blocks|key|1483084|text|试一试|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1483085|char+str[11];
scanf("%2510[0-9a-zA-Z+]",+str);|code-block|syntax|javascript|1483086|希望这能有所帮助。|1483087|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Try

<pre><code>char str[11];
scanf("%10[0-9a-zA-Z ]", str);
</code></pre>

Hope that helps.

blocks|key|1483204|text|这个示例使用了一个倒置的scanset，所以scanf一直在接受值，直到它遇到'\n'--+newline，这样也节省了空格|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1483205|#include+<stdio.h>

int+main+(int+argc,+char+const+*argv[])
{
++++char+name[20];

++++//+get+up+to+buffer+size+-+1+characters+(to+account+for+NULL+terminator)
++++scanf("%2519[%5E\n]",+name);
++++printf("%25s\n",+name);
++++return+0;
}|code-block|syntax|javascript|1483206|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This example uses an inverted scanset, so scanf keeps taking in values until it encounters a '\n'-- newline, so spaces get saved as well
<pre><code>#include &lt;stdio.h&gt;

int main (int argc, char const *argv[])
{
 char name[20];

 // get up to buffer size - 1 characters (to account for NULL terminator)
 scanf(&quot;%19[^\n]&quot;, name);
 printf(&quot;%s\n&quot;, name);
 return 0;
}
</code></pre>

blocks|key|1483253|text|你可以使用这个|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1483254|char+name[20];
scanf("%2520[%5E\n]",+name);|code-block|syntax|javascript|1483255|或者这个|1483256|void+getText(char+*message,+char+*variable,+int+size){
++++printf("\n+%25s:+",+message);
++++fgets(variable,+sizeof(char)+*+size,+stdin);
++++sscanf(variable,+"%25[%5E\n]",+variable);
}

char+name[20];
getText("Your+name",+name,+20);|1483257|DEMO|offset|length|1483258|entityMap|0|LINK|mutability|MUTABLE|url|http://www.tutorialspoint.com/compile_c_online.php?PID=0Bw_CjBb95KQMeVpEcThtcDRoUDQ^0|0|0|0|0|0|4|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|10|8|@]|9|@$M|11|N|12|1|13]]|A|$]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

You can use this

<pre><code>char name[20];
scanf("%20[^\n]", name);
</code></pre>

Or this

<pre><code>void getText(char *message, char *variable, int size){
 printf("\n %s: ", message);
 fgets(variable, sizeof(char) * size, stdin);
 sscanf(variable, "%[^\n]", variable);
}

char name[20];
getText("Your name", name, 20);
</code></pre>

<a href="http://www.tutorialspoint.com/compile_c_online.php?PID=0Bw_CjBb95KQMeVpEcThtcDRoUDQ" rel="noreferrer">DEMO</a>

blocks|key|1483134|text|不要在没有指定字段宽度的情况下使用scanf()读取字符串。您还应该检查返回值是否有错误：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1483135|#include+<stdio.h>

#define+NAME_MAX++++80
#define+NAME_MAX_S+"80"

int+main(void)
{
++++static+char+name[NAME_MAX+%2B+1];+//+%2B+1+because+of+null
++++if(scanf("%25"+NAME_MAX_S+"[%5E\n]",+name)+!=+1)
++++{
++++++++fputs("io+error+or+premature+end+of+line\n",+stderr);
++++++++return+1;
++++}

++++printf("Hello+%25s.+Nice+to+meet+you.\n",+name);
}|code-block|syntax|javascript|1483136|或者，使用fgets()|1483137|#include+<stdio.h>

#define+NAME_MAX+80

int+main(void)
{
++++static+char+name[NAME_MAX+%2B+2];+//+%2B+2+because+of+newline+and+null
++++if(!fgets(name,+sizeof(name),+stdin))
++++{
++++++++fputs("io+error\n",+stderr);
++++++++return+1;
++++}

