在一个活动中使用多个Youtube播放器
在一个活动中使用多个Youtube播放器
提问于 2013-04-30 10:00:41
我使用的是Youtube Android Player API，如下所示：https://developers.google.com/youtube/android/player/
然而，我不能同时在我的活动中包含多个视频。我尝试简单地将两个YouTubePlayerViews放入该活动中，如下所示：
activity_main.xml
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical"
android:paddingBottom="@dimen/activity_vertical_margin"
android:paddingLeft="@dimen/activity_horizontal_margin"
android:paddingRight="@dimen/activity_horizontal_margin"
android:paddingTop="@dimen/activity_vertical_margin" >
<com.google.android.youtube.player.YouTubePlayerView
android:id="@+id/view_one"
android:layout_width="wrap_content"
android:layout_height="wrap_content" />
<com.google.android.youtube.player.YouTubePlayerView
android:id="@+id/view_two"
android:layout_width="wrap_content"
android:layout_height="wrap_content" />
</LinearLayout>MainActivity.java
package com.example.multidemo;
import android.os.Bundle;
import com.google.android.youtube.player.YouTubeBaseActivity;
import com.google.android.youtube.player.YouTubeInitializationResult;
import com.google.android.youtube.player.YouTubePlayer;
import com.google.android.youtube.player.YouTubePlayer.Provider;
import com.google.android.youtube.player.YouTubePlayerView;
public class MainActivity extends YouTubeBaseActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
((YouTubePlayerView) findViewById(R.id.view_one)).initialize("API key", new YouTubePlayer.OnInitializedListener() {
@Override
public void onInitializationSuccess(Provider arg0, YouTubePlayer arg1, boolean arg2) {
arg1.cueVideo("RpwoN_XlN6Y");
}
@Override
public void onInitializationFailure(Provider arg0, YouTubeInitializationResult arg1) {
}
});
((YouTubePlayerView) findViewById(R.id.view_two)).initialize("API key", new YouTubePlayer.OnInitializedListener() {
@Override
public void onInitializationSuccess(Provider arg0, YouTubePlayer arg1, boolean arg2) {
arg1.cueVideo("jkk2mMq2x8E");
}
@Override
public void onInitializationFailure(Provider arg0, YouTubeInitializationResult arg1) {
}
});
}
}当我尝试这样做时，第一个视图显示为黑色，而第二个视频加载。如果我注释掉第二个视频的onCreate()中的代码，那么只会加载第一个视频。
有没有办法让多个YouTubePlayerViews加入到同一个活动中？
回答 1
Stack Overflow用户
发布于 2014-03-11 09:57:05
这可能太晚了，但我最近也遇到了同样的问题。希望这对那些可能面临同样问题的人有所帮助。解决这个问题的诀窍是使用YoutubePlayerFragments。只要你使用Youtube播放器视图，你就会达到在多个请求中只能完成一个初始化的限制。通常，最后一个初始化成功。
我最终动态生成了gridlayout，并将(动态生成的)片段视图放在每个单元格中。然后在onResume中初始化player的实例。一旦初始化成功，您将获得播放器的句柄，并且您可以在片段上随机提示不同的视频。
我将粘贴代码，它将使您了解我是如何构造片段和进行初始化的：
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState)
{
mLogger.i("Preparing Youtube view for fragment ..");
mFragmentHeight = CustomFragment.getFragmentHeight(mNumScreens,mNumColumns);
mFragmentWidth = CustomFragment.getFragmentWidth(mNumColumns);
LinearLayout linearLayout = new LinearLayout(getActivity());
GridLayout.LayoutParams gridparams = new GridLayout.LayoutParams();
gridparams.rowSpec = GridLayout.spec(mGridRow);
gridparams.columnSpec = GridLayout.spec(mGridColumn);
gridparams.height = mFragmentHeight;
gridparams.width = mFragmentWidth;
linearLayout.setLayoutParams(gridparams);
if(YouTubeApiServiceUtil.isYouTubeApiServiceAvailable(getActivity())==
YouTubeInitializationResult.SUCCESS)
{
View ytView = super.onCreateView(inflater, container, savedInstanceState);
linearLayout.addView(ytView);
}
else
mLogger.e("Either youtube service is down," +
" or you dont have required version of YouTube app .." +
"\nYouTube Fragment will not work as expected..");
mView = linearLayout;
mLogger.i("Preparation youtube view for fragment complete..");
return mView;
}
@Override
public void onInitializationFailure(Provider arg0,
YouTubeInitializationResult arg1)
{
mLogger.e("Youtube player initialization failed");
}
@Override
public void onInitializationSuccess(YouTubePlayer.Provider provider, YouTubePlayer player,
boolean wasRestored)
{
mLogger.i("You tube player initialized successfully.. will attempt to stream..");
mYoutubePlayer = player;
setListeners();
try
{
if (!wasRestored)
{
if(mPlayListFragment)
player.loadPlaylist(getResourceID());
else
player.loadVideo(getResourceID());
}
}
catch(Exception e)
{
mLogger.e("Error loading playlist/video .."+e);
}
}
public void onResume()
{
super.onResume();
initialize(API_KEY, this);
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/16291059
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