问如何交叉编译iOS5.1的zthread

EN

如何交叉编译iOS5.1的zthread，有没有人可以帮我？

http://www.cnblogs.com/maadiah/archive/2012/04/06/2434591.html和http://www.haogongju.net/art/1382733

我尝试了链接的方式，但是失败了，出现了这个错误。

./configure --prefix=/usr/local/iphone --build=arm-apple-darwin10 --enable-static=yes --enable-shared=no CC=/Applications/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/usr/bin/gcc CFLAGS="-arch armv7 -pipe -mdynamic-no-pic -std=c99 -Wno-trigraphs fpascal-string -O2 -Wreturn-type -Wunused variable -fmessage-length=0 -fvisibility=hidden -miphoneos-version-min=3.2 -I/Applications/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/SDK/iPhoneOS5.1.sdk/usr/include -isysroot /Applications/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS5.1.sdk“CPP=/Applications/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/usr/bin/arm-apple-darwin10-llvm-g++-4.2 AR=/Applications/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/usr/bin/ar LDFLAGS="-arch armv7 -isysroot /Applications/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS5.1.sdk -miphoneos-版本-最小=3.2“

获取错误日志:配置为: /private/var/tmp/llvmgcc42/llvmgcc42-2336.9~22/src/configure --禁用-检查--启用-werror mandir --mandir=/share/man --启用- --prefix=/Applications/Xcode.app/Contents/Developer/usr/llvm-gcc-4.2 =c，objc，c++，obj-c++ --program-prefix=llvm- program-transform name=/^cg*$/s/$/-4.2/ --with-slibdir=/usr/lib --build=i686-apple-darwin11 --enable-llvm=/private/var/tmp/llvmgcc42/llvmgcc42-2336.9~22/dst-llvmCore/Developer/usr/local --program-prefix=i686-apple-darwin11- host=x86_64-apple-darwin11 --target=i686-apple-darwin11 --with-gxx-include-dir=/usr/include/c++/4.2.1 llvm-g++-4.2:尝试执行'/usr/bin/../llvm-gcc-4.2/bin/arm-apple-darwin11-llvm-g++-4.2'：时出错execvp:没有这样的文件或目录配置:2222:错误: C++编译器无法创建可执行文件

所有日志为：