Android中的Java，帮助您连接到wifi网络，并在不成功时尝试重新连接
Android中的Java，帮助您连接到wifi网络，并在不成功时尝试重新连接
提问于 2012-12-20 11:52:15
我正在实现一种方法，如果连接到wifi网络不成功，它会尝试使用警告对话框重新连接，这是我到目前为止拥有的代码
public boolean autoConnect() {
String networkSSID = "xxxxx";
boolean connected = false;
WifiConfiguration conf = new WifiConfiguration();
conf.SSID = "\"" + networkSSID + "\"";
conf.allowedKeyManagement.set(WifiConfiguration.KeyMgmt.NONE);
WifiManager wifiManager = (WifiManager)getSystemService(Context.WIFI_SERVICE);
wifiManager.addNetwork(conf);
wifiManager.startScan();
List<ScanResult> list = wifiManager.getScanResults();
AlertDialog alertDialog = new AlertDialog.Builder(CarNannyv3Activity.this).create();
alertDialog.setTitle("xxxxxxxx Not Available");
alertDialog.setMessage("Please make sure xxxxxx is turned on ");
alertDialog.setButton("Reconnect", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
autoConnect();
dialog.dismiss();
} });
for( ScanResult i : list ) {
if(i.SSID.equals("\"" + networkSSID + "\"")) {
//wifiManager.enableNetwork(i.networkId, true);
wifiManager.reconnect();
return connected = true;
}else{
alertDialog.show();
}
}
return connected;
}我得到两种情况中的一种，它要么无限循环重新连接对话框，要么根本不显示，请告诉我我做错了什么。
回答 1
Stack Overflow用户
发布于 2012-12-20 15:32:46
尝试使用这个，它在我的案例中工作:：
WifiManager notif_manager = (WifiManager) context.getSystemService(Context.WIFI_SERVICE);
List<ScanResult> scan_list = notif_manager.getScanResults();
for (ScanResult scan_ap : scan_list)
{
if (scan_ap.SSID.equals("\"" + networkSSID + "\""))
{
/* Create a WifiConfig */
WifiConfiguration eliteAp = new WifiConfiguration();
/* AP Name */
eliteAp.SSID = "\"" + ssidString + "\"";
/* Priority */
eliteAp.priority = 40;
/* Enable Hidden SSID */
eliteAp.hiddenSSID = false;
.
.
.
.
.
.
eliteAp.status = WifiConfiguration.Status.ENABLED;
int res = wifi_manager.addNetwork(eliteAp);
boolean d = wifi_manager.enableNetwork(res, true);
break;
}
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/13965039
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