blocks|key|338521|text|这是Instagram+Developer+Console中的一个问题。max_id和min_id在那里不能工作。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|338522|entityMap|0|LINK|mutability|MUTABLE|url|https://www.instagram.com/developer/^0|10|6|17|6|2|R|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@$9|O|A|P|B|C]|$9|Q|A|R|B|C]]|D|@$9|S|A|T|1|U]]|E|$]]|$1|F|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|G|$H|$5|I|J|K|E|$L|M]]]]

It was a problem in <a href="https://www.instagram.com/developer/" rel="nofollow noreferrer">Instagram Developer Console</a>. <code>max_id</code> and <code>min_id</code> doesn't work there.

blocks|key|338578|text|有关pagination的信息，请参阅http://instagram.com/developer/endpoints/。您需要逐个遍历结果页面，每次都用结果在pagination对象中指定的next_url请求下一个部分。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|338579|entityMap|0|LINK|mutability|MUTABLE|url|http://instagram.com/developer/endpoints/^0|2|A|28|A|2O|8|J|15|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@$9|O|A|P|B|C]|$9|Q|A|R|B|C]|$9|S|A|T|B|C]]|D|@$9|U|A|V|1|W]]|E|$]]|$1|F|3|-4|5|6|7|X|8|@]|D|@]|E|$]]]|G|$H|$5|I|J|K|E|$L|M]]]]

See <a href="http://instagram.com/developer/endpoints/" rel="noreferrer">http://instagram.com/developer/endpoints/</a> for information on <code>pagination</code>. You need to subsequentially step through the result pages, each time requesting the next part with the <code>next_url</code> that the result specifies in the <code>pagination</code> object.

blocks|key|338659|text|你说得对，Instagram+API每次调用只会返回20张图片。因此，您必须使用分页功能。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|338660|如果您正在尝试使用API控制台。您需要首先允许API控制台通过您的Instagram登录进行身份验证。为此，您需要在Authentication下拉列表中选择OAUTH2。|338661|通过身份验证后，使用左侧菜单选择users/{user-id}/media/recent端点。因此，对于{user-id}这篇文章，您可以将其替换为self。然后，这将使用您的帐户检索信息。|338662|至少，这是为该端点执行GET所需的。一旦你发送，你会得到一些json返回给你。在所有服务器信息之后，在返回信息的最顶部，您将看到包含next_url和next_max_id的分页部分。|338663|next_max_id将用作查询的参数。请记住，max_id是最初返回的20个图像中最旧的一个图像的id。这将用于返回早于此图像的图像。|338664|如果您不想使用max_id，则不必使用它。实际上，您只需获取要开始查询更多图像的图像的id即可。|338665|因此，从返回的数据中，将max_id复制到参数max_id中。请求URL应该类似于下面的https://api.instagram.com/v1/users/self/media/recent?max_id=XXXXXXXXXXX，其中XXXXXXXXXXX是max_id。再次点击发送，你应该会得到接下来的20张照片。|offset|length|338666|从那里，您还将收到更新后的max_id。然后，您可以再次使用它来获取下一组20张照片，直到最终遍历用户的所有照片。|338667|在我正在工作的项目中，我所做的是加载从最初的最近媒体请求返回的前20张照片。然后，为图像分配一个data-id+(-id实际上可以是您想要的任何值)。然后在照片集的底部添加了一个load+more按钮。|338668|单击按钮时，我使用jQuery获取最后一个图像及其data-id属性，并使用该属性通过ajax创建一个get调用，并将结果附加到页面上已有照片的末尾。代替一个按钮，你可以简单地替换它，以获得无限的滚动效果。|338669|希望这能有所帮助。|338670|entityMap|0|LINK|mutability|MUTABLE|url|https://api.instagram.com/v1/users/self/media/recent?max_id=XXXXXXXXXXX^0|0|0|0|0|0|0|18|1Z|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|15|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|16|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|17|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|18|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|19|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|1A|8|@]|9|@]|A|$]]|$1|L|3|M|5|6|7|1B|8|@]|9|@$N|1C|O|1D|1|1E]]|A|$]]|$1|P|3|Q|5|6|7|1F|8|@]|9|@]|A|$]]|$1|R|3|S|5|6|7|1G|8|@]|9|@]|A|$]]|$1|T|3|U|5|6|7|1H|8|@]|9|@]|A|$]]|$1|V|3|W|5|6|7|1I|8|@]|9|@]|A|$]]|$1|X|3|-4|5|6|7|1J|8|@]|9|@]|A|$]]]|Y|$Z|$5|10|11|12|A|$13|14]]]]

