entityRanges|data|119273|var+continousDigitsRange1:Range<Int>+=+0..<0|code-block|syntax|javascript|119274|或者，如果您想要更简单|119275|var+continousDigitsRange+=+0..<0|119276|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

You should simply write

<pre><code>var continousDigitsRange1:Range&lt;Int&gt; = 0..&lt;0
</code></pre>

or if you want to go even simpler

<pre><code>var continousDigitsRange = 0..&lt;0
</code></pre>

blocks|key|119285|text|同样值得注意的是，要对字符串执行substringWithRange操作，现在可以使用|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|119286|let+theString+=+"Hello,+how+are+you"
let+range+=+theString.startIndex.advancedBy(start)+..<+theString.startIndex.advancedBy(end)
theString.substringWithRange(range)|code-block|syntax|javascript|119287|entityMap^0|G|I|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Also worth noting, to <code>substringWithRange</code> a String, you can now use

<pre><code>let theString = "Hello, how are you"
let range = theString.startIndex.advancedBy(start) ..&lt; theString.startIndex.advancedBy(end)
theString.substringWithRange(range)
</code></pre>

blocks|key|2668328|text|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2668329|闭合范围运算符(a...b)定义从a到b的范围，包括值a和b。a的值不能大于b。|blockquote|offset|length|style|CODE|2668330|2668331|半开范围运算符(a..<b)定义了一个从a到b的范围，但不包括b。之所以说它是半开范围，是因为它包含第一个值，但不包含最后一个值。与闭合范围运算符一样，a的值不能大于b。如果a的值等于b，则结果范围将为空。|2668332|2668333|The+Swift+Programming+Language+(Swift+2.2)+-+Basic+Operators|2668334|var+continousDigitsRange:Range<Int>+=+Range<Int>(start:+0,+end:+0)
--to--
var+continousDigitsRange:Range<Int>+=+0..<0|code-block|syntax|javascript|2668335|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.apple.com/library/ios/documentation/Swift/Conceptual/Swift_Programming_Language/BasicOperators.html^0|0|7|7|0|0|7|7|0|0|0|1O|0|0|0^^$0|@$1|2|3|-4|4|5|6|10|7|@]|8|@]|9|$]]|$1|A|3|B|4|C|6|11|7|@$D|12|E|13|F|G]]|8|@]|9|$]]|$1|H|3|-4|4|5|6|14|7|@]|8|@]|9|$]]|$1|I|3|J|4|5|6|15|7|@$D|16|E|17|F|G]]|8|@]|9|$]]|$1|K|3|-4|4|5|6|18|7|@]|8|@]|9|$]]|$1|L|3|M|4|5|6|19|7|@]|8|@$D|1A|E|1B|1|1C]]|9|$]]|$1|N|3|O|4|P|6|1D|7|@]|8|@]|9|$Q|R]]|$1|S|3|-4|4|5|6|1E|7|@]|8|@]|9|$]]]|T|$U|$4|V|W|X|9|$Y|Z]]]]

<blockquote>
 The closed range operator <code>(a...b)</code> defines a range that runs from a
 to b, and includes the values a and b. The value of a must not be
 greater than b.
 
 The half-open range operator <code>(a..&lt;b)</code> defines a range that runs from a
 to b, but does not include b. It is said to be half-open because it
 contains its first value, but not its final value. As with the closed
 range operator, the value of a must not be greater than b. If the
 value of a is equal to b, then the resulting range will be empty.
</blockquote>

<a href="https://developer.apple.com/library/ios/documentation/Swift/Conceptual/Swift_Programming_Language/BasicOperators.html" rel="noreferrer">The Swift Programming Language (Swift 2.2) - Basic Operators</a>

<pre><code>var continousDigitsRange:Range&lt;Int&gt; = Range&lt;Int&gt;(start: 0, end: 0)
--to--
var continousDigitsRange:Range&lt;Int&gt; = 0..&lt;0
</code></pre>

blocks|key|119190|text|为了完整地展示bmichotte的答案...|type|unstyled|depth|inlineStyleRanges|entityRanges|data|119191|let+theString+=+"Hello,+how+are+you+today+my+friend"
++++let+start+=+3
++++let+end+=+15
++++let+range+=+theString.startIndex.advancedBy(start)+..<+theString.startIndex.advancedBy(end)
++++let+p+=+theString.substringWithRange(range)
++++print("this+is+the+middle+bit>\(p)<")|code-block|syntax|javascript|119192|这产生了这是中间的bit>lo，如何是<|119193|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

to show bmichotte's answer in full...

<pre><code>let theString = "Hello, how are you today my friend"
 let start = 3
 let end = 15
 let range = theString.startIndex.advancedBy(start) ..&lt; theString.startIndex.advancedBy(end)
 let p = theString.substringWithRange(range)
 print("this is the middle bit&gt;\(p)&lt;")
</code></pre>

this produces this is the middle bit>lo, how are &lt;

