blocks|key|3459204|text|你需要在“上下文切换”的上下文中搜索“原子操作”的概念，以及互斥锁的概念。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3459205|基本上，互斥是一个由线程设置或清除的布尔值。|3459206|每个线程将：|3459207|function+pop(){+Get_Mutex()；do_the_pop_operation()；Free_Mutex()；}|3459208|或|3459209|函数push()+{+Get_Mutex()；do_the_push_operation()；Free_Mutex()；}|3459210|Get_Mutex()函数将处于休眠状态，直到它接收到互斥锁为止，因此一次只能发生一个操作。|3459211|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Q|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|R|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|S|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|T|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|U|8|@]|9|@]|A|$]]|$1|L|3|M|5|6|7|V|8|@]|9|@]|A|$]]|$1|N|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|O|$]]

You need to google the concepts of an "atomic operation" in the context of "context switching", and also the idea of a mutex.

Basicly, a mutex is a boolean that gets set or cleared by your threads.

Each thread will:

function pop(){
 Get_Mutex();
 do_the_pop_operation();
 Free_Mutex();
}

or

function push() {
 Get_Mutex();
 do_the_push_operation();
 Free_Mutex();
}

The Get_Mutex() function will sleep until it receives the mutex, thus only one operation can occur at a time.

blocks|key|3459217|text|不，Flash是独一无二的单线程，所以不可能同时进行两个操作。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3459218|基本上，在处理事件时，您不必担心其他代码尚未完成执行。|3459219|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

No, Flash is exclusively single threaded so there's no way two operations can happen at the same time.

Basically you won't have to worry about other code having not finished executing when handling an event.

blocks|key|189735|text|你应该阅读这篇关于Order+of+operations的帖子(见事件和帧执行)。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|189736|虽然flash可能会给人以多线程和异步操作的印象，但它只是一个单线程程序，所以你永远不需要担心锁定。基本上，事件操作是在“帧之间”运行的，所以“在”帧上运行的代码是在事件运行之前/之后完成的，所以不会担心功能重叠。|189737|entityMap|0|LINK|mutability|MUTABLE|url|http://www.senocular.com/flash/tutorials/orderofoperations/^0|9|J|0|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@$A|O|B|P|1|Q]]|C|$]]|$1|D|3|E|5|6|7|R|8|@]|9|@]|C|$]]|$1|F|3|-4|5|6|7|S|8|@]|9|@]|C|$]]]|G|$H|$5|I|J|K|C|$L|M]]]]

you should read the post by senocular on this one (see Events and Frame Execution specifically) <a href="http://www.senocular.com/flash/tutorials/orderofoperations/" rel="nofollow noreferrer">Order of operations</a>.

although flash might give the impression multithreading with some asynchronious operations, it is only a single threaded program so you never need to worry about locking. basically the event operation is run "between" frames, so the code running "on" the frame is completed before/after the events are run, so there is no worry of overlapping functions.

In a custom queue, there's a push() and a pop() function. The pop() may be called any time on an Event.COMPLETE, so does this mean that code can be running in push() and pop() simultaneously? If so, is there a way to prevent the code from being run in both functions at the same time?

Can two functions in a class be accessed simultaneously in AS3?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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在自定义队列中，有一个push()和一个pop()函数。pop()可以在Event.COMPLETE上的任何时候被调用，所以这是否意味着代码可以同时在push()和pop()中运行？如果是这样，有没有办法防止代码同时在两个函数中运行？

问在AS3中可以同时访问一个类中的两个函数吗？
EN

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问在AS3中可以同时访问一个类中的两个函数吗？EN