You're right, the Instagram API will only return 20 images per call. So you'll have to use the pagination feature.

If you're trying to use the API console. You'll want to first allow the API console to authenticate via your Instagram login. To do this you'll want to select OAUTH2 under the Authentication dropdown.

Once Authenticated, use the left hand side menu to select the users/{user-id}/media/recent endpoint. So for the sake of this post for {user-id} you can just replace it with self. This will then use your account to retrieve information.

At a bare minimum that is what's needed to do a GET for this endpoint. Once you send, you'll get some json returned to you. At the very top of the returned information after all the server info, you'll see a pagination portion with next_url and next_max_id.

next_max_id is what you'll use as a parameter for your query. Remember max_id is the id of the image that is the oldest of the 20 that was first returned. This will be used to return images earlier than this image.

You don't have to use the max_id if you don't want to. You can actually just grab the id of the image where you'd like to start querying more images from.

So from the returned data, copy the max_id into the parameter max_id. The request URL should look something like this <a href="https://api.instagram.com/v1/users/self/media/recent?max_id=XXXXXXXXXXX" rel="noreferrer">https://api.instagram.com/v1/users/self/media/recent?max_id=XXXXXXXXXXX</a> where XXXXXXXXXXX is the max_id. Hit send again and you should get the next 20 photos.

From there you'll also receive an updated max_id. You can then use that again to get the next set of 20 photos until eventually going through all of the user's photos.

What I've done in the project I'm working on is to load the first 20 photos returned from the initial recent media request. I then, assign the images with a data-id (-id can actually be whatever you'd like it to be). Then added a load more button on the bottom of the photo set.

When the button is clicked, I use jQuery to grab the last image and it's data-id attribute and use that to create a get call via ajax and append the results to the end of the photos already on the page. Instead of a button you could just replace it to have a infinite scrolling effect.

Hope that helps.

blocks|key|554750|text|我已经通过将可选参数count设置为-1解决了这个问题。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|554751|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

I've solved this issue with the optional parameter count set to -1.

blocks|key|554809|text|我要做的是(在Javascript中)使用递归函数遍历所有页面。这很危险，因为instagram用户可能有数以千计的图片(所以你必须控制它)我使用以下代码：(count参数，我认为，没有太多作用)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|554810|++++++++instagramLoadDashboard+=+function(hash)
++++{
++++++++code+=+hash.split('=')[1];

++++++++$('#instagram-pictures+.images-list+.container').html('').addClass('loading');


++++++++ts+=+Math.round((new+Date()).getTime()+/+1000);
++++++++url+=+'https://api.instagram.com/v1/users/self/media/recent?count=200&min_timestamp=0&max_timestamp='%2Bts%2B'&access_token='%2Bcode;

++++++++instagramLoadMediaPage(url,+function(){

++++++++++++galleryHTML+=+instagramLoadGallery(instagramData);
++++++++++++//console.log(galleryHTML);
++++++++++++$('#instagram-pictures+.images-list+.container').html(galleryHTML).removeClass('loading');
++++++++++++initImages('#instagram-pictures');

++++++++++++IGStatus+=+'loaded';

++++++++});

++++};

++++instagramLoadMediaPage+=+function+(url,+callback)
++++{
++++++++$.ajax({
++++++++++++++++url+:+url,
++++++++++++++++dataType+:+'jsonp',
++++++++++++++++cache+:+false,
++++++++++++++++success:++function(response){

++++++++++++++++++++++++++++++++++++++++console.log(response);