blocks|key|116405|text|参考swift+3.0增加了一些要点|type|unstyled|depth|inlineStyleRanges|entityRanges|data|116406|//可数区间示例。|116407|let+range1+=+0..<5|offset|length|style|CODE|116408|可数闭值域示例|116409|let+range2+=+0...5|code-block|syntax|javascript|116410|//范围从边界开始|116411|let+range+=+Range(uncheckedBounds:+(range1.lowerBound,range1.upperBound))|116412|//获取与substringRange的距离。|116413|let+str+=+"Hello,+how+are+you"
let+substringRange+=+str.characters.indices|116414|//低于Swift+3.0|116415|let+length+=+substringRange.distance(from:+substringRange.startIndex,+to:+substringRange.endIndex)|116416|//对于Swift+3.0|116417|let+length2+=+str.distance(from:+substringRange.startIndex,+to:+substringRange.endIndex)|116418|entityMap^0|0|0|0|I|0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|18|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|19|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|1A|8|@$F|1B|G|1C|H|I]]|9|@]|A|$]]|$1|J|3|K|5|6|7|1D|8|@]|9|@]|A|$]]|$1|L|3|M|5|N|7|1E|8|@]|9|@]|A|$O|P]]|$1|Q|3|R|5|6|7|1F|8|@]|9|@]|A|$]]|$1|S|3|T|5|N|7|1G|8|@]|9|@]|A|$O|P]]|$1|U|3|V|5|6|7|1H|8|@]|9|@]|A|$]]|$1|W|3|X|5|N|7|1I|8|@]|9|@]|A|$O|P]]|$1|Y|3|Z|5|6|7|1J|8|@]|9|@]|A|$]]|$1|10|3|11|5|N|7|1K|8|@]|9|@]|A|$O|P]]|$1|12|3|13|5|6|7|1L|8|@]|9|@]|A|$]]|$1|14|3|15|5|N|7|1M|8|@]|9|@]|A|$O|P]]|$1|16|3|-4|5|6|7|1N|8|@]|9|@]|A|$]]]|17|$]]

Adding some points with reference to swift 3.0

//Countable Range Example.

<code>let range1 = 0..&lt;5</code>

Countable Closed Range Example

<pre><code>let range2 = 0...5
</code></pre>

//Range from bounds

<pre><code>let range = Range(uncheckedBounds: (range1.lowerBound,range1.upperBound))
</code></pre>

//To get the distance from substringRange.

<pre><code>let str = "Hello, how are you"
let substringRange = str.characters.indices
</code></pre>

// Below Swift 3.0

<pre><code>let length = substringRange.distance(from: substringRange.startIndex, to: substringRange.endIndex)
</code></pre>

//For Swift 3.0

<pre><code>let length2 = str.distance(from: substringRange.startIndex, to: substringRange.endIndex)
</code></pre>

blocks|key|2879775|text|我一直有一个函数来获取字符串的子字符串范围。这是我为Swift+3更新的函数：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2879776|func+getSubStringRange(fullString:+String,+fromIndex:+Int,+subStringSize:+Int)+->+Range<String.Index>+{
++++let+startIndex+=+fullString.characters.index(fullString.startIndex,+offsetBy:+fromIndex)
++++let+endIndex+=+fullString.characters.index(startIndex,+offsetBy:+subStringSize)

++++let+subStringRange+=+startIndex..<endIndex

++++return+subStringRange
}|code-block|syntax|javascript|2879777|该函数非常简单明了-传入一个字符串(FullString)、该子字符串开头的字符串的索引(FromIndex)以及substring的大小(SubStringSize)。|2879778|示例：|2879779|let+greeting+=+"Hi,+my+name+is+Nathaniel"
let+getName+=+greeting[getSubStringRange(fullString:+greeting,+fromIndex:+15,+subStringSize:+9)]

print("Name:+\(getName)")|2879780|->打印：“姓名:纳撒尼尔”|2879781|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|U|8|@]|9|@]|A|$E|F]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

I have always had a function to get the substring range of a string. Here is my updated function for Swift 3:

<pre><code>func getSubStringRange(fullString: String, fromIndex: Int, subStringSize: Int) -&gt; Range&lt;String.Index&gt; {
 let startIndex = fullString.characters.index(fullString.startIndex, offsetBy: fromIndex)
 let endIndex = fullString.characters.index(startIndex, offsetBy: subStringSize)

 let subStringRange = startIndex..&lt;endIndex

 return subStringRange
}
</code></pre>

The function is pretty self explanatory - You pass in a string(fullString), the index of that string where the substring starts(fromIndex) and how big the subString is(subStringSize).

Example:

<pre><code>let greeting = "Hi, my name is Nathaniel"
let getName = greeting[getSubStringRange(fullString: greeting, fromIndex: 15, subStringSize: 9)]

print("Name: \(getName)")
</code></pre>

-> Prints: "Name: Nathaniel"

I'm using the following code:

<pre><code>var continousDigitsRange:Range&lt;Int&gt; = Range&lt;Int&gt;(start: 0, end: 0)
</code></pre>

Since update to Xcode 7.3 (Swift 2.2) I got the following hint:

<blockquote>
 'init(start:end:)' is deprecated: it will be removed in Swift 3. Use
 the '..&lt;' operator.
</blockquote>

For me is not clear how to "translate" it correctly with "using the '..&lt;' operator.

'init(start:end:)' is deprecated: it will be removed in Swift 3. Use the '..<' operator

Swift

Xcode

我使用了以下代码：var continousDigitsRange:Range<Int> = Range<Int>(start: 0, end: 0)自从更新到Xcode 7.3 (Swift 2.2)后，我得到了以下提示： 'init(start:end:)‘已弃用:它将在Swift 3中删除。请使用'..<’运算符。对于我来说，不清楚如何使用“..<”运算符正确地“翻译”它。

问“‘init(start:end：)”已弃用:它将在Swift 3中删除。请使用“..<”运算符
EN

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问“‘init(start:end：)”已弃用:它将在Swift 3中删除。请使用“..<”运算符EN

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问“‘init(start:end：)”已弃用:它将在Swift 3中删除。请使用“..<”运算符
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