调用OnClick事件时更新ListView中行的布局
调用OnClick事件时更新ListView中行的布局
提问于 2014-04-11 19:33:08
我有一个ListView，其中有一个TextView和一个自定义视图，我在其中绘制一个矩形。我想要一个功能，当一行ListView被点击时，矩形应该变得更大，但其他行的矩形应该保持其以前的形状。
因此，我首先增加布局的宽度和高度，然后尝试增加矩形的大小，但是虽然在单击侦听器时会调用onDraw()方法，但矩形的大小并没有增加。
此外，我的DrawView的onDraw()方法被无限调用，即使我只单击了一次，任何人都可以帮助我。
DrawView.java，用于制作矩形
public class DrawView extends View {
Paint paint = new Paint();
public int x=-1; // this variable will tell
public DrawView(Context context) {
this(context, null);
}
public DrawView(Context context, AttributeSet attrs) {
this(context, attrs, 0);
}
public DrawView(Context context, AttributeSet attrs, int defStyle) {
super(context, attrs, defStyle);
}
@Override
public void onDraw(Canvas canvas) {
paint.setStrokeWidth(10);
paint.setColor(Color.MAGENTA);
Log.e("Ronak","onDraw "+x);
canvas.drawRect(0, 0, 300, 200, paint );
if(x>=0) //this method is not called for first view but is called for onClickListener
{
increase(canvas);
}
}
private void increase(Canvas canvas) {
Log.e("Ronak","Increase");
canvas.drawRect(0, 0, 700, 800, paint );
}
}我的自定义ListView的getView()函数
public View getView(final int position, View convertView, final ViewGroup parent) {
ViewHolder holder = null;
if (convertView == null) {
holder = new ViewHolder();
convertView = mInflater.inflate(R.layout.news_list_item,null);
final LinearLayout layout = (LinearLayout)convertView.findViewById(R.id.mainLayout);
TextView t= (TextView)convertView.findViewById(R.id.textView1);
holder.textview = t;
holder.ll=layout;
final DrawView abc = (DrawView)convertView.findViewById(R.id.drawview);
holder.drawview=abc;
Log.e("Ronak","reached here3");
convertView.setTag(holder);
} else {
holder = (ViewHolder)convertView.getTag();
}
holder.textview.setText(mData.get(position));
convertView.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
Toast.makeText(c, "Clicked on="+position, 2).show();
ViewHolder mH = (ViewHolder) v.getTag();
LinearLayout.LayoutParams pp = new LinearLayout.LayoutParams(500,400);
mH.ll.setLayoutParams(pp);
DrawView dd=mH.drawview;
dd.x=position;
dd.invalidate();
}
});
return convertView;
}
static class ViewHolder {
public DrawView drawview;
public TextView textview;
public LinearLayout ll;
} 和我的ListView每一行的布局文件
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/mainLayout"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:orientation="vertical"
android:padding="2dp" >
<TextView
android:id="@+id/textView1"
android:layout_width="50dp"
android:layout_height="30dp"
android:text="Text"
android:textAppearance="?android:attr/textAppearanceLarge" />
<com.krish.horizontalscrollview.DrawView
android:id="@+id/drawview"
android:layout_width="150dp"
android:layout_height="100dp" >
</com.krish.horizontalscrollview.DrawView>
</LinearLayout> 我的ListView类
public class CenterLockHorizontalScrollview extends HorizontalScrollView {
Context context;
int prevIndex = 0;
public CenterLockHorizontalScrollview(Context context, AttributeSet attrs) {
super(context, attrs);
this.context = context;
this.setSmoothScrollingEnabled(true);
}
public void setAdapter(Context context, CustomListAdapter mAdapter) {
try {
fillViewWithAdapter(mAdapter);
} catch (ZeroChildException e) {
e.printStackTrace();
}
}
private void fillViewWithAdapter(CustomListAdapter mAdapter)
throws ZeroChildException {
if (getChildCount() == 0) {
throw new ZeroChildException(
"CenterLockHorizontalScrollView must have one child");
}
if (getChildCount() == 0 || mAdapter == null)
return;
ViewGroup parent = (ViewGroup) getChildAt(0);
//parent.removeAllViews();
for (int i = 0; i < mAdapter.getCount(); i++) {
parent.addView(mAdapter.getView(i, null, parent));
}
}回答 1
Stack Overflow用户
发布于 2014-04-11 19:42:11
我假设您在mData中存储了一个字符串列表。创建一个成员为mData和mIsSelected (布尔值)的类，并在适配器中传递该类的对象。在onClick()中，检查行是否已被选中，反转mIsSelected的值，并在结束调用notifyDataSetChanged()时执行所需的操作
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/23011438
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