++++++++++++++++++++++++++++++++++++++++if(response.code+==+'400')
++++++++++++++++++++++++++++++++++++++++{
++++++++++++++++++++++++++++++++++++++++++++alert(response.error_message);
++++++++++++++++++++++++++++++++++++++++++++return+false;
++++++++++++++++++++++++++++++++++++++++}

++++++++++++++++++++++++++++++++++++++++if(response.pagination.next_url+!==+undefined)+{
++++++++++++++++++++++++++++++++++++++++++++instagramData+=+instagramData.concat(response.data);
++++++++++++++++++++++++++++++++++++++++++++return+instagramLoadMediaPage(response.pagination.next_url,callback);
++++++++++++++++++++++++++++++++++++++++}

++++++++++++++++++++++++++++++++++++++++instagramData+=+instagramData.concat(response.data);
++++++++++++++++++++++++++++++++++++++++callback.apply();
++++++++++++++++++++++++++++++++++++}
++++++++});
++++};

++++instagramLoadGallery+=+function(images)
++++{
++++++++galleryHTML+='<ul>';

++++++++for(var+i=0;i<images.length;i%2B%2B)
++++++++{
++++++++++++galleryHTML+%2B=+'<li><img+src="'%2Bimages[i].images.thumbnail.url%2B'"+width="120"+id="instagram-'%2Bimages[i].id%2B'+data-type="instagram"+data-source="'%2Bimages[i].images.standard_resolution.url%2B'"+class="image"/></li>';

++++++++}

++++++++galleryHTML+%2B='</ul>';

++++++++return+galleryHTML;
++++};|code-block|syntax|javascript|554811|这里有一些与打印图片库相关的东西。|554812|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

What I had to do is (in Javascript) is go through all pages by using a recursive function. It's dangerouse as instagram users could have thousands of pictures i a part from that (so your have to controle it) I use this code: (count parameter I think , doesn't do much)

<pre><code> instagramLoadDashboard = function(hash)
 {
 code = hash.split('=')[1];

 $('#instagram-pictures .images-list .container').html('').addClass('loading');


 ts = Math.round((new Date()).getTime() / 1000);
 url = 'https://api.instagram.com/v1/users/self/media/recent?count=200&amp;min_timestamp=0&amp;max_timestamp='+ts+'&amp;access_token='+code;

 instagramLoadMediaPage(url, function(){

 galleryHTML = instagramLoadGallery(instagramData);
 //console.log(galleryHTML);
 $('#instagram-pictures .images-list .container').html(galleryHTML).removeClass('loading');
 initImages('#instagram-pictures');

 IGStatus = 'loaded';

 });

 };

 instagramLoadMediaPage = function (url, callback)
 {
 $.ajax({
 url : url,
 dataType : 'jsonp',
 cache : false,
 success: function(response){

 console.log(response);

 if(response.code == '400')
 {
 alert(response.error_message);
 return false;
 }

 if(response.pagination.next_url !== undefined) {
 instagramData = instagramData.concat(response.data);
 return instagramLoadMediaPage(response.pagination.next_url,callback);
 }

 instagramData = instagramData.concat(response.data);
 callback.apply();
 }
 });
 };

 instagramLoadGallery = function(images)
 {
 galleryHTML ='&lt;ul&gt;';

 for(var i=0;i&lt;images.length;i++)
 {
 galleryHTML += '&lt;li&gt;&lt;img src="'+images[i].images.thumbnail.url+'" width="120" id="instagram-'+images[i].id+' data-type="instagram" data-source="'+images[i].images.standard_resolution.url+'" class="image"/&gt;&lt;/li&gt;';

 }

 galleryHTML +='&lt;/ul&gt;';

 return galleryHTML;
 };
</code></pre>

There some stuff related to print out a gallery of picture.

blocks|key|338812|text|使用最好的递归函数来获取用户的所有帖子。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|338813|<?php
++++set_time_limit(0);
++++function+getPost($url,$i)+
++++{
++++++++static+$posts=array();++
++++++++$json=file_get_contents($url);
++++++++$data+=+json_decode($json);
++++++++$ins_links=array();
++++++++$page=$data->pagination;
++++++++$pagearray=json_decode(json_encode($page),true);
++++++++$pagecount=count($pagearray);