++++//+don't+print+newline
++++printf("Hello+%25.*s.+Nice+to+meet+you.\n",+strlen(name)+-+1,+name);
}|1483138|entityMap^0|H|7|0|0|5|7|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|Y|8|@]|D|@]|E|$]]]|P|$]]

Don't use <code>scanf()</code> to read strings without specifying a field width. You should also check the return values for errors:

<pre><code>#include &lt;stdio.h&gt;

#define NAME_MAX 80
#define NAME_MAX_S "80"

int main(void)
{
 static char name[NAME_MAX + 1]; // + 1 because of null
 if(scanf("%" NAME_MAX_S "[^\n]", name) != 1)
 {
 fputs("io error or premature end of line\n", stderr);
 return 1;
 }

 printf("Hello %s. Nice to meet you.\n", name);
}
</code></pre>

Alternatively, use <code>fgets()</code>:

<pre><code>#include &lt;stdio.h&gt;

#define NAME_MAX 80

int main(void)
{
 static char name[NAME_MAX + 2]; // + 2 because of newline and null
 if(!fgets(name, sizeof(name), stdin))
 {
 fputs("io error\n", stderr);
 return 1;
 }

 // don't print newline
 printf("Hello %.*s. Nice to meet you.\n", strlen(name) - 1, name);
}
</code></pre>

blocks|key|1483236|text|您可以使用fgets()函数读取字符串，也可以使用scanf("%25[%5E\n]s",name);，这样字符串读取将在遇到换行符时终止。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1483237|entityMap^0|5|7|P|M|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|M|8|@]|D|@]|E|$]]]|G|$]]

You can use the <code>fgets()</code> function to read a string or use <code>scanf("%[^\n]s",name);</code> so string reading will terminate upon encountering a newline character.

blocks|key|1483161|text|getline()|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1483162|现在是POSIX的一部分，尽管如此。|1483163|它还解决了您之前询问的缓冲区分配问题，尽管您必须处理内存中的free。|1483164|entityMap|0|LINK|mutability|MUTABLE|url|http://linux.die.net/man/3/getline^0|0|9|0|9|0|0|0|U|4|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]]|D|@$9|U|A|V|1|W]]|E|$]]|$1|F|3|G|5|6|7|X|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|J|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|K|$L|$5|M|N|O|E|$P|Q]]]]

<a href="http://linux.die.net/man/3/getline" rel="nofollow noreferrer"><code>getline()</code></a>

Now part of POSIX, none-the-less.

It also takes care of the buffer allocation problem that you asked about earlier, though you have to take care of <code>free</code>ing the memory.

blocks|key|1483339|text|如果有人还在寻找，这是我的工作-读取包括空格在内的任意长度的字符串。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1483340|感谢网络上的许多帖子分享了这个简单而优雅的解决方案。如果它工作了，功劳归他们，但任何错误都是我的。|1483341|char+*name;
scanf+("%25m[%5E\n]s",&name);
printf+("%25s\n",name);|code-block|syntax|javascript|1483342|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

If someone is still looking, here's what worked for me - to read an arbitrary length of string including spaces.

Thanks to many posters on the web for sharing this simple &amp; elegant solution.
If it works the credit goes to them but any errors are mine.

<pre><code>char *name;
scanf ("%m[^\n]s",&amp;name);
printf ("%s\n",name);
</code></pre>

blocks|key|1268796|text|虽然您真的不应该使用scanf()来做这类事情，因为有更好的调用，比如gets()或getline()，但是可以这样做：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1268797|#include+<stdio.h>

char*+scan_line(char*+buffer,+int+buffer_size);

char*+scan_line(char*+buffer,+int+buffer_size)+{
+++char*+p+=+buffer;
+++int+count+=+0;
+++do+{
+++++++char+c;
+++++++scanf("%25c",+&c);+//+scan+a+single+character
+++++++//+break+on+end+of+line,+string+terminating+NUL,+or+end+of+file
+++++++if+(c+==+'\r'+%7C%7C+c+==+'\n'+%7C%7C+c+==+0+%7C%7C+c+==+EOF)+{
+++++++++++*p+=+0;
+++++++++++break;
+++++++}
+++++++*p%2B%2B+=+c;+//+add+the+valid+character+into+the+buffer
+++}+while+(count+<+buffer_size+-+1);++//+don't+overrun+the+buffer
+++//+ensure+the+string+is+null+terminated
+++buffer[buffer_size+-+1]+=+0;
+++return+buffer;
}

