blocks|key|466204|text|下面是如何做的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|466205|soup.find_all('ul',+{'class':"score"})|code-block|syntax|javascript|466206|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here is how to do it:

<pre><code>soup.find_all('ul', {'class':"score"})
</code></pre>

blocks|key|3367346|text|您的问题似乎是期望find_all中的字符串能够找到与您的字符串完全匹配的字符串。In+fact|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3367347|3367348|当您搜索与某个CSS类匹配的标签时，您是在与其任何CSS类进行匹配：|blockquote|3367349|3367350|3367351|您可以像@alKid所说的那样正确地搜索class标签。您还可以使用class_关键字arg进行搜索。|3367352|soup.find_all('ul',+class_="score")|code-block|syntax|javascript|3367353|entityMap|0|LINK|mutability|MUTABLE|url|http://www.crummy.com/software/BeautifulSoup/bs4/doc/#searching-by-css-class^0|9|8|15|7|0|0|0|0|0|0|Y|6|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@$9|13|A|14|1|15]]|E|$]]|$1|F|3|-4|5|6|7|16|8|@]|D|@]|E|$]]|$1|G|3|H|5|I|7|17|8|@]|D|@]|E|$]]|$1|J|3|-4|5|6|7|18|8|@]|D|@]|E|$]]|$1|K|3|-4|5|6|7|19|8|@]|D|@]|E|$]]|$1|L|3|M|5|6|7|1A|8|@$9|1B|A|1C|B|C]]|D|@]|E|$]]|$1|N|3|O|5|P|7|1D|8|@]|D|@]|E|$Q|R]]|$1|S|3|-4|5|6|7|1E|8|@]|D|@]|E|$]]]|T|$U|$5|V|W|X|E|$Y|Z]]]]

Your problem seems to be that you expect <code>find_all</code> in the soup to find an exact match for your string. <a href="http://www.crummy.com/software/BeautifulSoup/bs4/doc/#searching-by-css-class" rel="noreferrer">In fact</a>:

<blockquote>
 When you search for a tag that matches a certain CSS class, you’re
 matching against any of its CSS classes:
</blockquote>

You can properly search for a class tag as @alKid said. You can also search with the <code>class_</code> keyword arg.

<pre><code>soup.find_all('ul', class_="score")
</code></pre>

blocks|key|3367380|text|如果OP对通过ul获取finalScore感兴趣，您可以用几行gazpacho来解决这个问题|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3367381|from+gazpacho+import+Soup

html+=+"""\
<div>
++++<ul+class="score+header"+id="400488971-linescoreHeader"+style="display:+block">
++++++<li>1</li>
++++++<li>2</li>
++++++<li>3</li>
++++++<li>4</li>
++++++<li+id="400488971-lshot">+</li>
++++++<li+class="finalScore">T</li>
++++</ul>
<div>
"""

soup+=+Soup(html)
soup.find("ul",+{"class":+"score"}).find("li",+{"class":+"finalScore"}).text|code-block|syntax|javascript|3367382|这将输出：|3367383|'T'|3367384|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/maxhumber/gazpacho^0|7|2|B|A|V|8|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@$9|11|A|12|1|13]]|E|$]]|$1|F|3|G|5|H|7|14|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|15|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|16|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]]]

If OP is interested in getting the <code>finalScore</code> by going through <code>ul</code> you could solve this with a couple of lines of <a href="https://github.com/maxhumber/gazpacho" rel="nofollow noreferrer">gazpacho</a>:
<pre class="lang-py prettyprint-override"><code>from gazpacho import Soup

html = &quot;&quot;&quot;\
&lt;div&gt;
 &lt;ul class=&quot;score header&quot; id=&quot;400488971-linescoreHeader&quot; style=&quot;display: block&quot;&gt;
 &lt;li&gt;1&lt;/li&gt;
 &lt;li&gt;2&lt;/li&gt;
 &lt;li&gt;3&lt;/li&gt;
 &lt;li&gt;4&lt;/li&gt;
 &lt;li id=&quot;400488971-lshot&quot;&gt; &lt;/li&gt;
 &lt;li class=&quot;finalScore&quot;&gt;T&lt;/li&gt;
 &lt;/ul&gt;
&lt;div&gt;
&quot;&quot;&quot;

soup = Soup(html)
soup.find(&quot;ul&quot;, {&quot;class&quot;: &quot;score&quot;}).find(&quot;li&quot;, {&quot;class&quot;: &quot;finalScore&quot;}).text
</code></pre>
Which would output:
<pre class="lang-py prettyprint-override"><code>'T'
</code></pre>

I want to do the following code, which is what BS documentation says to do, the only problem is that the word "class" isn't just a word. It can be found inside HTML, but it's also a python keyword which causes this code to throw an error. 

So how do I do the following?

<pre><code>soup.findAll('ul', class="score")
</code></pre>

Python BeautifulSoup findAll by "class" attribute

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我想做下面的代码，这是BS文档说要做的，唯一的问题是"class“这个词不仅仅是一个词。它可以在HTML中找到，但它也是一个python关键字，导致此代码抛出错误。那么我该怎么做呢？soup.findAll('ul', class="score")

问Python BeautifulSoup findAll by "class“属性
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