++++++++foreach(+$data->data+as+$user_data+)
++++++++{
++++++++++++$posts[$i%2B%2B]=$user_data->link;
++++++++}

++++++++if($pagecount>0)
++++++++++++return+getPost($page->next_url,$i);
++++++++else
++++++++++++return+$posts;
++++}
++++$posts=getPost("https://api.instagram.com/v1/users/CLIENT-ACCOUNT-NUMBER/media/recent?client_id=CLIENT-ID&count=33",0);

++++print_r($posts);

?>|code-block|syntax|javascript|338814|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Use the best recursion function for getting all posts of users.

<pre><code>&lt;?php
 set_time_limit(0);
 function getPost($url,$i) 
 {
 static $posts=array(); 
 $json=file_get_contents($url);
 $data = json_decode($json);
 $ins_links=array();
 $page=$data-&gt;pagination;
 $pagearray=json_decode(json_encode($page),true);
 $pagecount=count($pagearray);

 foreach( $data-&gt;data as $user_data )
 {
 $posts[$i++]=$user_data-&gt;link;
 }

 if($pagecount&gt;0)
 return getPost($page-&gt;next_url,$i);
 else
 return $posts;
 }
 $posts=getPost("https://api.instagram.com/v1/users/CLIENT-ACCOUNT-NUMBER/media/recent?client_id=CLIENT-ID&amp;count=33",0);

 print_r($posts);

?&gt;
</code></pre>

blocks|key|554918|text|使用next_url对象获取接下来的20张图像。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|554919|在JSON响应中有一个pagination数组：|554920|+"pagination":{
++++++"next_max_tag_id":"1411892342253728",
++++++"deprecation_warning":"next_max_id+and+min_id+are+deprecated+for+this+endpoint;+use+min_tag_id+and+max_tag_id+instead",
++++++"next_max_id":"1411892342253728",
++++++"next_min_id":"1414849145899763",
++++++"min_tag_id":"1414849145899763",
++++++"next_url":"https:\/\/api.instagram.com\/v1\/tags\/lemonbarclub\/media\/recent?client_id=xxxxxxxxxxxxxxxxxx\u0026max_tag_id=1411892342253728"
+}|code-block|syntax|javascript|554921|这是关于特定API调用的信息，对象next_url显示了获取下20张图片的URL，所以只需获取该URL并为下20张图片调用它。|554922|有关Instagram+API的更多信息，请查看此博客文章：Getting+Friendly+With+Instagram’s+API|554923|entityMap|0|LINK|mutability|MUTABLE|url|https://medium.com/@KevinMcAlear/getting-friendly-with-instagrams-api-abe3b929bc52^0|2|8|0|B|A|0|0|H|8|0|U|11|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|11|8|@$9|12|A|13|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|14|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|15|8|@$9|16|A|17|B|C]]|D|@]|E|$]]|$1|O|3|P|5|6|7|18|8|@]|D|@$9|19|A|1A|1|1B]]|E|$]]|$1|Q|3|-4|5|6|7|1C|8|@]|D|@]|E|$]]]|R|$S|$5|T|U|V|E|$W|X]]]]

Use the <code>next_url</code> object to get the next 20 images.

In the JSON response there is an <code>pagination</code> array:

<pre><code> "pagination":{
 "next_max_tag_id":"1411892342253728",
 "deprecation_warning":"next_max_id and min_id are deprecated for this endpoint; use min_tag_id and max_tag_id instead",
 "next_max_id":"1411892342253728",
 "next_min_id":"1414849145899763",
 "min_tag_id":"1414849145899763",
 "next_url":"https:\/\/api.instagram.com\/v1\/tags\/lemonbarclub\/media\/recent?client_id=xxxxxxxxxxxxxxxxxx\u0026max_tag_id=1411892342253728"
 }
</code></pre>

This is the information on specific API call and the object <code>next_url</code> shows the URL to get the next 20 pictures so just take that URL and call it for the next 20 pictures.