#define+MAX_SCAN_LENGTH+1024

int+main()
{
+++char+s[MAX_SCAN_LENGTH];
+++printf("Enter+a+string:+");
+++scan_line(s,+MAX_SCAN_LENGTH);
+++printf("got:+\"%25s\"\n\n",+s);
+++return+0;
}|code-block|syntax|javascript|1268798|entityMap^0|A|7|Z|6|16|9|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|U|8|@]|D|@]|E|$]]]|L|$]]

While you really shouldn't use <code>scanf()</code> for this sort of thing, because there are much better calls such as <code>gets()</code> or <code>getline()</code>, it can be done:

<pre><code>#include &lt;stdio.h&gt;

char* scan_line(char* buffer, int buffer_size);

char* scan_line(char* buffer, int buffer_size) {
 char* p = buffer;
 int count = 0;
 do {
 char c;
 scanf("%c", &amp;c); // scan a single character
 // break on end of line, string terminating NUL, or end of file
 if (c == '\r' || c == '\n' || c == 0 || c == EOF) {
 *p = 0;
 break;
 }
 *p++ = c; // add the valid character into the buffer
 } while (count &lt; buffer_size - 1); // don't overrun the buffer
 // ensure the string is null terminated
 buffer[buffer_size - 1] = 0;
 return buffer;
}

#define MAX_SCAN_LENGTH 1024

int main()
{
 char s[MAX_SCAN_LENGTH];
 printf("Enter a string: ");
 scan_line(s, MAX_SCAN_LENGTH);
 printf("got: \"%s\"\n\n", s);
 return 0;
}
</code></pre>

blocks|key|1483350|text|/*reading+string+which+contains+spaces*/
#include<stdio.h>
int+main()
{
+++char+*c,*p;
+++scanf("%25[%5E\n]s",c);
+++p=c;++++++++++++++++/*since+after+reading+then+pointer+points+to+another+
+++++++++++++++++++++++location+iam+using+a+second+pointer+to+store+the+base+
+++++++++++++++++++++++address*/+
+++printf("%25s",p);
+++return+0;
+}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1483351|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>/*reading string which contains spaces*/
#include&lt;stdio.h&gt;
int main()
{
 char *c,*p;
 scanf("%[^\n]s",c);
 p=c; /*since after reading then pointer points to another 
 location iam using a second pointer to store the base 
 address*/ 
 printf("%s",p);
 return 0;
 }
</code></pre>

Using the following code:

<pre><code>char *name = malloc(sizeof(char) + 256); 

printf("What is your name? ");
scanf("%s", name);

printf("Hello %s. Nice to meet you.\n", name);
</code></pre>

A user can enter their name but when they enter a name with a space like <code>Lucas Aardvark</code>, <code>scanf()</code> just cuts off everything after <code>Lucas</code>. How do I make <code>scanf()</code> allow spaces

How do you allow spaces to be entered using scanf?

使用以下代码：char *name = malloc(sizeof(char) + 256); printf("What is your name? ");scanf("%s", name);printf("Hello %s. Nice to meet you.\n", name);用户可以输入他们的名字，但是当他们输入一个像Lucas Aardvark这样的空格的名字时，scanf()会在Luc

问如何允许使用scanf输入空格？
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回答 9

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问如何允许使用scanf输入空格？EN

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问如何允许使用scanf输入空格？
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