从GWT读取属性文件
从GWT读取属性文件
提问于 2013-01-13 19:11:09
我得到了这样的错误。当尝试读取属性文件时，它在开发模式下工作得很好，但当我尝试将应用程序部署到tomcat时，这个错误就来了。
SEVERE: Exception while dispatching incoming RPC call
com.google.gwt.user.client.rpc.SerializationException: Type 'java.io.FileNotFoundException' was not included in the set of types which can be serialized by this SerializationPolicy or its Class object not found in the classpath
at com.google.gwt.user.server.rpc.impl.ServerSerializationStreamWriter.serialize(ServerSerializationStreamWriter.java:619)
at com.google.gwt.user.client.rpc.impl.AbstractSerializationStreamWriter.writeObject(AbstractSerializationStreamWriter.java:126)
at com.google.gwt.user.server.rpc.impl.ServerSerializationStreamWriter$ValueWriter$8.write(ServerSerializationStreamWriter.java:153)
at com.google.gwt.user.server.rpc.impl.ServerSerializationStreamWriter.serializeValue(ServerSerializationStreamWriter.java:539)
at com.google.gwt.user.server.rpc.RPC.encodeResponse(RPC.java:616)
at com.google.gwt.user.server.rpc.RPC.encodeResponseForFailure(RPC.java:390)
at com.google.gwt.user.server.rpc.RPC.invokeAndEncodeResponse(RPC.java:588)
at com.google.gwt.user.server.rpc.RemoteServiceServlet.processCall(RemoteServiceServlet.java:208)
at com.google.gwt.user.server.rpc.RemoteServiceServlet.processPost(RemoteServiceServlet.java:248)
at com.google.gwt.user.server.rpc.AbstractRemoteServiceServlet.doPost(AbstractRemoteServiceServlet.java:62)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:647)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:305)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:222)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:123)
at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:472)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:171)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:99)
at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:936)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:118)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:407)
at org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:1004)
at org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:589)
at org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:312)
at java.util.concurrent.ThreadPoolExecutor.runWorker(Unknown Source)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(Unknown Source)
at java.lang.Thread.run(Unknown Source)回答 2
Stack Overflow用户
发布于 2013-01-13 19:29:15
无论何时进行Rpc调用，所涉及的类都必须实现java.io.Serializable。在您的情况下，这可能已经发生了。
在您的service class方法中，您在某个地方提到了一个参数或返回类型为java.io.FileNotFoundException，它不实现java.io.Serializable。因此它不能被序列化。
Stack Overflow用户
发布于 2013-01-14 03:25:25
每个可能到达客户端的异常都必须在RemoteService接口的throws子句中声明。
如果它在DevMode中工作，可能是因为您没有这样的异常。您必须找到FileNotFoundException的原因。
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原文链接：
https://stackoverflow.com/questions/14302866
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