For more information about the Instagram API check out this blogpost: <a href="https://medium.com/@KevinMcAlear/getting-friendly-with-instagrams-api-abe3b929bc52" rel="nofollow noreferrer">Getting Friendly With Instagram’s API</a>

blocks|key|338940|text|你可以使用Instagram+PHP+API的分页：https://github.com/cosenary/Instagram-PHP-API/wiki/Using-Pagination|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|338941|大概是这样的：|338942|++++$Instagram+=+new+MetzWeb\Instagram\Instagram(array(
++++++++"apiKey"++++++=>+IG_APP_KEY,
++++++++"apiSecret"+++=>+IG_APP_SECRET,
++++++++"apiCallback"+=>+IG_APP_CALLBACK
++++));
++++$Instagram->setSignedHeader(true);

++++$pictures+=+$Instagram->getUserMedia(123);
++++do+{

++++++++foreach+($pictures->data+as+$picture_data):

++++++++++++echo+'<img+src="'.$picture_data->images->low_resolution->url.'">';

++++++++endforeach;

++++}+while+($pictures+=+$instagram->pagination($pictures));|code-block|syntax|javascript|338943|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/cosenary/Instagram-PHP-API/wiki/Using-Pagination^0|Q|1V|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|6|7|W|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|X|8|@]|9|@]|C|$I|J]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]]]

You can user pagination of Instagram PHP API: <a href="https://github.com/cosenary/Instagram-PHP-API/wiki/Using-Pagination" rel="nofollow">https://github.com/cosenary/Instagram-PHP-API/wiki/Using-Pagination</a>

Something like that:

<pre><code> $Instagram = new MetzWeb\Instagram\Instagram(array(
 "apiKey" =&gt; IG_APP_KEY,
 "apiSecret" =&gt; IG_APP_SECRET,
 "apiCallback" =&gt; IG_APP_CALLBACK
 ));
 $Instagram-&gt;setSignedHeader(true);

 $pictures = $Instagram-&gt;getUserMedia(123);
 do {

 foreach ($pictures-&gt;data as $picture_data):

 echo '&lt;img src="'.$picture_data-&gt;images-&gt;low_resolution-&gt;url.'"&gt;';

 endforeach;

 } while ($pictures = $instagram-&gt;pagination($pictures));
</code></pre>

blocks|key|555044|text|2016年6月，Instagram使其API的大部分功能仅对通过审查过程的应用程序可用。但是，它们仍然通过web接口提供JSON数据，您可以将参数__a=1添加到URL以仅包含JSON数据。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|555045|max=
while+:;do
++c=$(curl+-s+"https://www.instagram.com/username/?__a=1&max_id=$max")
++jq+-r+'.user.media.nodes[]?%7C.display_src'<<<"$c"
++max=$(jq+-r+.user.media.page_info.end_cursor<<<"$c")
++jq+-e+.user.media.page_info.has_next_page<<<"$c">/dev/null%7C%7Cbreak
done|code-block|syntax|javascript|555046|编辑:正如alnorth29在注释中提到的，max_id参数现在被忽略。Instagram还改变了回复的格式，你需要执行额外的请求，才能获得新风格帖子中图片的完整大小URL，每个帖子有多张图片。您现在可以这样做，在结果的第一页列出图像的完整大小的URL：|555047|c=$(curl+-s+"https://www.instagram.com/username/?__a=1")
jq+-r+'.graphql.user.edge_owner_to_timeline_media.edges[]?%7C.node%7Cselect(.__typename!="GraphSidecar").display_url'<<<"$c"
jq+-r+'.graphql.user.edge_owner_to_timeline_media.edges[]?%7C.node%7Cselect(.__typename=="GraphSidecar")%7C.shortcode'<<<"$c"%7Cwhile+read+l;do
++curl+-s+"https://www.instagram.com/p/$l?__a=1"%7Cjq+-r+'.graphql.shortcode_media%7C.edge_sidecar_to_children.edges[]?.node%7C.display_url'
done|555048|要列出用户在Safari最前面的选项卡中打开其配置文件的每个帖子的快捷码，我使用如下脚本：|555049|sjs(){+osascript+-e'{on+run{a}','tell+app"safari"to+do+javascript+a+in+document+1',end}+--+"$1";}

while+:;do
++sjs+'o="";a=document.querySelectorAll(".v1Nh3+a");for(i=0;e=a[i];i%2B%2B){o%2B=e.href%2B"\n"};o'>>/tmp/a
++sjs+'window.scrollBy(0,window.innerHeight)'
++sleep+1
done|555050|entityMap^0|21|5|0|0|M|6|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|12|8|@]|D|@]|E|$]]|$1|Q|3|R|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|S|3|-4|5|6|7|14|8|@]|D|@]|E|$]]]|T|$]]

In June 2016 Instagram made most of the functionality of their API available only to applications that have passed a review process. They still however provide JSON data through the web interface, and you can add the parameter <code>__a=1</code> to a URL to only include the JSON data.

<pre class="lang-none prettyprint-override"><code>max=
while :;do
 c=$(curl -s "https://www.instagram.com/username/?__a=1&amp;max_id=$max")
 jq -r '.user.media.nodes[]?|.display_src'&lt;&lt;&lt;"$c"
 max=$(jq -r .user.media.page_info.end_cursor&lt;&lt;&lt;"$c")
 jq -e .user.media.page_info.has_next_page&lt;&lt;&lt;"$c"&gt;/dev/null||break
done
</code></pre>

Edit: As mentioned in the comment by alnorth29, the <code>max_id</code> parameter is now ignored. Instagram also changed the format of the response, and you need to perform additional requests to get the full-size URLs of images in the new-style posts with multiple images per post. You can now do something like this to list the full-size URLs of images on the first page of results:

<pre class="lang-none prettyprint-override"><code>c=$(curl -s "https://www.instagram.com/username/?__a=1")
jq -r '.graphql.user.edge_owner_to_timeline_media.edges[]?|.node|select(.__typename!="GraphSidecar").display_url'&lt;&lt;&lt;"$c"
jq -r '.graphql.user.edge_owner_to_timeline_media.edges[]?|.node|select(.__typename=="GraphSidecar")|.shortcode'&lt;&lt;&lt;"$c"|while read l;do
 curl -s "https://www.instagram.com/p/$l?__a=1"|jq -r '.graphql.shortcode_media|.edge_sidecar_to_children.edges[]?.node|.display_url'
done
</code></pre>

To make a list of the shortcodes of each post made by the user whose profile is opened in the frontmost tab in Safari, I use a script like this:

<pre class="lang-none prettyprint-override"><code>sjs(){ osascript -e'{on run{a}','tell app"safari"to do javascript a in document 1',end} -- "$1";}

while :;do
 sjs 'o="";a=document.querySelectorAll(".v1Nh3 a");for(i=0;e=a[i];i++){o+=e.href+"\n"};o'&gt;&gt;/tmp/a
 sjs 'window.scrollBy(0,window.innerHeight)'
 sleep 1
done
</code></pre>

blocks|key|339033|text|Instagram开发者控制台已经为它提供了解决方案。https://www.instagram.com/developer/endpoints/|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|339034|要在PHP中使用它，下面是代码片段，|339035|/**
**
**+Add+this+code+snippet+after+your+first+curl+call
**+assume+the+response+of+the+first+call+is+stored+in+$userdata
**+$access_token+have+your+access+token
*/

$maximumNumberOfPost+=+33;+//+it+can+be+20,+depends+on+your+instagram+application
$no_of_images+=+50+//+Enter+the+number+of+images+you+want

if+($no_of_images+>+$maximumNumberOfPost)+{

++++$ImageArray+=+[];
++++$next_url+=+$userdata->pagination->next_url;
++++while+($no_of_images+>+$maximumNumberOfPost)+{
+++++++++++$originalNumbersOfImage+=+$no_of_images;
+++++++++++$no_of_images+=+$no_of_images+-+$maximumNumberOfPost;
+++++++++++$next_url+=+str_replace("count="+.+$originalNumbersOfImage,+"count="+.+$no_of_images,+$next_url);
+++++++++++$chRepeat+=+curl_init();
+++++++++++curl_setopt_array($chRepeat,+[
+++++++++++++++++++++++++++++CURLOPT_URL+=>+$next_url,
+++++++++++++++++++++++++++++CURLOPT_HTTPHEADER+=>+[
++++++++++++++++++++++++++++++++++++"Authorization:+Bearer+$access_token"
++++++++++++++++++++++++++++++],
++++++++++++++++++++++++++++++CURLOPT_RETURNTRANSFER+=>+true
++++++++++++++++++++++++++++]);
++++++++++++$userRepeatdata+=+curl_exec($chRepeat);
++++++++++++curl_close($chRepeat);
++++++++++++if+($userRepeatdata)+{
++++++++++++++++++++++$userRepeatdata+=+json_decode($userRepeatdata);
++++++++++++++++++++++$next_url+=+$userRepeatdata->pagination->next_url;
+++++++++++++++++++++if+(isset($userRepeatdata->data)+&&+$userRepeatdata->data)+{
++++++++++++++++++++++++++$ImageArray+=+$userRepeatdata->data;
+++++++++++++++++++}
+++++++++++}
++++}

}|code-block|syntax|javascript|339036|entityMap|0|LINK|mutability|MUTABLE|url|https://www.instagram.com/developer/endpoints/^0|R|1A|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|6|7|W|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|X|8|@]|9|@]|C|$I|J]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]]]

Instagram developer console has provided the solution for it. <a href="https://www.instagram.com/developer/endpoints/" rel="nofollow noreferrer">https://www.instagram.com/developer/endpoints/</a> 

To use this in PHP, here is the code snippet,

<pre><code>/**
**
** Add this code snippet after your first curl call
** assume the response of the first call is stored in $userdata
** $access_token have your access token
*/

$maximumNumberOfPost = 33; // it can be 20, depends on your instagram application
$no_of_images = 50 // Enter the number of images you want

if ($no_of_images &gt; $maximumNumberOfPost) {

 $ImageArray = [];
 $next_url = $userdata-&gt;pagination-&gt;next_url;
 while ($no_of_images &gt; $maximumNumberOfPost) {
 $originalNumbersOfImage = $no_of_images;
 $no_of_images = $no_of_images - $maximumNumberOfPost;
 $next_url = str_replace("count=" . $originalNumbersOfImage, "count=" . $no_of_images, $next_url);
 $chRepeat = curl_init();
 curl_setopt_array($chRepeat, [
 CURLOPT_URL =&gt; $next_url,
 CURLOPT_HTTPHEADER =&gt; [
 "Authorization: Bearer $access_token"
 ],
 CURLOPT_RETURNTRANSFER =&gt; true
 ]);
 $userRepeatdata = curl_exec($chRepeat);
 curl_close($chRepeat);
 if ($userRepeatdata) {
 $userRepeatdata = json_decode($userRepeatdata);
 $next_url = $userRepeatdata-&gt;pagination-&gt;next_url;
 if (isset($userRepeatdata-&gt;data) &amp;&amp; $userRepeatdata-&gt;data) {
 $ImageArray = $userRepeatdata-&gt;data;
 }
 }
 }

}
</code></pre>

In general I need to get all user media.

User has more than 250 photos.

I do <code>/users/1/media/recent/?access_token=...&amp;count=250</code>

But it returns only 20 photos.

Maybe instagram has a limit for getting media. 
If it is, response has a pagination to solve it. 
But there are only max ID photo. How to know the first (min) ID photo to paginate it then?

Instagram API: How to get all user media?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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一般来说，我需要获取所有的用户媒体。用户有超过250张照片。我做/users/1/media/recent/?access_token=...&count=250但它只返回20张照片。也许instagram在获取媒体方面是有限制的。如果是，那么response会使用分页来解决这个问题。但是只有最大的身份证照片。那么如何...

问Instagram API:如何获取所有用户媒体？
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